Physics Chapter on Quantum Mechanics

Choose a study mode

Play Quiz
Study Flashcards
Spaced Repetition
Chat to Lesson

Podcast

Play an AI-generated podcast conversation about this lesson

Questions and Answers

When a p-n junction diode is forward biased, then:

  • the depletion region is reduced and barrier height is increased
  • the depletion region is widened and barrier height is reduced (correct)
  • both the depletion region and barrier height are increased
  • both the depletion region and barrier height are reduced

Energy levels A, B and C of a certain atom correspond to increasing values of energy, i.e. $E_A < E_B < E_C$. If $\lambda_1$, $\lambda_2$ and $\lambda_3$ are the wavelengths of radiations corresponding to transitions C to B, B to A and C to A respectively, which of the following relations is correct?

  • $\lambda _3 = \lambda _1 + \lambda _2$
  • $\lambda _3 = \sqrt{\lambda _1 ^2 + \lambda _2 ^2}$
  • $\lambda _3 = \sqrt{\lambda _1 \lambda _2}$ (correct)
  • $\lambda _3 = rac{\lambda _1 \lambda _2}{(\lambda _1 + \lambda _2)}$

The energy that should be added to an electron to reduce its de-Broglie wavelength from 1 nm to 0.5 nm is

  • twice the initial energy (correct)
  • thrice the initial energy
  • four times the initial energy
  • equal to the initial energy

Assertion: Gamma rays are more energetic than X-rays. Reason: Gamma rays are of nuclear origin but X-rays are produced due to sudden deceleration of high energy electrons while falling on a metal of high atomic number.

<p>both Assertion and Reason are true but Reason is not correct explanation of the Assertion (C)</p> Signup and view all the answers

The binding energy per nucleon for deuterons ($^2_1H$) and helium ($^4_2He$) are 1.1 MeV and 7.0 MeV respectively. The energy released when two deuterons fuse to form a helium nucleus ($^4_2He$) is:

<p>18.6 MeV (B)</p> Signup and view all the answers

A Zener diode is connected to a battery and a load as shown below: The currents $I$, $I_z$ and $I_L$ are respectively

<p>12.5 mA, 7.5 mA, 5 mA (A)</p> Signup and view all the answers

In a H-atom spectrum $\lambda_{3-1}$ and $\lambda_{2-1}$ represents wavelengths emitted due to transition from second and first excited states to the ground state respectively. The value of $ rac{\lambda_{3-1}}{\lambda_{2-1}}$ is:

<p>27/32 (D)</p> Signup and view all the answers

Maximum kinetic energy of a photoelectric varies with the frequency (f) of the incident radiation as

<p>A (A)</p> Signup and view all the answers

When a $U^{238}$ nucleus originally at rest, decays by emitting an alpha particle having a speed ' u', the recoil speed of the residual nucleus is

<p>$ rac{4u}{234}$ (C), $ rac{4u}{234}$ (D)</p> Signup and view all the answers

When 24.8 keV X-rays strike a material, the photoelectrons emitted from K shell are observed to move in a circle of radius 23 mm in a magnetic field of 2 10 T. The binding energy of K shell electrons is

<p>7.4 keV (C)</p> Signup and view all the answers

The truth table for the following logic circuit is:

<p>B (A)</p> Signup and view all the answers

A pulse of light of duration 100 ns is absorbed completely by a small object initially at rest. Power of the pulse is 30 mW and the speed of light is $3 imes 10^8$ ms. The final momentum of the object is

<p>$3.0 imes 10^{-17} kg ms^{-1}$ (D)</p> Signup and view all the answers

The wavelength of the first spectral line of sodium is 5896 . The first excitation potential of sodium atom will be (h = $6.63 imes 10^{-34} J s$)

<p>2.1 V (D)</p> Signup and view all the answers

Choose the incorrect statement.

<p>The nuclear force becomes weak if the nucleus contains too many protons compared to the number of neutrons (C)</p> Signup and view all the answers

In the following circuits, PN-junction diodes D1, D2 and D3 are ideal for the following potential of A and B, the correct increasing order of resistance between A and B will be (i) 10 V, 5 V (ii) -5 V, -10 V (iii) 4 V, 12 V

<p>(i) = (iii) &lt; (ii) (A)</p> Signup and view all the answers

Flashcards

Forward biasing a p-n junction diode

The depletion region is the area between the p-type and n-type materials in a diode where there are very few free charge carriers. Forward biasing reduces the width of this region, making it easier for current to flow.

Relationship between wavelength and energy of radiation

The energy of a photon is inversely proportional to its wavelength. A shorter wavelength corresponds to higher energy and vice versa.

