Podcast Beta
Questions and Answers
What is the underlying reason for the requirement that an eigenfunction $\psi(x)$ and its derivative $d\psi(x)/dx$ must be finite?
To ensure that measurable quantities evaluated from the eigenfunction are also finite and well-behaved.
Why is it necessary for an eigenfunction $\psi(x)$ to be single-valued?
To ensure that measurable quantities evaluated from the eigenfunction are well-behaved and do not exhibit unreasonable behavior.
What would happen if an eigenfunction $\psi(x)$ or its derivative $d\psi(x)/dx$ were not continuous?
Measurable quantities evaluated from the eigenfunction would not be well-behaved and might not be finite.
Why are the requirements of finiteness, single-valuedness, and continuity imposed on eigenfunctions?
Signup and view all the answers
What is the consequence of having an eigenfunction $\psi(x)$ that is not finite or single-valued?
Signup and view all the answers
How does the general formula for calculating expectation values of position or momentum, etc. relate to the requirements of eigenfunctions?
Signup and view all the answers
What is the significance of energy quantization in the Schrdinger theory?
Signup and view all the answers
What is the purpose of Figure 5-8 in the context of eigenfunctions?
Signup and view all the answers
Study Notes
Eigenfunctions: Required Properties
- For an eigenfunction ψ(x) to be acceptable, it must have certain properties.
- The derivative of the eigenfunction, dψ(x)/dx, must also have these properties.
Properties of Eigenfunctions
- ψ(x) must be finite to ensure that measurable quantities are well-behaved.
- dψ(x)/dx must be finite for the same reason.
- ψ(x) must be single-valued to ensure that expectation values are well-defined.
- dψ(x)/dx must be single-valued to ensure that expectation values are well-defined.
- ψ(x) must be continuous to ensure that measurable quantities are well-behaved.
- dψ(x)/dx must be continuous to ensure that measurable quantities are well-behaved.
Importance of These Properties
- If ψ(x) or dψ(x)/dx were not finite or single-valued, the same would be true for the wave function ψ(x,t) and its derivative ∂ψ(x,t)/∂x.
- This would result in unacceptable behavior when evaluating measurable quantities, such as position x or momentum p.
- Measurable quantities must have finite and definite values.
Exceptional Cases
- In rare circumstances, ψ(x) may go to infinity at a point, but only if it does so slowly enough to keep the integral of ψ*(x)ψ(x) over a region containing that point finite.
Studying That Suits You
Use AI to generate personalized quizzes and flashcards to suit your learning preferences.
Description
Explore the properties of eigenfunctions and their significance in the time-independent Schrödinger equation, leading to energy quantization.
