Physics Electronics Stage 1 Quiz

$KE = \frac{1}{2}mv^2$ (correct)

$KE = qEd$

$KE = qV$

$KE = \frac{1}{2}mv^2 + qV$

$t = \frac{m}{qE}v$ (correct)

$t = \frac{m}{qE}v^2$

$t = \frac{qE}{m}v$

$t = \frac{2qV}{m}$

$F = qV/d$

$F = \frac{1}{2}mv^2$

$F = qE$ (correct)

$F = m\cdot a$