Effect of doubling the kinetic energy on de Broglie wavelength

De Broglie wavelength is inversely proportional to the momentum of a particle. Doubling the momentum would halve the wavelength. Since kinetic energy is proportional to momentum squared, doubling the kinetic energy would result in a 4-fold increase in momentum and a halving of the wavelength.

Origin of gamma rays and x-rays

Gamma rays are electromagnetic radiation emitted from the nucleus of an atom during radioactive decay. X-rays are produced when high-energy electrons are decelerated as they interact with a metal target.

Signup and view all the flashcards

Energy released during nuclear fusion

Binding energy per nucleon is the energy required to remove a nucleon from the nucleus. The higher the binding energy per nucleon, the more stable the nucleus. When two deuterons fuse to form helium, the binding energy per nucleon increases, releasing energy.

Signup and view all the flashcards

Uncertainty principle and measuring position and velocity

The uncertainty principle states that the product of the uncertainties in position and momentum of a particle is always greater than or equal to a constant value (hbar/2). Higher accuracy in measuring velocity (momentum) leads to lower accuracy in measuring position.

Signup and view all the flashcards

Zener diode's function in a circuit

A Zener diode is designed to operate in reverse breakdown, maintaining a constant voltage across it even with varying current. The Zener diode acts like a voltage regulator, keeping the output voltage constant despite changes in the input voltage.

Signup and view all the flashcards

Balmer series in hydrogen atom spectrum

In a hydrogen atom, the Balmer series corresponds to electronic transitions from higher excited states to the second energy level (n=2). The higher the initial energy level, the shorter the wavelength of the emitted radiation.

Signup and view all the flashcards

Relationship between maximum kinetic energy of photoelectron and frequency of incident radiation

The maximum kinetic energy of a photoelectron emitted from a metal surface is directly proportional to the frequency of the incident radiation. This is known as the photoelectric effect.

Signup and view all the flashcards

Recoil speed of a nucleus after alpha decay

Momentum is conserved in all interactions, including nuclear decay. The recoil speed of the residual nucleus is determined by the momentum of the emitted alpha particle and the conservation of momentum principle.

Signup and view all the flashcards

Determining binding energy of K-shell electrons from photoelectric effect

The photoelectric effect is the emission of electrons from a metal surface when light of sufficient frequency is incident on it. The binding energy of the electrons in the K-shell is the energy required to remove them from the atom. The kinetic energy of a photoelectron can be calculated by subtracting the binding energy from the energy of the incident photon.

Signup and view all the flashcards

Identification of a NAND gate in a logic circuit

A logic gate is an electronic circuit that performs a basic logical operation on input signals. A NAND gate (Not AND) produces an output of 1 only when both inputs are 0. It is the opposite of an AND gate.

Signup and view all the flashcards

Average energy density of electromagnetic wave

The energy density of an electromagnetic wave is proportional to the square of the electric field strength. The average total energy density is the sum of electric and magnetic energy densities.

Signup and view all the flashcards

Calculating maximum kinetic energy of photoelectrons ejected using Balmer series

The Balmer series is a set of spectral lines in the visible region of the hydrogen spectrum. Calculate the energy difference between the initial and final states using the given information. Then, use the fact that energy is inversely proportional to wavelength to find the wavelength corresponding to the maximum kinetic energy.

Signup and view all the flashcards

Determining atomic number of a hydrogen-like atom

Calculate the maximum energy photon that can be emitted considering transitions to the ground state (n=1). Then, use the given energy of the photon emitted during the transition to quantum state 'n' to calculate the energy difference between the initial state (2n) and the final state (n). Use the formula for energy levels in hydrogen-like atoms to determine the atomic number (Z).

Signup and view all the flashcards

Relationship between nuclear radius and atomic mass number

The nuclear radius of an atom is proportional to the cube root of its mass number (A). Compare the nuclear radii of the two atoms using the ratio of their mass numbers.

Signup and view all the flashcards

Current flowing through Zener diode

A Zener diode operates in reverse breakdown, allowing current to flow when the reverse voltage reaches a specific point. In this circuit, the Zener diode effectively limits the voltage across the 10 kΩ resistor to 7.5 V. Calculate the current flowing through the Zener diode using Ohm's law and Kirchhoff's laws.

Signup and view all the flashcards

Power of a nuclear reactor

The power of a reactor is calculated as the energy released per fusion reaction multiplied by the number of reactions occurring per second. Calculate the number of reactions per second using the given mass consumption and energy released per reaction.

