Organic Chemistry: Tetravalence and Hybridisation

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Questions and Answers

Which type of hybridization is present in ethyne (C₂H₂)?

  • sp²
  • sp (correct)
  • s
  • sp³

All carbon atoms in the molecule H₂C=O are sp³ hybridized.

False (B)

What is the common shape of carbon atoms that are sp³ hybridized?

tetrahedral

In organic compounds, the number of σ bonds in HC≡CCH=CHCH₃ is _____.

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Match the following organic compounds with their hybridization states:

<p>CH₃Cl = sp³ (CH₃)₂CO = sp³, sp² HCONH₂ = sp² CH₃CH=CHCN = sp³, sp², sp², sp</p> Signup and view all the answers

Flashcards

Sigma Bond (σ bond)

The shared pair of elections in a covalent bond that lie along the internuclear axis.

Pi Bond (π bond)

The shared pair of electrons in a covalent bond that lie above and below the internuclear axis.

Hybridization

The process of combining atomic orbitals from an atom to form new hybrid orbitals. This leads to different bond angles and geometries.

sp³ Hybridization

Carbon atom is bonded to four other atoms, resulting in a tetrahedral shape. Each carbon has four sp³ orbitals.

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sp² Hybridization

Carbon atom is bonded to three other atoms. The molecule has a triangular planar shape. Each carbon uses three sp² hybridized orbitals.

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Study Notes

Tetravalence of Carbon and Shapes of Organic Compounds

  • Covalent bonding ushered in the modern era of organic chemistry.
  • Understanding molecular structure helps predict properties of organic compounds.
  • Knowledge of valency and molecular structures from Unit 4 is assumed.

Hybridisation and Bond Length/Enthalpy

  • Hybridisation influences bond length and enthalpy
  • sp hybrid orbitals contain more 's' character, leading to shorter, stronger bonds compared to sp³ hybrid orbitals.
  • sp² hybrid orbitals have intermediate 's' character, and bond lengths and enthalpies are also intermediate.
  • Greater 's' character in hybrid orbitals leads to higher electronegativity.

Characteristics of π Bonds

  • Parallel orientation of p orbitals on adjacent atoms leads to proper sideways overlap.
  • π bonds create a maximum electron overlap which makes them easily reactive.
  • π bonds are located above and below the bonding atoms' plane.

Problem 12.1: σ and π Bonds

  • Determining the number of σ and π bonds in given molecules requires examining C-C and C-H bonds.
  • Provided example solutions demonstrate the calculation method for HC≡CCH=CHCH₃ and CH₂=C=CHCH₃ molecules.

Problem 12.2: Carbon Hybridisation in Different Compounds

  • Determining the type of carbon hybridisation in different compounds.
  • Examples include determining the hybridisation in CH₂Cl, (CH₃)₂CO, CH₃CN, HCONH₂, and CH₃CH=CHCN.
  • Solution examples are provided for determining sp, sp², sp³ hybridisation.

Problem 12.3: Hybridisation and Molecular Shapes

  • Determining the state of carbon hybridisation and then the shape of different molecules.
  • Determining the carbon hybridisation in H₂C=O, CHF, and HC≡N. Example solutions are given for each molecule.

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