Nuclear Size and Density Quiz

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Questions and Answers

What is the approximate size of the gold nucleus?

  • $10^{-14}$ m (correct)
  • $10^{-18}$ m
  • $10^{-22}$ m
  • $10^{-10}$ m

Which of the following factors influences the scattering angle of an alpha particle interacting with a gold nucleus?

  • The mass of the alpha particle
  • The kinetic energy of the alpha particle
  • The charge of the gold nucleus
  • All of the above (correct)

Why is the probability of a close collision between an alpha particle and a gold nucleus low?

  • Alpha particles are repelled by the electron cloud.
  • The gold nucleus has a very large mass.
  • The nucleus occupies a very small volume. (correct)
  • The alpha particle has a very small mass.

What does the principle of energy conservation tell us about the distance of closest approach (d) between an alpha particle and a gold nucleus?

<p>The alpha particle's kinetic energy is converted into potential energy at d. (B)</p> Signup and view all the answers

What is the significance of the alpha particle's kinetic energy being 1.2 x 10^-12 J in the calculation of the distance of closest approach?

<p>It represents the initial kinetic energy of the alpha particle before it interacts with the gold nucleus. (C)</p> Signup and view all the answers

Which of the following represents the charge of the gold nucleus, as used in the provided equation for the distance of closest approach?

<p>79e (B)</p> Signup and view all the answers

What is the relationship between the distance of closest approach (d) and the kinetic energy of the alpha particle?

<p>d is inversely proportional to the kinetic energy. (A)</p> Signup and view all the answers

What is the main reason why more energetic alpha particles were able to get closer to the nucleus than expected?

<p>They have higher momentum, allowing them to overcome the electrostatic repulsion. (B)</p> Signup and view all the answers

Why is Coulomb's law used to model the scattering of alpha particles from gold nuclei?

<p>Coulomb's law describes the electrostatic force, which is the dominant force governing the interaction between charged particles like alpha particles and gold nuclei. (A)</p> Signup and view all the answers

In Rutherford's alpha-scattering experiment, what percentage of alpha particles were deflected at angles greater than 90°?

<p>0.01% (B)</p> Signup and view all the answers

If the alpha particles in Rutherford's experiment were replaced with beta particles, which of the following would be the most likely outcome?

<p>A significant decrease in the number of beta particles deflected at greater than 90° angles. (B)</p> Signup and view all the answers

The alpha-scattering experiment provided evidence for which of the following concepts related to atomic structure?

<p>The existence of a nucleus and its relative size compared to the atom. (B)</p> Signup and view all the answers

Which of these is NOT a conclusion drawn from Rutherford's alpha-scattering experiment?

<p>The electrons are arranged in energy levels within the atom. (C)</p> Signup and view all the answers

Imagine a similar experiment where alpha particles are fired at a very thin sheet of a different element, such as aluminum. Compared to the alpha particles scattering from gold foil, what would you expect to see?

<p>Fewer alpha particles scattered at large angles due to the smaller atomic number of aluminum. (C)</p> Signup and view all the answers

Which of the following statements accurately describes the relationship between the alpha-scattering experiment and Thomson's plum pudding model?

<p>Rutherford's experiment debunked Thomson's model completely. (C)</p> Signup and view all the answers

If instead of a gold foil, a thin sheet of a much heavier element like uranium was used in the alpha-scattering experiment, what would be the most likely outcome?

<p>More alpha particles would be scattered at large angles. (C)</p> Signup and view all the answers

If the alpha particles used in the experiment were replaced with protons, what would be the most significant change to the experiment?

<p>Protons would be more likely to be deflected at large angles due to their positive charge. (C)</p> Signup and view all the answers

Using the information from the experiment, how could you estimate the relative size of the nucleus compared to the atom?

<p>By analyzing the percentage of particles not deflected, you can estimate the ratio of the volume of the atom to the volume of the nucleus. (A)</p> Signup and view all the answers

If the radius of a nucleus is doubled, what happens to the density of the nucleus?

<p>The density remains the same. (A)</p> Signup and view all the answers

A hypothetical atom has a nucleus with a radius of 3.6 fm. The nucleus is composed of 20 protons and 20 neutrons. What is the approximate density of the nucleus? (1 fm = 10^-15 m, 1 u = 1.661 x 10^-27 kg)

<p>2.3 x 10^17 kg m^-3 (A)</p> Signup and view all the answers

A nucleus with a nucleon number of 64 has a radius of approximately:

<p>4.8 fm (A)</p> Signup and view all the answers

A hypothetical atom's nucleus has a radius of 2.4 fm. What is the approximate nucleon number of this nucleus? (1 fm = 10^-15 m, 1 u = 1.661 x 10^-27 kg)

<p>8 (B)</p> Signup and view all the answers

Which of the following statements about the strong nuclear force is NOT true?

<p>The strong nuclear force is much weaker than the electrostatic force between protons. (C)</p> Signup and view all the answers

Imagine that a hypothetical nucleus composed of only protons is discovered. Which of the following statements best describes why such a nucleus is extremely unlikely to exist?