Signup and view all the flashcards

Lanthanoid contraction

Lanthanoid contraction refers to the gradual decrease in atomic and ionic radii across the lanthanoid series. This is due to the poor shielding effect of 4f electrons.

Signup and view all the flashcards

Identifying a salt based on its reactions

The salt is barium sulfide (BaS). Barium sulfide gives a green flame in a flame test, reacts with dilute hydrochloric acid to produce hydrogen sulfide (a pungent gas) and forms a yellow precipitate with potassium chromate.

Signup and view all the flashcards

Trend in boiling points of group 16 hydrides

The boiling points of hydrides are affected by both hydrogen bonding and London dispersion forces. Hydrogen bonding is strongest in NH3, causing it to have the highest boiling point. As we move down the group, the size of the central atom increases, leading to stronger London dispersion forces.

Signup and view all the flashcards

Properties of borax

Borax is a useful primary standard for titrating against acids. Borax is a salt containing both BO3 and BO4 units. Borax solutions can be used as buffers in some specific pH ranges.

Signup and view all the flashcards

Allotropic forms of elements

Sulfur exists in different allotropic forms, including Sg (the most common form) and other forms with different chain lengths. Oxygen can also exist in different allotropic forms, including common O2 and the reactive O3. Allotropic forms are different structural arrangements of the same element.

Signup and view all the flashcards

Identifying a metal ion based on its reactions

The metal ion is mercury(I), Hg2?. It forms a red precipitate with KI, which dissolves in excess KI to form a colorless solution. It also forms a deep blue precipitate with cobalt(II) thiocyanate. The reactions are characteristic of mercury(I) ions.

Signup and view all the flashcards

Matching chemical processes and reactions with their outcomes

The Solvay process is used to manufacture sodium carbonate (Na2CO3). The green color in the [Cr(H2O)6]3+ ion is due to d-d transitions. SO32- + K2CrO7/H+ gives green color.

Signup and view all the flashcards

Correct statements about transition metals

Aluminium forms an octahedral complex with fluoride ions, [AlF6]3-. Beryllium and Aluminium have diagonal relationships due to similar ionic radii and similar chemical properties. Beryllium forms a tetrahedral complex with oxalate ions, [Be(C2O4)2]2-.

Signup and view all the flashcards

Reason for difficult separation of lanthanides

Lanthanide contraction is the gradual decrease in atomic and ionic radii across the lanthanide series. This contraction makes the separation of lanthanides difficult due to their similar chemical properties and size.

Signup and view all the flashcards

Correct statement about NOx compounds

NO2- is a polyatomic ion with a negative charge. When reacting with NaOH, it forms a mixture of two salts: NaNO2 and NaNO3. N2O, commonly known as laughing gas, has a linear shape, not angular.

Signup and view all the flashcards

Trend in Lewis acidity of boron trihalides

Lewis acidity is a compound's ability to accept an electron pair. The Lewis acidity of boron trihalides increases as the size of the halogen atom increases. This is because the larger halogen atom can donate electron density more effectively.

Signup and view all the flashcards

Identifying a metal ion using borax bead test

The emerald green color in a borax bead test indicates the presence of cobalt(II) ions (Co2+). The blue color in the reducing flame confirms this. In a flame test, the compound's specific flame color helps identify the metal ion.

Signup and view all the flashcards

Color change of chromate and dichromate

CrO42- is yellow in solution and exists under basic conditions. It changes to Cr2O72-, which is orange, under acidic conditions. The shift in pH influences the equilibrium between chromate and dichromate ions.

Signup and view all the flashcards

Difference in bonding of nitrogen and phosphorus

Nitrogen forms a triple bond in N2, which is stronger than the single P-P bond in P4. This difference in bonding strength explains the difference in stability and reactivity. Phosphorus prefers to form single bonds due to its larger size and lower electronegativity.

Signup and view all the flashcards

Classification of lanthanum in the periodic table

Lanthanum (La) is a lanthanoid element, which is a d-block element. All Lanthanoids belong to group 3 of the periodic table.

Signup and view all the flashcards

Least basic halogen acid

Halogens are highly electronegative and readily form negative ions. The acidity of halogen acids increases down the group. The least basic halogen acid would be the most acidic, which is HI.

Signup and view all the flashcards

Correct statements about transition metals

Transition metals form interstitial compounds, which are formed by trapping small, non-metal atoms in the spaces between their crystal lattice. 5d-elements have higher energies than 3d or 4d-elements because of the stronger screening effect of the inner electrons. Zr and Hf have similar atomic and ionic radii due to lanthanoid contraction.

