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Questions and Answers
What is the specific heat capacity of iron as mentioned?
What is the specific heat capacity of iron as mentioned?
- 14
- 12
- 10 (correct)
- 8
What is the maximum height reached by a projectile with an initial velocity of 5m/s?
What is the maximum height reached by a projectile with an initial velocity of 5m/s?
- 2.5m (correct)
- 3.5m
- 4.5m
- 1.25m
What is the total acceleration of the combined mass $m_1 + m_2$ under a force of 20N?
What is the total acceleration of the combined mass $m_1 + m_2$ under a force of 20N?
- 2.0m/$s^2$ (correct)
- 3.0m/$s^2$
- 5.0m/$s^2$
- 1.5m/$s^2$
What is the estimated length of a woman's foot as stated?
What is the estimated length of a woman's foot as stated?
What is the velocity of the mobile at time t=2 seconds based on the equation $x = 6 + (2t - 0.5t^2)$?
What is the velocity of the mobile at time t=2 seconds based on the equation $x = 6 + (2t - 0.5t^2)$?
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Study Notes
Physics Exam - G1 Medicine
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Question 1 asks for power dissipated by a stove.
- The options provided are: 1000, 10, 0.10, 30, and (missing).
- There is no context or other information to determine the correct power dissipation.
-
Question 2 involves heat transfer between iron and water.
- 1kg of iron at 600°C is immersed in 20°C water.
- The specific heat capacity of iron is 10.
- The question asks for the equilibrium temperature.
- The options provided are: 310°C, 100°C, (missing), (missing), and 280°C.
- The solution requires utilizing the principle of heat exchange and solving the relevant equation:
Q_iron = - Q_water m_iron * c_iron * (T_equilibrium - T_iron) = - m_water * c_water * (T_equilibrium - T_water)
- Where m is mass, c is specific heat capacity, and T is temperature.
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Question 3 involves motion described by a mathematical equation.
- The movement of a mobile is described by the equation: x = 6 + (2t - 0.5t^2).
- The question asks for the velocity at t=2 seconds.
- The options provided are: 14m/s, 12m/s, 0m/s, 4m/s, and 16m/s.
- To solve, we need to find the derivative of the position function (x) with respect to time (t) to get the velocity function (v)
v = dx/dt = 2 - t
- Substitute t=2 seconds into the velocity function to get the velocity at t=2 seconds.
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Question 4 involves a projectile launched vertically upwards.
- A projectile is launched vertically upward with an initial velocity of 5m/s. (Assuming that velocity is actually 12 m/s)
- The question asks for the maximum height reached by the projectile.
- The options provided are: 5m/s, 12m/s, 0m/s, 10m/s, and 8.5m/s.
- At the maximum height, the projectile's velocity is 0 m/s.
- We can find the maximum height using the following equation for projectile motion: v^2 = u^2 + 2as, where v is final velocity, u is initial velocity, a is acceleration due to gravity, and s is displacement.
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Question 5 involves a stone thrown vertically upward.
- A stone is thrown vertically upward from the ground with a velocity of 10m/s.
- The question asks for the time it takes to reach its maximum height and the height reached.
- The answer seems to be presented in an image which is not provided.
- The solution requires applying the equations for projectile motion and considering both the vertical component of velocity and displacement.
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Question 6 involves estimating the length of a woman's foot.
- The options provided are: 7.5cm, 23 cm, 23m, 2.3m, and 2.5m.
- The most reasonable estimate for the length of a woman's foot among these options is 23 cm.
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Question 7 involves forces and combined masses.
- A force of 20N accelerates mass m1 by 3m/s^2 and mass m2 by 4m/s^2.
- The question asks for the acceleration of a combined mass (m1+m2) by the same force.
- The options provided are: 1.71m/s^2, 1.6m/s^2, 2m/s^2, 7m/s^2, and 0.23km.
- We can use Newton's Second Law of Motion (F=ma) to find the individual masses (m1 and m2). Then, we can find the combined mass (m1 + m2) and use the same force of 20N to calculate the acceleration of the combined mass.
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Question 8 involves an alternating current passing through a resistor.
- The alternating current with sinusoidal form passes through a resistor with resistance R = 13 ohms.
- The heat dissipated per minute is 3140 Joules.
- The question asks for the power of the current.
- Power dissipated in a resistor is given by P = I^2 * R, where I is the current and R is the resistance.
- We can use the relationship between power and energy (P = E/t) to find the power of the current, where E is the energy (3140 Joules) and t is the time (1 minute).
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