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Physics Center of Mass Quiz
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Physics Center of Mass Quiz

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Questions and Answers

What is the formula to calculate the center of mass for two bodies?

  • Kcom = m1 * r1 + m2 * r2
  • Kcom = (m1 + m2) / (m1 * r1 + m2 * r2)
  • Kcom = (m1 * r1 + m2 * r2) / (m1 + m2) (correct)
  • Kcom = (m1 + m2) / (r1 + r2)
  • In a perfectly inelastic collision, what can be said about the final momentum?

  • Final momentum is the sum of individual momentum before the collision (correct)
  • Final momentum is less than initial momentum
  • Final momentum is equal to zero
  • Final momentum is equal to twice the initial momentum
  • What does the variable 'e' represent in the context of collision?

  • The distance traveled after the collision
  • The coefficient of restitution (correct)
  • The ratio of separation to the initial velocity
  • The energy absorbed in the collision
  • Which equation represents the condition for no movement of the center of mass in a two-body system?

    <p>m1 * d * r1 = -m2 * d * r2</p> Signup and view all the answers

    How is the acceleration of the center of mass represented in a pulley block system?

    <p>acm = -(m2 - m1)^2 / (m1 + m2) * g</p> Signup and view all the answers

    What is the principle of conservation of momentum for a closed system during an explosion?

    <p>Momentum before explosion equals momentum after explosion</p> Signup and view all the answers

    Which expression represents the distance of the center of mass for a continuous mass system?

    <p>xcm = ∫ x dm / ∫ dm</p> Signup and view all the answers

    What does the variable ΔKE represent in an inelastic collision?

    <p>Change in kinetic energy</p> Signup and view all the answers

    Study Notes

    Center of Mass

    • The center of mass (Com) is the average position of all the mass points in a system.
    • To find the Com, use the formula: Kcom = (m1r1 + m2r2) / (m1+m2), where m1 and m2 are the masses and r1 and r2 are the positions of the masses.
    • The Com can be found by taking moments of the masses along a line.
    • The Com can also be calculated continuously by integrating over the mass distribution.

    Position of Center of Mass

    • The position of the Com depends on your choice of origin.
    • (xcm)1 = m2R / (m1+m2) and (xcm)2 = m1R / (m1+m2), where R is the distance between the two masses.

    Special Bodies

    • The Com of a rod is at its midpoint.
    • The Com of a hay disc is at 4R/3Ï€, where R is the radius of the disc.
    • The Com of a half ring is at 2R/Ï€.
    • The Com of a hollow hemisphere is at 4R/8.
    • The Com of a hollow core is at h/3, where h is the height of the core.
    • The Com of a solid core is at h/4.
    • The Com of a potential hemisphere is at 4Ï€R/8.

    Cavity Wall Problems

    • The Com of a cavity and the remaining mass of the object are equal.

    Shift in Position of the Com

    • The change in the position of the Com can be calculated using the formula: drcm = (m1dr1 + m2*dr2) / (m1+m2), where dr1 and dr2 are the changes in position of the masses.
    • For no movement of the Com, m1dr1 = -m2dr2.

    Acceleration of the Com

    • The acceleration of the Com is given by acm = (m1a1 + m2a2) / (m1+m2).
    • In a pulley block system, the acceleration of the Com is: acm = -(m2-m1)^2 / (m1+m2)*g.

    Momentum

    • The momentum of a body is defined as P = mv, where m is the mass and v is the velocity.
    • Newton's second law states: F = dP / dt.
    • If the net external force on a system is zero, the momentum of the system is conserved.
    • This means that the velocity of the Com is constant, and the acceleration of the Com is zero.
    • The velocity of the Com can be zero, but this does not necessarily mean that the acceleration of the Com is zero.
    • For a system, the external force is equal to the rate of change of the momentum of the Com: Fext = dPcm / dt.

    Internal Forces

    • Internal forces within a system do not affect the motion of the Com.
    • However, internal forces can change the kinetic energy of the system.

    Explosion

    • An explosion is a process where internal forces cause a rapid increase in kinetic energy.
    • In an explosion, the net external force on the system is zero, so the momentum of the system is conserved.
    • The change in kinetic energy during an explosion is equal to the energy released in the explosion: Q = Kf - Ki = 1/2 * mv^2f + 1/2 * mV^2i, where Kf is the final kinetic energy and Ki is the initial kinetic energy.

    Collision

    • A collision is an event where two or more objects come into contact.
    • The coefficient of restitution (e) is a measure of how much kinetic energy is lost during a collision.
    • e = separation / muom = (V1-V2) / (U2-U1)

    Elastic Collision

    • In an elastic collision, kinetic energy is conserved: KEi = KEf.
    • The momentum of the system is also conserved: Pi = Pf.
    • The final velocities of the objects can be calculated using the following equations:
      • V1 = (m1-m2 / m1+m2) * U1 + 2m2 / m1+m2 * U2
      • V2 = 2m1 / m1+m2 * U1 + (m2-m1 / m1+m2) * U2
    • The change in kinetic energy in an elastic collision is zero: ΔKE = 0.

    Special Cases in Elastic Collisions

    • When the two masses are equal, their velocities are interchanged after the collision.

    Inelastic Collisions

    • In inelastic collisions, kinetic energy is not conserved: KEi ≠ KEf.
    • Momentum is still conserved: Pi = Pf.
    • The final velocities of the objects can be calculated using the following equation:
      • V1 = (m1-m2 / m1+m2) * U1 + b*U2 (m1+m2 / m1+m2)
    • The change in kinetic energy in an inelastic collision is given by: ΔKE =~ 1/2 * m1*m2 / (m1+m2) * (V^2i - V^2f)

    Perfectly Inelastic Collisions

    • In a perfectly inelastic collision, the two objects stick together after the collision.
    • Momentum is still conserved: Pi = Pf.
    • Kinetic energy is not conserved: KEi ≠ KEf.
    • The final velocity of the two objects is given by: Vo comunes = (m1*U1 + m2 *U2) / (m1+m2).
    • The change in kinetic energy is given by: ΔKE = 1/2 * (m1 * m2 / (m1+m2)) *(V0)^2

    Oblique Collision

    • In an oblique collision, the objects collide at an angle.
    • We use the following steps to analyze oblique collisions:
      • Resolve the velocities of the objects into components perpendicular and parallel to the line of impact.
      • Apply the conservation of momentum along both the parallel and perpendicular directions.
      • If the collision is inelastic, use the coefficient of restitution to calculate the final velocities.
      • If the collision is elastic, use the principle of kinetic energy conservation in addition to the momentum conservation equations.

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