Signup and view all the flashcards

Identifying a metal chloride based on its solubility

The metal chloride A is likely to be lead chloride (PbCl2), which is insoluble in cold water but dissolves in hot water. Lead chloride forms a white precipitate with potassium sulfate (K2SO4). Lead salts generally form yellow precipitates with potassium iodide (KI) due to the formation of lead iodide (PbI2).

Signup and view all the flashcards

Identifying compounds based on reaction products

The gas Y turning acidified potassium chromate (K2CrO7) paper green indicates that it is sulfur dioxide (SO2), which is formed by reacting sulfite ions (SO32-) with acid. The gas Z turning lead acetate paper black indicates hydrogen sulfide (H2S), which is formed by reacting sulfide ions (S2-) with acid. The compounds A and B are therefore sodium sulfite (Na2SO3) and sodium sulfide (Na2S), respectively.

Signup and view all the flashcards

Trend in electropositive character

Electropositivity (or metallic character) increases down the group and decreases across the period. So, the decreasing order of electropositive character is: Rb > Ca > Sc > Fe > Te > Br > F.

Signup and view all the flashcards

Counting compounds that are not Lewis acids

Count the compounds that cannot accept an electron pair. There are 3 such compounds. Here is the compound with Lewis acid : SnCl4, H3BO3, AlCl3, CF4, SiF4, CCl4, BF3, and SnCl2.

Signup and view all the flashcards

Oxidation number of Mn in MnO4-

In alkaline oxidative fusion, MnO2 is oxidized to MnO4-. The oxidation number of Mn in MnO4- is +7. Remember, alkaline oxidative fusion is a process often used for analyzing metal oxides during chemical analysis.

Signup and view all the flashcards

Correct trends in group 16 hydrides

From the given trends, only the bond angle trend is correct. The other trends are incorrect. For instance, water (H2O) is more volatile than H2S, and the acidic strength of hydrides increases down the group.

Signup and view all the flashcards

Elements that impart color to a Bunsen flame

The elements that impart color to a Bunsen flame are Ba (green), Ca (orange-red), Na (bright yellow), Sr (bright red), and K (violet). Flame tests are a way to identify metal ions based on the characteristic color of their emitted light.

Signup and view all the flashcards

Counting bonds and hybridization in borax

In the compound Na2[B4O5(OH)4]•8H2O (borax), there are 4 B-O-B bonds, 0 B-B bonds, and 4 sp3 hybridized B atoms (the four B atoms in the B4O5 unit are sp3 hybridized). Hence, x + y + z = 4 + 0 + 4 = 8.

Signup and view all the flashcards

Study Notes

Question 1

  • Forward biasing a p-n junction reduces the depletion region and increases the barrier height.

Question 2

  • Energy levels (A, B, C) increase in order: EA < EB < Ec.
  • λ3 = (λ1 * λ2) / (λ1 + λ2)

Question 3

  • Energy to reduce de Broglie wavelength from 1 nm to 0.5 nm is twice the initial energy.

Question 4

  • Assertion: Gamma rays are more energetic than X-rays.
  • Reason: Gamma rays originate from nuclear processes, while X-rays result from high-energy electrons decelerating.
  • Both assertion and reason are true, and the reason correctly explains the assertion.

Question 5

  • Binding energy per nucleon for deuterons (H²) = 1.1 MeV
  • Binding energy per nucleon for helium (He⁴) = 7.0 MeV
  • Energy released when two deuterons fuse to form a helium nucleus = 23.6 MeV

Question 6

  • Uncertainty in velocity of an electron (v) = 0.005%
  • Velocity (v)= 50 ms⁻¹
  • Accuracy in measuring position (Δx) = 4.634 × 10⁻⁵m

Question 7

  • Zener diode connected to a battery and load.
  • Currents I, Iz, and I, respectively = 12.5 mA, 7.5 mA, 5 mA

Question 8

  • In a hydrogen atom spectrum, transitions from second and first excited states to the ground state are represented by values of 3-1 and 2-1.
  • Wavelength (3-1) = 32/27 (value provided)

Question 9

  • Maximum kinetic energy of photoelectric varies with frequency (f), represented by a graph. Graph shows linear increasing relationship.

Question 10

  • U²³⁸ nucleus at rest, decays by emitting an alpha particle with speed 'u'
  • Recoil speed of the residual nucleus = 4u/238

Question 11

  • 24.8 keV X-rays strike a material.
  • Photoelectrons from K shell move in a circle (radius 23 mm) in a magnetic field (2 × 10⁻² T).
  • Binding energy of K shell electrons = 6.2 keV

Question 12

  • Truth table for a given logic circuit (involving inputs A and B, leading to output Y).

