Physics: Projectile and Circular Motion

False (B)

parabola

<p>zero</p> Signup and view all the answers

<p>Initial horizontal velocity (A)</p> Signup and view all the answers

<p>10 m/s (A)</p> Signup and view all the answers

<p>False (B)</p> Signup and view all the answers

<p>-9.8 m/s^2</p> Signup and view all the answers

<p>Constant speed and changing velocity direction. (D)</p> Signup and view all the answers

<p>False (B)</p> Signup and view all the answers

<p>To counteract gravity and provide the necessary centripetal force. (A)</p> Signup and view all the answers

<p>$v = \frac{2\pi r}{T}$</p> Signup and view all the answers

<p>False (B)</p> Signup and view all the answers

<p>radians</p> Signup and view all the answers

<p>$v$ = Instantaneous Velocity $\omega$ = Angular Velocity $r$ = Radius of Circle $a_c$ = Centripetal Acceleration</p> Signup and view all the answers

<p>normal force</p> Signup and view all the answers

<p>acceleration</p> Signup and view all the answers

<p>The acceleration directed towards the center of the circular path. (B)</p> Signup and view all the answers

<p>$F_{c} = \frac{mv^{2}}{r}$ = Centripetal Force $\omega = \frac{\mathrm{\Delta}\theta}{t}$ = Angular Velocity $a_{c} = \frac{v^{2}}{r}$ = Centripetal Acceleration $v = \frac{2\pi r}{T}$ = Velocity</p> Signup and view all the answers

<p>The centripetal force is the vector sum of the horizontal components of the normal force and the frictional force. (A)</p> Signup and view all the answers

<p>$KE = \frac{1}{2}TL$ (B)</p> Signup and view all the answers

<p>Allow for greater speed by counterbalancing centripetal force. (D)</p> Signup and view all the answers

<p>When the frictional forces between the tires and the track are negligible. (C)</p> Signup and view all the answers

<p>$T = \frac{mg}{\cos(\theta)}$</p> Signup and view all the answers

<p>The turning movement of a force (A)</p> Signup and view all the answers

<p>False (B)</p> Signup and view all the answers

<p>$v = \sqrt{\frac{\text{GM}}{r}}$</p> Signup and view all the answers

<p>perpendicular</p> Signup and view all the answers

<p>Low Earth Orbit (LEO) = Orbital period of 1.5 - 4 hours Geostationary Orbit (GEO) = Remains stationary in the sky Elliptical Orbit = Has two focal points</p> Signup and view all the answers

<p>The required centripetal force is provided entirely by the horizontal component of the normal force. (B)</p> Signup and view all the answers

<p>The acceleration due to gravity at a specific location. (B)</p> Signup and view all the answers

<p>The ratio of $r^2$ to $T^3$ (D)</p> Signup and view all the answers

<p>speed</p> Signup and view all the answers

<p>Half of Earth's orbital period (D)</p> Signup and view all the answers

An object thrown into the air moving freely without a power source.

The parabolic trajectory that projectiles follow when in motion.

Only the weight force due to gravity acts on a projectile after launch.

At the highest point, only horizontal motion exists for an oblique projectile.

Use diagrams and separate horizontal and vertical components for analysis.

Neglecting air resistance means horizontal velocity is constant (no acceleration).

Vertical acceleration is always due to gravity, -9.8 m/s², and peaks have zero velocity.

Time is constant for both horizontal and vertical motion, affected only by height and launch angle.

An object moving in a circle at constant speed with changing direction, thus accelerating.

Period (T) is time for one rotation; frequency (f) is rotations per second (f = 1/T).

Average speed equals circumference divided by period: v = 2πr/T.

Rate of rotation over time: ω = Δθ/t, measured in radians/second.

v = ωr links instantaneous speed to angular velocity and radius.

Acceleration towards the center of the circle: a_c = v²/r.

Force keeping an object in circular motion, not a singular force like gravity.

A way to define a point in space as (r, θ) - radius and angle in radians.

The force required to keep an object moving in a circle, balancing gravity.

In a conical pendulum, tension counters gravity and provides centripetal force.

The acceleration acting on an object moving in a circle, calculated as ac = v²/r.

The speed of an object moving in a circular path, can be calculated using v = 2πr/T.

The angle at which a ball swings in a conical pendulum determined by velocity.

Tracks inclined at an angle to help vehicles maintain speed during circular motion.

A car moving on a banked track experiences a centripetal force toward the circle's center.

Banked tracks allow higher speeds by increasing centripetal force against gravity.

The angle at which a road curves to prevent sideways friction during turns.

The twisting effect of a force, calculated as the product of distance and force.

The force between two masses, given by F = GMm/r².

Acceleration due to gravity, typically 9.8 m/s² on Earth.

The gravitational force acting as the centripetal force for an orbiting object.

The speed needed to break free from a planet's gravitational field.

Ratios of the squared periods of orbits are constant for planets around the same body.

An object in stable orbit around a larger central mass.

The speed at which an object must travel in orbit, dependent on mass and radius.

Energy of an object due to its position in a gravitational field, U = -GMm/r.