Permutations and Combinations Basics

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Questions and Answers

The formula for permutations is nPr = ______ / (______ - ______)!, where n is the total number of items and r is the number of items being chosen. Permutations are used when the order of the selection ______ matter.

A bag contains 3 red and 7 blue balls. What is the probability of drawing a red ball and then a blue ball without replacement?

  • 3/10 * 7/10
  • 7/10 * 3/9
  • 3/10 * 7/9 (correct)
  • 7/10 * 3/10

If two dice are rolled, the probability of getting a sum greater than 9 is ______.

1/6

The probability of drawing two face cards in a row from a deck without replacement is the same as drawing one face card and then another face card with replacement.

<p>False (B)</p> Signup and view all the answers

A box has 5 defective and 15 non-defective items. What is the probability of randomly picking two non-defective items in a row without replacement?

<p>15/20 * 14/19</p> Signup and view all the answers

Match the following probability scenarios with their corresponding formulas:

<p>Probability of rolling a 2 or a 5 on a fair die = 1/6 + 1/6 Probability of rolling three 6s in a row = (1/6) * (1/6) * (1/6) Probability of getting at least one tails when flipping a coin twice = 1 - (1/2) * (1/2) Probability of rolling doubles and flipping heads = (1/6) * (1/2)</p> Signup and view all the answers

How many ways can the letters in 'SUCCESS' be arranged?

<p>7!/(3! * 2!) (B)</p> Signup and view all the answers

A box contains 3 identical red and 4 identical green balls. How many ways can they be arranged? ______

<p>7!/(3! * 4!)</p> Signup and view all the answers

The number of ways to arrange 7 identical books and 3 different books on a shelf is the same as the number of ways to arrange 10 different books on a shelf.

<p>False (B)</p> Signup and view all the answers

How many different ways can 5 people be seated in a row?

<p>5! (D)</p> Signup and view all the answers

The probability of drawing an ace from a standard deck of 52 cards is 1/13.

<p>True (A)</p> Signup and view all the answers

What is the probability of rolling a 5 on a fair 6-sided die?

<p>1/6</p> Signup and view all the answers

If two dice are rolled, the probability that the sum is 7 is __________.

<p>1/6</p> Signup and view all the answers

Match the situation with the correct number of arrangements or combinations:

<p>Choosing 4 members from a club of 12 = Combinations Arranging 6 books on a shelf = Permutations Selecting a president and vice president from 6 candidates = Permutations Forming a committee of 3 from a group of 10 = Combinations</p> Signup and view all the answers

How many ways can a 4-digit code be formed if digits can repeat?

<p>10^4 (A)</p> Signup and view all the answers

The probability of flipping at least one heads in two flips of a fair coin is 0.75.

<p>True (A)</p> Signup and view all the answers

In how many ways can the top 3 finishers be arranged in a race with 8 runners?

<p>336</p> Signup and view all the answers

Flashcards

Probability of King or Heart

Probability of drawing a King or a Heart from a deck of cards.

Rolling Die Probability

Probability of rolling a 6 followed by an even number on dice.

Drawing Face Cards

Probability of drawing two face cards in a row without replacement.

Drawing Red and Blue Balls

Probability of drawing a red ball then a blue ball without replacement.

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Sum of Dice Greater than 9

Probability of the sum of two rolled dice being greater than 9.

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Selecting Girls from Class

Probability of randomly selecting two girls from a class of 40 girls and 60 boys.

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Arranging Letters in 'SUCCESS'

Total distinct arrangements of the letters in the word 'SUCCESS'.

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Identical Balls Arrangement

Ways to arrange 5 red and 4 blue identical balls in a row.

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Permutations Formula

P(n, r) = n! / (n - r)! for arranging items

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Combinations Formula

C(n, r) = n! / [r!(n - r)!] for selecting items

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Probability of Rolling 5

Probability of rolling a 5 on a 6-sided die is 1/6.

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Probability of Flipping Heads

Probability of flipping heads on a fair coin is 1/2.

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Probability of Event Not Happening

If an event has a probability of 0.25, the probability it doesn't occur is 0.75.

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Arrangements of MATH

The letters in the word 'MATH' can be arranged in 4! = 24 ways.

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Choosing 4 from 12

The number of ways to choose 4 members from 12 is C(12, 4).

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Chair and Vice Chair Selection

Selecting a president and vice president from 6 candidates is 6P2 = 30 ways.

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Study Notes

Permutations and Combinations Formulas

  • Permutations: Arrange n distinct objects in r positions. Formula: P(n, r) = n! / (n-r)! Use when order matters.