Question 13

  • A pulse of light (duration 100 ns).
  • Power of the pulse = 30 mW
  • Speed of light = 3 × 10⁸ ms⁻¹
  • Final momentum of the object = 9 × 10⁻¹⁷ kg ms⁻¹

Question 14

  • Wavelength of the first spectral line of sodium = 5896 Å
  • h = 6.63 × 10⁻³⁴ Js
  • First excitation potential of sodium atom = 2.1 V

Question 15

  • Nuclear force weakens with increasing number of protons, relative to neutrons, in the nucleus.
  • Nuclei with atomic numbers greater than 82 tend to disintegrate.
  • Nuclear force becomes stronger with more nucleons in the nucleus.

Question 16

  • Increasing order of resistance between A and B with different voltages:
  • (iii) < (ii) < (i)

Question 17

  • Electric displacement current through a surface area S is proportional to the rate of change of electric flux through S.

Question 18

  • Work functions of three photosensitive materials are 1 eV, 2 eV, and 3 eV, respectively.
  • Ratio of frequencies to produce photoelectrons of maximum kinetic energy of 1 eV from each of them is 3:2:1

Question 19

  • Compounds A and B are treated with dil. HCl to get Y and Z respectively.
  • Y (gas) turns acidified K₂Cr₂O₇ paper green..
  • Z turns lead acetate paper black.
  • X and Y are Na₂SO₃ and Na₂S, respectively

Question 20

  • Correct decreasing order of electropositive character among the elements (Fe, Sc, Rb, Br, Te, F, Ca).
    • Rb > Ca > Sc > Fe > Te > Br > F

Question 1 (Numerical Physics)

  • Balmer series wavelengths (450 nm to 750 nm).
  • Work function = 2.0 eV
  • hc = 1242 eV nm

Question 2 (Numerical Physics)

  • Hydrogen-like atom (atomic number Z).
  • Excited state (quantum number 2n).
  • Maximum energy photon = 204 eV
  • Photon emitted in transition to quantum state n = 40.8 eV
  • Find atomic number Z.

Question 3 (Numerical Physics)

  • Nuclear radius ratio for an atom with mass number A and He⁴.

Question 4 (Numerical Physics)

  • Circuit current (in mA) through the Zener diode.

Question 5 (Numerical Chemistry)

  • Nuclear reaction (H² + H³ → He⁴).
  • Energy released per fusion reaction = 20 meV
  • Mass of H²¹ consumed per day = 0.1 g
  • Power of the reactor in MW.

Question 6 (Numerical Chemistry)

  • Number of compounds that do not act as Lewis acids.

Question 7 (Numerical Chemistry)

  • Oxidation number of Mn in the product of the alkaline oxidative fusion of MnO₂.

Question 8 (Numerical Chemistry)

  • Trends in the properties of group 16 hydrides (bond angle, volatility, thermal stability, acidic strength).

Question 9 (Numerical Chemistry)

  • Compounds that impart colour to a Bunsen flame.

Question 10 (Numerical Chemistry)

  • Number of B – O – B bonds in Na₂[B₄O₅(OH)₄]⋅8H₂O.
  • Number of B – B bonds.
  • Number of sp² hybridized B atoms.

Question 11 (Numerical Mathematics)

  • Shortest distance between two lines.

Question 12 (Numerical Mathematics)

  • Two lines intersect at a point.
  • Value of x² + 4.

Question 13 (Numerical Mathematics)

  • Coefficients of variation for two distributions are 60% and 75%.
  • Standard deviations are 18 and 15.
  • Arithmetic mean for the two distributions.

Question 14 (Numerical Mathematics)

  • Line passing through two points.
  • Line crosses the yz-plane.
  • Values of a and b.

Question 15 (Numerical Mathematics)

  • Line passing through a point with direction ratios.
  • Image of a point related to the line.
  • Length of median

Question 16 (Numerical Mathematics)

  • Points with position vectors (collinear).
  • Value of (19a - 6β)²

Question 17 (Numerical Mathematics)

  • Vectors a and b, and a vector related to vectors a + b and a - b.

Question 18 (Numerical Mathematics)

  • Direction cosines of two lines related by equations.
  • Angle between lines.

Question 19 (Numerical Mathematics)

  • Vectors a and b. Vector perpendicular to a +and a – b.

Question 20 (Numerical Mathematics)

  • Perpendicular distance of a point from a line.

Studying That Suits You

Use AI to generate personalized quizzes and flashcards to suit your learning preferences.

Quiz Team

Related Documents

Mathongo Physics Paper 9 PDF

More Like This

Use Quizgecko on...
Browser
Browser