Physics Solved Paper 2018
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Questions and Answers

What is the energy equivalent of a substance with a mass of 1 g?

  • 9 x 10^{13} J (correct)
  • 18 x 10^{6} J
  • 9 x 10^{6} J
  • 18 x 10^{13} J
  • What mass of tritium will remain undecayed after 50 years if the initial mass is 64 mg and the half-life is 12.5 years?

  • 4 mg
  • 16 mg
  • 32 mg
  • 8 mg (correct)
  • In a common emitter amplifier, the input AC signal is applied across which junction?

  • Reverse biased collector-base junction
  • Forward biased collector-base junction
  • Forward biased emitter-base junction (correct)
  • Reverse biased emitter-base junction
  • If A = 1 and B = 0 in Boolean algebra, what is the value of A + B?

    <p>A</p> Signup and view all the answers

    What is the electron density in doped germanium if the hole density increases to 45 x 10^{22} m^{-3} from 3 x 10^{16} m^{-3}?

    <p>2 x 10^{10}</p> Signup and view all the answers

    Study Notes

    Energy Equivalent

    • Energy equivalent for 1 g of mass can be calculated using Einstein's equation E=mc².
    • The correct energy equivalent is (a) 18 x 10¹³ J.

    Tritium Half-Life

    • Tritium has a half-life of 12.5 years.
    • Starting with 64 mg, after 50 years, the remaining mass can be calculated through half-life formula.
    • Final undetected mass is (b) 8 mg.

    CE Amplifier Input

    • In a Common Emitter (CE) amplifier, input AC signal is applied across the (a) forward biased emitter-base junction to achieve amplification.

    Boolean Algebra

    • For the values A = 1 and B = 0, the result of A + B in Boolean algebra is (c) A.

    Doped Germanium Electron Density

    • In pure germanium at room temperature, the density of electron-hole pairs is 3 x 10¹⁶ m⁻³.
    • After doping with aluminium, hole density increases to 45 x 10²² m⁻³.
    • The resultant electron density in doped germanium is (a) 1 x 10¹⁰ m⁻³.

    DC Current Gain in Transistor

    • The DC common emitter current gain is a crucial parameter in transistor performance, defined by the relationship between emitter resistance (Re) and collector current (Ic).
    • Example given: Ic = 50. Specific values or context not provided.

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    Description

    Test your knowledge with this solved paper from the Physics exam of 2018. This quiz includes questions on energy equivalence, radioactive decay, and amplifier circuits. Perfect for students preparing for their physics assessments.

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