<p>The strong nuclear force would be too weak to overcome the electrostatic repulsion between the protons. (B)</p> Signup and view all the answers

The density of a nucleus is primarily determined by:

<p>The mass of the nucleus. (D)</p> Signup and view all the answers

Flashcards

Alpha-Particle Scattering Experiment

An experiment demonstrating the atomic structure through alpha particles interacting with gold foil.

Nuclear Model of the Atom

A model proposing that atoms consist of a small, dense nucleus surrounded by empty space.

Plum Pudding Model

J.J. Thomson's model suggesting atoms are a mix of positive and negative charges.

Observations from the Experiment

Most alpha particles passed through foil, while few were deflected, indicating atomic structure.

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Alpha Particles

Positively charged particles emitted from a radioactive source, used in scattering experiments.

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Gold Foil

Thin sheet used in the alpha-particle scattering experiment to study atomic structure.

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Deflection of Alpha Particles

Change in direction of alpha particles when they encounter the nucleus of an atom.

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Empty Space in Atoms

The majority of an atom's volume is empty space, according to scattering results.

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Nucleus

Dense, positively charged center of the atom containing most of its mass.

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Nucleon number

The total number of protons and neutrons in a nucleus.

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Nucleus size equation

R = r0A^(1/3), where R is the nucleus radius and r0 is approximately 1.2 fm.

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Nuclear density

The density of atomic nuclei, approximately 10^17 kg/m^3.

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Helium-4 nucleus density calculation

Density of a helium-4 nucleus is approximately 2.3 x 10^17 kg/m^3.

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Repulsive electrostatic force

The force between protons due to their positive charges, calculated using Coulomb's law.

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Strong nuclear force

A powerful force that holds protons and neutrons together in the nucleus, overcoming electrostatic repulsion.

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Volume of a nucleus

The volume is V = (4/3)π(r0A^(1/3))^3.

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Scattering angle

The angle at which a particle deviates from its original path after collision.

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Head-on collision

A direct impact where one particle collides straight with another.

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Coulomb's law

A formula that describes the force between two charged particles.

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Radius of the gold nucleus

The estimated size of the gold nucleus, about $10^{-14}$ m.

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Distance of closest approach (d)

The minimum distance between the alpha particle and the nucleus during collision.

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Kinetic energy of alpha particles

The energy an alpha particle has due to its motion, here measured as 1.2 x 10^-12 J.

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Gold nucleus charge

The total charge of the gold nucleus, calculated as +Ze, where Z = 79.

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Alpha particle charge

The charge of an alpha particle, which is +2e.

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Study Notes

Nuclear size and density

  • The radius of the nucleus depends on the nucleon number A of the nucleus.
  • Fast-moving electrons have de Broglie wavelengths of about 10⁻¹⁵ m.
  • Diffraction of such electrons has been used to determine the radii of nuclei.
  • The radius is given by the equation: R = r₀A¹/³
  • Where r₀ has an approximate value of 1.2 fm (1 fm = 10⁻¹⁵ m).
  • The simplest nucleus is that of hydrogen - ¹H, with A = 1.
  • Therefore, think of r₀ as roughly the radius of a proton.
  • The nucleus of an atom is very small but massive (10¹⁷ kg⁻³).
  • All nuclei have a density of around 10¹⁴ kg m⁻³.
  • A spoonful of nuclear material would have a mass of about a thousand million tonnes.
  • Ordinary matter, made of atoms and not just nuclei, has a density of around 10³ kg m⁻³.

Worked example: Density of a helium nucleus

  • Step 1: Calculate the volume of the helium-4 nucleus
    • volume of nucleus = ⁴⁄₃πr₀³A = ⁴⁄₃π(1.2 x 10⁻¹⁵)³ x 4 = 2.895... x 10⁻⁴⁴ m³
  • Step 2: The approximate mass of the helium-4 nucleus is 4 u.
    • density = mass/volume = (4 x 1.661 x 10⁻²⁷) / (2.895... x 10⁻⁴⁴) = 2.3 x 10¹⁷ kg m⁻³
  • Step 3: The mass of the electrons in a helium atom is negligible, so the mass of the helium-4 atom is about 4 u.
    • density of atom = (4 x 1.661 x 10⁻²⁷)/ (⁴⁄₃π x (10⁻¹⁰)³) = 1600 kg m⁻³

Nature of the strong nuclear force

  • In a helium-4 nucleus, the two protons are separated by a distance of about 10⁻¹⁵ m and exert a large repulsive force on each other.
  • According to Coulomb's law, the repulsive electrostatic force F is given by:
    • F = Q₁Q₂ / 4πε₀r² = [(1.60 x 10⁻¹⁹)²] / [4π x 8.85 x 10⁻¹² x (10⁻¹⁵)²] = 230 N
  • This is an extremely large repulsive force, so why do the protons not fly apart?
  • The attractive gravitational force between the protons is far too small (about 10⁻³⁴ N).
  • There must be another, much stronger force acting on the protons. This force is the strong nuclear force.
  • Figure 3 shows a graph of how the nuclear force F varies with separation r for two nucleons.

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