Partial Differential Equations

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Questions and Answers

Obtain the partial differential equation by eliminating the arbitrary constants 'a' and 'b' from the given equation $(x^2)p + ay^2 + b = z$.

The partial differential equation can be obtained by differentiating the given equation partially with respect to 'x' and 'y', resulting in the equations $(x^2)p + b = 2xq$ and $ay^2 + b = 2yp$. Substituting these back into the original equation, we get $(2xq)(2yp) = 4xyz$, which is the partial differential equation.

Form the partial differential equation of all spheres whose centers lie on the z-axis.

The partial differential equation of all spheres whose centers lie on the z-axis is $x^2 + y^2 + (z - c)^2 = r^2$, where $c$ is the constant representing the center of the sphere and $r$ is the radius.

Differentiate the equation $x^2 + y^2 + (z - c)^2 = r^2$ with respect to 'x' and 'y'.

When differentiated with respect to 'x', we get $2x + 2(z - c)p = 0$, and when differentiated with respect to 'y', we get $2y + 2(z - c)q = 0$.

Express the equations $x = -(z - c)p$ and $y = -(z - c)q$ in terms of $p$ and $q.

<p>From the given equations, we can express $p$ as $p = -\frac{x},{z - c}$ and $q$ as $q = -\frac{y},{z - c}$.</p> Signup and view all the answers

What is the equation obtained by substituting the expressions for $p$ and $q$ into the original equation $(x^2)p + ay^2 + b = z?

<p>Substituting the expressions for $p$ and $q$ into the original equation, we obtain the equation $2x(-\frac{y},{z - c}) = 4xyz$.</p> Signup and view all the answers

Obtain the partial differential equation by eliminating the arbitrary constants 'a' and 'b' from the equation $(x^2)p + ay^2 + b = z$.

<p>The partial differential equation obtained by eliminating 'a' and 'b' is $(x^2)p + y^2 = 2xz$.</p> Signup and view all the answers

Form the partial differential equation of all spheres whose centers lie on the z-axis.

<p>The partial differential equation of all spheres whose centers lie on the z-axis is $x^2 + y^2 + (z - c)^2 = r^2$.</p> Signup and view all the answers

Differentiate the equation of the sphere $x^2 + y^2 + (z - c)^2 = r^2$ with respect to 'x' and 'y'.

<p>Differentiating with respect to 'x', we get $2x + 2(z - c)p = 0$, and differentiating with respect to 'y', we get $2y + 2(z - c)q = 0$.</p> Signup and view all the answers

What is the equation obtained by differentiating the sphere equation with respect to 'x'?

<p>The equation obtained by differentiating with respect to 'x' is $2x + 2(z - c)p = 0$.</p> Signup and view all the answers

What is the equation obtained by differentiating the sphere equation with respect to 'y'?

<p>The equation obtained by differentiating with respect to 'y' is $2y + 2(z - c)q = 0.</p> Signup and view all the answers

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Study Notes

Partial Differential Equation of a Sphere

  • Given equation: $(x^2)p + ay^2 + b = z$, where 'a' and 'b' are arbitrary constants
  • To obtain the partial differential equation, eliminate 'a' and 'b' from the equation
  • The equation represents a sphere with center on the z-axis

Sphere Equation

  • The equation of a sphere is: $x^2 + y^2 + (z - c)^2 = r^2$, where 'c' is the center of the sphere and 'r' is the radius
  • Differentiating the sphere equation with respect to 'x' gives: $2x + 2(z - c)(-p) = 0$, where $p = \frac{\partial z}{\partial x}$
  • Differentiating the sphere equation with respect to 'y' gives: $2y + 2(z - c)(-q) = 0$, where $q = \frac{\partial z}{\partial y}$
  • Expressing the equations in terms of 'p' and 'q' gives: $x = -(z - c)p$ and $y = -(z - c)q$
  • Substituting these expressions into the original equation gives: $(x^2)p + ay^2 + b = z$, where 'a' and 'b' are eliminated
  • The resulting partial differential equation represents all spheres whose centers lie on the z-axis

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