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Questions and Answers
The Trichotomy Property states that for any integers a and b, either a < b, a = b, or a > b is true.
True
The Transitivity Property states that if a < b and b < c, then b < a.
False
The Addition Compatibility Property indicates that if a < b, then a + c < b + c holds true for any integer c.
True
The Antisymmetry Property states that for any integers a and b, if a < b, then it must be the case that b < a.
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If a = -3 and b = 2, the Transitivity Property can be used to assert relations with another integer c.
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According to the Antisymmetry Property, if a ≤ b and b ≤ a, then a must be less than or equal to b.
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If c > 0, then for a < b, it follows that a · c < b · c according to the Multiplication Compatibility Property.
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The proof of the Addition Compatibility Property shows that adding the same number to both sides of an inequality will reverse its order.
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For the integers a = -5, b = 0, and c = 4, the Transitivity Property can demonstrate that -5 < 4.
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Under the Addition Compatibility Property, for any integers a and b, a + c < b + c requires a < b.
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Study Notes
Order Properties of the System (ℤ, +)
- Order properties are important for understanding mathematical operations and concepts.
- They are essential for simplifying expressions, solving equations, and ensuring consistency in calculations.
Trichotomy Property
-
Statement: For any two integers,
a
andb
, one and only one of the following statements must be true:a
is less thanb
,a
is equal tob
, ora
is greater thanb
. -
Proof:
- Consider the difference
d = a - b
. - If
d
is greater than zero, thena
is greater thanb
. - If
d
is equal to zero, thena
is equal tob
. - If
d
is less than zero, thena
is less thanb
. - Only one of these cases can be true because the difference
d
can only have one value.
- Consider the difference
Transitivity Property
-
Statement: If
a
is less thanb
andb
is less thanc
, thena
is less thanc
. -
Proof:
- Assume
a
is less thanb
andb
is less thanc
. - This means there exist positive integers
m
andn
such thatb = a + m
andc = b + n
. - Substituting
b
in the second equation, we getc = a + m + n
. - Since
m
andn
are positive,a
must be less thanc
.
- Assume
Antisymmetry Property
-
Statement: If
a
is less thanb
, then it is not the case thatb
is less thana
. -
Proof:
- Assume
a
is less thanb
. - This means there exists a positive integer
m
such thatb = a + m
. - Assume
b
is less thana
. - This means there exists a positive integer
n
such thata = b + n
. - Substituting
b
from the first equation into the second equation, we geta = a + m + n
, which implies0 = m + n
. - This is a contradiction because
m
andn
are positive integers. - Therefore, if
a
is less thanb
, thenb
cannot be less thana
.
- Assume
Addition Compatibility Property
-
Statement: If
a
is less thanb
, thena + c
is less thanb + c
for any integerc
. -
Proof:
- Assume
a
is less thanb
, so there exists a positive integerm
such thatb = a + m
. - Adding
c
to both sides, we getb + c = a + c + m
. - Since
m
is positive,a + c
is less thanb + c
.
- Assume
Multiplication Compatibility Property
-
Statement: If
a
is less thanb
andc
is greater than zero, thena · c
is less thanb · c
.
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Description
Explore the crucial order properties of integers with this quiz. Learn about the trichotomy and transitivity properties, which are fundamental for mathematical reasoning. Test your understanding of how these properties apply to simplifying expressions and solving equations.