  • Combinations: Choose r objects from a set of n distinct objects. Formula: C(n, r) = n! / (r! * (n-r)!) Use when order does not matter.

Basic Probability Concepts

  • Probability of an event: A numerical measure of the likelihood of an event occurring. Value ranges from 0 (impossible) to 1 (certain).

  • Complement of an event: The probability of an event not occurring is 1 minus the probability of it occurring.

Simple Examples

  • Arranging 6 books: 6! = 720 ways

  • Choosing 4 members from 12: C(12, 4) = 495 ways

  • Rolling a 5 on a fair die: 1/6

  • Flipping heads: 1/2

  • Probability of an event not occurring (0.25 probability): 1 - 0.25 = 0.75

  • Drawing an ace: 4/52 = 1/13

  • Arranging letters in "MATH": 4! = 24 ways

  • Probability of a certain event: 1

Situational Permutations and Combinations

  • Committee of 3 from 10: C(10, 3) = 120 ways

  • 3-digit code from 0-9 (no repeats): P(10, 3) = 720 possible codes

  • Top 3 finishers in 8-runner race: P(8, 3) = 336 ways

  • 5 people seated in a row, 2 together: (4!) * 2! = 48 ways

  • President and Vice-President from 6 candidates: P(6, 2) = 30 ways

  • 4-digit code with repeats allowed: 10 * 10 * 10 * 10 = 10,000 ways

  • 5 students arranged in a line: 5! = 120 ways

  • 2-person leadership team from 7: C(7, 2) = 21 ways

  • Answering 8 multiple-choice questions (4 choices each): 4^8 = 65,536 ways

  • Choosing 3 students from 20: C(20, 3) = 1140 ways

Probability with Dice, Coins, and Cards

  • Sum of 7 when rolling two dice: 6/36 = 1/6

  • Possible sequences of heads and tails in 4 flips: 2^4 = 16

  • Probability of rolling a prime number (2, 3, 5): 3/6= 1/2

  • Probability of drawing a red marble: 4 / (4+5+6) = 4/15

  • Probability of drawing all 5 hearts: (13/52) * (12/51) * (11/50) * (10/49) * (9/48) = very low

  • Probability of at least one heads in two flips: 1 - (1/4) = 3/4

  • Probability of at least one 3 when rolling two dice: 1- (5/6 * 5/6) =11/36

  • Probability of drawing a king or a heart: (4/52) + (13/52) - (1/52) = 16/52

  • Probability of 6 followed by even number: (1/6) * (3/6) = 1/12

  • Probability of drawing two face cards: (12/52) * (11/51)

Compound Probability and Dependent Events

  • Probability of red ball then blue ball (without replacement): (3/10) * (7/9) = 21/90

  • Probability of two spades: (13/52) * (12/51)

  • Probability of sum greater than 9 with two dice: (4/36)

  • Probability of two non-defective items: (15/20) * (14/19)

  • Probability of rolling a 2 or 5: (2/6) = 1/3

  • Probability of three 6s in a row: (1/6)^3 = 1/216

  • Probability of at least one tails (2 coin flips): 1 - (1/4) = 3/4

  • Probability of all three students being boys (20 students total, 10 boys, 10 girls): ((10/20) * (9/19) * (8/18))

  • Probability of doubles and heads (2 dice, 1 coin): (6/36) * (1/2) = 1/12

  • Probability of two girls from a class of 100 students (60 boys, 40 girls): (40/100) * (39/99)

Distinguishable and Non-Distinguishable Arrangements

  • Arrangements of "SUCCESS": 7! / 3! = 840

  • Arrangements of "BALLOON": 7! / 2! 2! = 1260

  • Arrangements of 5 red & 4 blue balls: (9! / 5! , 4!) = 126 ways

  • Arrangements of "PEPPER": 6! / 3! = 120 ways

  • 3 red & 4 green balls:(7! / 3! , 4!) = 35 ways

  • 7 identical & 3 different books arrangement on a shelf: you can treat 7 identical books as one unique and total arrangements will be (10! / 7!)

  • 10 students lined up, 4 twins: treat 4 twins as one person. Total is (7! * 4!)

  • "MISSISSIPPI" arrangements: 11! / 4! * 4! * 2! =34,650

  • Flag with 3 red, 2 blue, & 2 green stripes: 7! / 3! 2! 2! = 210 ways

  • 8 books (3 identical math & 5 different): treat the identical 3 as 1 and use the formula (9! / 3!)

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