Physics Chapter on Current and Resistance

<p>superposition of forces (D)</p> Signup and view all the answers

<p>15 C (B)</p> Signup and view all the answers

<p>The net force on q3​points somewhere between q1​ and q2, depending on their relative force magnitudes. (A)</p> Signup and view all the answers

<p>The total charge will double. (B)</p> Signup and view all the answers

<p>The total amount of charge passing through a conductor in a given time. (C)</p> Signup and view all the answers

<p>The electric flux remains the same because it depends only on the enclosed charge. (D)</p> Signup and view all the answers

<p>The capacitance increases to 10 µF, the charge increases to 100 µC, and the voltage remains at 10 V. (D)</p> Signup and view all the answers

<p>The presence of other charges nearby. (B)</p> Signup and view all the answers

<p>The capacitance increases to 40 µF, the charge remains the same at 60 µC, and the voltage decreases to 1.5 V. (C)</p> Signup and view all the answers

<p>Electric flux is directly proportional to the enclosed charge. (B)</p> Signup and view all the answers

<p>The electric field decreases. (A)</p> Signup and view all the answers

<p>1 A (C)</p> Signup and view all the answers

<p>Electric potential is the integral of the electric field. (D)</p> Signup and view all the answers

<p>5 A (C)</p> Signup and view all the answers

<p>less (C)</p> Signup and view all the answers

<p>Electrons are transferred from one object to another. (D)</p> Signup and view all the answers

<p>The total current entering a junction is equal to the total current leaving the junction. (D)</p> Signup and view all the answers

<p>Rearranging charges in an object without direct contact. (A)</p> Signup and view all the answers

<p>32 Ω (D)</p> Signup and view all the answers

<p>Rubbing involves contact, while induction does not require direct contact. (D)</p> Signup and view all the answers

<p>The resistance will be quartered. (D)</p> Signup and view all the answers

<p>2 A (A)</p> Signup and view all the answers

<p>4.3 x 10^7 m (B)</p> Signup and view all the answers

<p>The current is directly proportional to the voltage and inversely proportional to the resistance. (A)</p> Signup and view all the answers

<p>1.8 × 10^4 N/C (A)</p> Signup and view all the answers

<p>The conductor with 0.25 A for 5 hours transfers more charge. (D)</p> Signup and view all the answers

<p>Add the magnitudes of the forces due to q1 and q2 directly without considering their directions. (A)</p> Signup and view all the answers

<p>2400 C (C)</p> Signup and view all the answers

<p>60 J (A)</p> Signup and view all the answers

<p>The electric field strength is halved. (B)</p> Signup and view all the answers

<p>The electric field points radially outward from the charge. (B)</p> Signup and view all the answers

<p>The capacitance increases, the charge on the plates remains the same, and the electric field decreases. (B)</p> Signup and view all the answers

<p>The electric field is uniform and points from the positive plate to the negative plate. (A)</p> Signup and view all the answers

<p>Capacitors can release the stored energy quickly to generate a high-intensity flash. (D)</p> Signup and view all the answers

<p>The electric potential is always positive at all points. (A)</p> Signup and view all the answers

<p>60 µC (A)</p> Signup and view all the answers

<p>Capacitance is directly proportional to charge and inversely proportional to voltage. (D)</p> Signup and view all the answers

<p>The electric potential is inversely proportional to the distance from the charge. (A)</p> Signup and view all the answers

<p>They filter out unwanted frequencies, allowing only the desired signal to pass. (B)</p> Signup and view all the answers

<p>The electric potential is zero. (C)</p> Signup and view all the answers

<p>They allow high-frequency signals to pass through while blocking low-frequency signals. (B)</p> Signup and view all the answers

<p>To control the rate at which the circuit charges and discharges, determining the timing cycle. (D)</p> Signup and view all the answers

<p>The electric potential energy is reduced by a factor of four. (B)</p> Signup and view all the answers

<p>To store and release electrical energy to smooth out fluctuations in voltage. (C)</p> Signup and view all the answers

<p>The electric potential energy is quadrupled. (C)</p> Signup and view all the answers

The total current in a parallel circuit is greater than in a series circuit due to lower total resistance.

Charge transfer occurs when electrons move from one object to another due to friction.

The total current entering a junction equals the total current leaving the junction.

Charging by induction involves rearranging charges in an object without direct contact.

If the length of a wire is doubled and cross-sectional area is halved, resistance increases.

Rubbing (friction) involves contact, while induction does not require direct contact.

Resistance (R) is affected by length (L) and cross-sectional area (A) using R=ρL/A.

If the length of a wire is halved and its area is doubled, the resistance remains the same according to R=ρL/A.

The relationship between current, voltage, and resistance: V = IR.

The flow of electric charge, measured in amperes (A).

The opposition to the flow of current, measured in ohms (Ω).

The force between two charges, calculated using Coulomb's law.

The quantity of electric charge that passes through a conductor over time.

Describes the force between two charges: F = k * |q1*q2|/r².

The total electric field experienced at a point due to nearby charges.

Combining quantities that have both magnitude and direction.

The amount of electric charge that has moved through a circuit, calculated by Q = I × t.

The principle that states charges exert forces on each other; the total force is the vector sum of individual forces.

Doubling the current while keeping time constant doubles the total charge transferred (Q = I × t).

When the charges of objects are doubled, the force between them quadruples if distance remains constant.

If you maintain a current for a longer time, the total charge transferred increases according to Q = I × t.

The total charge transferred during different current scenarios can be found using cumulative current multiplied by time periods.

A concept stating that when multiple forces act on a charge, the net force is the vector sum of all individual forces.

Two charges attract each other; the force between them is affected by their magnitudes and inversely by the distance separating them.

Ability of a capacitor to store charge per unit voltage.

Electric field strength decreases by a factor of four when distance from charge doubles.

Electric field created by positive charge points radially outward.

Inserting a dielectric increases capacitance and decreases electric field strength.

Electric field between parallel plates is uniform and directed from positive to negative plate.

Capacitors are used in cameras for quick release of stored energy.

Electric potential due to a positive charge is always positive.

When capacitance increases, for the same charge, voltage decreases.

Electric potential decreases as distance from charge increases.

Capacitors filter out unwanted frequencies, allowing desired signals to pass.

The electric potential halfway between +Q and -Q is zero.

Capacitors allow high-frequency signals to pass while blocking low frequencies.

Capacitors control the timing cycle by managing charge and discharge rates.

Doubling the distance between charges reduces potential energy by a factor of four.

Capacitors smooth out voltage fluctuations by storing and releasing electrical energy.

Capacitors do not act as resistors but store energy and regulate current flow.

The total electric field passing through a surface.

Represents the total charge passing through a conductor over time.

Electric flux remains the same when radius increases, depending only on charge.

Inserting a dielectric increases capacitance and may change charge and voltage.

Strength depends on charge magnitude and distance, not external charges.

With a constant voltage, capacitance increase leads to charge increase.

When a dielectric is added, the voltage decreases while charge stays the same.

When disconnected, inserting a dielectric increases capacitance, decreases voltage without charge change.