Physics Exam - G1 Medicine
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Questions and Answers

What is the specific heat capacity of iron as mentioned?

  • 14
  • 12
  • 10 (correct)
  • 8
  • What is the maximum height reached by a projectile with an initial velocity of 5m/s?

  • 2.5m (correct)
  • 3.5m
  • 4.5m
  • 1.25m
  • What is the total acceleration of the combined mass $m_1 + m_2$ under a force of 20N?

  • 2.0m/$s^2$ (correct)
  • 3.0m/$s^2$
  • 5.0m/$s^2$
  • 1.5m/$s^2$
  • What is the estimated length of a woman's foot as stated?

    <p>23cm</p> Signup and view all the answers

    What is the velocity of the mobile at time t=2 seconds based on the equation $x = 6 + (2t - 0.5t^2)$?

    <p>14m/s</p> Signup and view all the answers

    Study Notes

    Physics Exam - G1 Medicine

    • Question 1 asks for power dissipated by a stove.

      • The options provided are: 1000, 10, 0.10, 30, and (missing).
      • There is no context or other information to determine the correct power dissipation.
    • Question 2 involves heat transfer between iron and water.

      • 1kg of iron at 600°C is immersed in 20°C water.
      • The specific heat capacity of iron is 10.
      • The question asks for the equilibrium temperature.
      • The options provided are: 310°C, 100°C, (missing), (missing), and 280°C.
      • The solution requires utilizing the principle of heat exchange and solving the relevant equation:
      Q_iron = - Q_water
      m_iron * c_iron * (T_equilibrium - T_iron) = - m_water * c_water * (T_equilibrium - T_water)
      
      • Where m is mass, c is specific heat capacity, and T is temperature.
    • Question 3 involves motion described by a mathematical equation.

      • The movement of a mobile is described by the equation: x = 6 + (2t - 0.5t^2).
      • The question asks for the velocity at t=2 seconds.
      • The options provided are: 14m/s, 12m/s, 0m/s, 4m/s, and 16m/s.
      • To solve, we need to find the derivative of the position function (x) with respect to time (t) to get the velocity function (v)
      v = dx/dt = 2 - t
      
      • Substitute t=2 seconds into the velocity function to get the velocity at t=2 seconds.
    • Question 4 involves a projectile launched vertically upwards.

      • A projectile is launched vertically upward with an initial velocity of 5m/s. (Assuming that velocity is actually 12 m/s)
      • The question asks for the maximum height reached by the projectile.
      • The options provided are: 5m/s, 12m/s, 0m/s, 10m/s, and 8.5m/s.
      • At the maximum height, the projectile's velocity is 0 m/s.
      • We can find the maximum height using the following equation for projectile motion: v^2 = u^2 + 2as, where v is final velocity, u is initial velocity, a is acceleration due to gravity, and s is displacement.
    • Question 5 involves a stone thrown vertically upward.

      • A stone is thrown vertically upward from the ground with a velocity of 10m/s.
      • The question asks for the time it takes to reach its maximum height and the height reached.
      • The answer seems to be presented in an image which is not provided.
      • The solution requires applying the equations for projectile motion and considering both the vertical component of velocity and displacement.
    • Question 6 involves estimating the length of a woman's foot.

      • The options provided are: 7.5cm, 23 cm, 23m, 2.3m, and 2.5m.
      • The most reasonable estimate for the length of a woman's foot among these options is 23 cm.
    • Question 7 involves forces and combined masses.

      • A force of 20N accelerates mass m1 by 3m/s^2 and mass m2 by 4m/s^2.
      • The question asks for the acceleration of a combined mass (m1+m2) by the same force.
      • The options provided are: 1.71m/s^2, 1.6m/s^2, 2m/s^2, 7m/s^2, and 0.23km.
      • We can use Newton's Second Law of Motion (F=ma) to find the individual masses (m1 and m2). Then, we can find the combined mass (m1 + m2) and use the same force of 20N to calculate the acceleration of the combined mass.
    • Question 8 involves an alternating current passing through a resistor.

      • The alternating current with sinusoidal form passes through a resistor with resistance R = 13 ohms.
      • The heat dissipated per minute is 3140 Joules.
      • The question asks for the power of the current.
      • Power dissipated in a resistor is given by P = I^2 * R, where I is the current and R is the resistance.
      • We can use the relationship between power and energy (P = E/t) to find the power of the current, where E is the energy (3140 Joules) and t is the time (1 minute).

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    Description

    This quiz covers essential concepts in physics, focusing on the power dissipated by appliances, heat transfer between substances, and motion analysis through mathematical equations. Participants will solve problems related to thermodynamics and dynamics, which are critical for understanding physics in medical applications.

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