Pressure Measurement Instruments

1.280 m of water

9.6 m of water

Pa-Pb = 12.556 kN/m2

<p>The liquid in pipe A is denser than water.</p> Signup and view all the answers

<p>0.85, indicating it is less dense than water.</p> Signup and view all the answers

<p>The pressure difference is influenced by the specific gravities of the liquids in both pipes.</p> Signup and view all the answers

<p>By summing the heights of water equivalents from each side of the mercury.</p> Signup and view all the answers

<p>113.856 kN/m2</p> Signup and view all the answers

<p>The pressure in a pipe can be determined by using the micro manometer equation that incorporates the heights of liquid columns and the specific gravities of the liquids involved.</p> Signup and view all the answers

<p>To calculate the pressure, you need the height of liquid in both limbs, the specific gravity of both the liquid and mercury, along with the ratio of the areas.</p> Signup and view all the answers

<p>The Bourdons tube is designed to measure high pressure by deforming elastically in response to the fluid pressure, converting this deformation into a rotational movement for the pointer.</p> Signup and view all the answers

<p>The specific weight of water is essential in pressure calculations as it provides the necessary constant used to convert height measurements of liquid columns into pressure units.</p> Signup and view all the answers

<p>Mechanical gauges are durable and provide direct readings, making them practical for various applications.</p> Signup and view all the answers

<p>The ratio of basin area to limb area affects the pressure measurement sensitivity and accuracy by influencing the liquid height differences observed.</p> Signup and view all the answers

<p>The specific gravity of the liquids influences the height difference in the manometer, which is crucial for calculating the pressure difference accurately.</p> Signup and view all the answers

<p>Pointer movement in a Bourdons tube gauge is achieved through the elastic deformation of the tube, which causes one end to move and rotates a linked pointer.</p> Signup and view all the answers

<p>The difference in mercury level is 0.988 m.</p> Signup and view all the answers

<p>The height h2 is 0.3416 m.</p> Signup and view all the answers

<p>The specific gravity of the liquid in both pipes is 1.4.</p> Signup and view all the answers

<p>The equation is derived from the manometer reading as ha - h1S1 = hb - h2S2 - h3S3.</p> Signup and view all the answers

<p>The difference in pressure Pa - Pb is 2.178 kN/m2.</p> Signup and view all the answers

<p>It is used to relate the heights of the liquid columns to the pressure differences.</p> Signup and view all the answers

<p>The heights and densities of the fluids on both sides must be balanced to determine pressure differences.</p> Signup and view all the answers

<p>The pressure in pipe A is 118 kN/m2.</p> Signup and view all the answers

<p>9.066 m of Oil</p> Signup and view all the answers

<p>11.213 m</p> Signup and view all the answers

<p>The density of seawater is approximately 10.9 kN/m³.</p> Signup and view all the answers

<p>131.325 kN/m²</p> Signup and view all the answers

<p>1.89 m</p> Signup and view all the answers

<p>1.575 m of water</p> Signup and view all the answers

<p>Specific calculation required for pressure conversion.</p> Signup and view all the answers

<p>100.54 kN/m²</p> Signup and view all the answers

<p>The equation used is $h_f = f \times \frac{L}{d} \times \frac{v^2}{2g}$ where $h_f$ is the head loss.</p> Signup and view all the answers

<p>The head loss is 15.92 m.</p> Signup and view all the answers

<p>The head loss is approximately 101.9368 m.</p> Signup and view all the answers

<p>Discharge is calculated using $Q = a v$, where $a = \frac{\pi d^2}{4}$ and $v$ is determined from the head loss.</p> Signup and view all the answers

<p>The diameter, velocity $v = 1.9889 , m/s$, and the formula yields a discharge of 390.05 liters/sec.</p> Signup and view all the answers

<p>The pipe with a larger diameter will have a higher discharge under the same head loss conditions.</p> Signup and view all the answers

<p>A higher friction factor results in greater head loss for the same flow conditions.</p> Signup and view all the answers

<p>Increased velocity leads to increased head loss, as it is squared in the head loss equation.</p> Signup and view all the answers