Physics Exam - G1 Medicine

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Questions and Answers

What is the specific heat capacity of iron as mentioned?

  • 14
  • 12
  • 10 (correct)
  • 8

What is the maximum height reached by a projectile with an initial velocity of 5m/s?

  • 2.5m (correct)
  • 3.5m
  • 4.5m
  • 1.25m

What is the total acceleration of the combined mass $m_1 + m_2$ under a force of 20N?

  • 2.0m/$s^2$ (correct)
  • 3.0m/$s^2$
  • 5.0m/$s^2$
  • 1.5m/$s^2$

What is the estimated length of a woman's foot as stated?

<p>23cm (C)</p> Signup and view all the answers

What is the velocity of the mobile at time t=2 seconds based on the equation $x = 6 + (2t - 0.5t^2)$?

<p>14m/s (D)</p> Signup and view all the answers

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Study Notes

Physics Exam - G1 Medicine

  • Question 1 asks for power dissipated by a stove.

    • The options provided are: 1000, 10, 0.10, 30, and (missing).
    • There is no context or other information to determine the correct power dissipation.
  • Question 2 involves heat transfer between iron and water.

    • 1kg of iron at 600°C is immersed in 20°C water.
    • The specific heat capacity of iron is 10.
    • The question asks for the equilibrium temperature.
    • The options provided are: 310°C, 100°C, (missing), (missing), and 280°C.
    • The solution requires utilizing the principle of heat exchange and solving the relevant equation:
    Q_iron = - Q_water
    m_iron * c_iron * (T_equilibrium - T_iron) = - m_water * c_water * (T_equilibrium - T_water)
    
    • Where m is mass, c is specific heat capacity, and T is temperature.
  • Question 3 involves motion described by a mathematical equation.

    • The movement of a mobile is described by the equation: x = 6 + (2t - 0.5t^2).
    • The question asks for the velocity at t=2 seconds.
    • The options provided are: 14m/s, 12m/s, 0m/s, 4m/s, and 16m/s.
    • To solve, we need to find the derivative of the position function (x) with respect to time (t) to get the velocity function (v)
    v = dx/dt = 2 - t
    
    • Substitute t=2 seconds into the velocity function to get the velocity at t=2 seconds.
  • Question 4 involves a projectile launched vertically upwards.

    • A projectile is launched vertically upward with an initial velocity of 5m/s. (Assuming that velocity is actually 12 m/s)
    • The question asks for the maximum height reached by the projectile.
    • The options provided are: 5m/s, 12m/s, 0m/s, 10m/s, and 8.5m/s.
    • At the maximum height, the projectile's velocity is 0 m/s.
    • We can find the maximum height using the following equation for projectile motion: v^2 = u^2 + 2as, where v is final velocity, u is initial velocity, a is acceleration due to gravity, and s is displacement.
  • Question 5 involves a stone thrown vertically upward.

    • A stone is thrown vertically upward from the ground with a velocity of 10m/s.
    • The question asks for the time it takes to reach its maximum height and the height reached.
    • The answer seems to be presented in an image which is not provided.
    • The solution requires applying the equations for projectile motion and considering both the vertical component of velocity and displacement.
  • Question 6 involves estimating the length of a woman's foot.

    • The options provided are: 7.5cm, 23 cm, 23m, 2.3m, and 2.5m.
    • The most reasonable estimate for the length of a woman's foot among these options is 23 cm.
  • Question 7 involves forces and combined masses.

    • A force of 20N accelerates mass m1 by 3m/s^2 and mass m2 by 4m/s^2.
    • The question asks for the acceleration of a combined mass (m1+m2) by the same force.
    • The options provided are: 1.71m/s^2, 1.6m/s^2, 2m/s^2, 7m/s^2, and 0.23km.
    • We can use Newton's Second Law of Motion (F=ma) to find the individual masses (m1 and m2). Then, we can find the combined mass (m1 + m2) and use the same force of 20N to calculate the acceleration of the combined mass.
  • Question 8 involves an alternating current passing through a resistor.

    • The alternating current with sinusoidal form passes through a resistor with resistance R = 13 ohms.
    • The heat dissipated per minute is 3140 Joules.
    • The question asks for the power of the current.
    • Power dissipated in a resistor is given by P = I^2 * R, where I is the current and R is the resistance.
    • We can use the relationship between power and energy (P = E/t) to find the power of the current, where E is the energy (3140 Joules) and t is the time (1 minute).

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