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Questions and Answers
Write a nuclear equation for the alpha decay of $^{231}_{91}Pa$.
Write a nuclear equation for the alpha decay of $^{231}_{91}Pa$.
$^{231}{91}Pa \rightarrow ^4_2He + ^{227}{89}Ac$
Write a nuclear equation for the beta decay of $^{223}_{87}Fr$.
Write a nuclear equation for the beta decay of $^{223}_{87}Fr$.
$^{223}{87}Fr \rightarrow ^0{-1}e + ^{223}_{88}Ra$
Write a nuclear equation for the alpha decay of $^{149}_{62}Sm$.
Write a nuclear equation for the alpha decay of $^{149}_{62}Sm$.
$^{149}{62}Sm \rightarrow ^4_2He + ^{145}{60}Nd$
Write a nuclear equation for the beta decay of $^{165}_{61}Pm$.
Write a nuclear equation for the beta decay of $^{165}_{61}Pm$.
Write a nuclear equation for the alpha decay of $^{249}_{101}Md$.
Write a nuclear equation for the alpha decay of $^{249}_{101}Md$.
Write a nuclear equation for the beta decay of $^{198}_{85}At$.
Write a nuclear equation for the beta decay of $^{198}_{85}At$.
Write a nuclear equation for the beta decay of $^{152}_{54}Xe$.
Write a nuclear equation for the beta decay of $^{152}_{54}Xe$.
Flashcards
Alpha Decay
Alpha Decay
A nuclear reaction where an alpha particle is emitted.
Beta Decay
Beta Decay
A nuclear reaction where a beta particle (electron or positron) is emitted.
$^{231}_{91}Pa$
$^{231}_{91}Pa$
An isotope of Protactinium with 91 protons and 231 total nucleons.
$^{223}_{87}Fr$
$^{223}_{87}Fr$
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$^{231}_{91}Pa \longrightarrow 2^4He + ^{227}{89}Ac$
$^{231}_{91}Pa \longrightarrow 2^4He + ^{227}{89}Ac$
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$^{223}_{87}Fr \longrightarrow {-1}^0e + ^{223}{88}Ra$
$^{223}_{87}Fr \longrightarrow {-1}^0e + ^{223}{88}Ra$
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$^{149}_{62}Sm$
$^{149}_{62}Sm$
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$^{149}_{62}Sm \longrightarrow 2^4He + ^{145}{60}Nd$
$^{149}_{62}Sm \longrightarrow 2^4He + ^{145}{60}Nd$
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$^{165}_{61}Pm$
$^{165}_{61}Pm$
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$^{165}_{61}Pm \longrightarrow {-1}^0e + ^{165}{62}Sm$
$^{165}_{61}Pm \longrightarrow {-1}^0e + ^{165}{62}Sm$
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$^{249}_{101}Md$
$^{249}_{101}Md$
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$^{249}_{101}Md \longrightarrow 2^4He + ^{245}{99}Es$
$^{249}_{101}Md \longrightarrow 2^4He + ^{245}{99}Es$
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$^{146}_{62}Sm$
$^{146}_{62}Sm$
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$^{146}_{62}Sm \longrightarrow 2^4He + ^{142}{60}Nd$
$^{146}_{62}Sm \longrightarrow 2^4He + ^{142}{60}Nd$
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$^{198}_{85}At$
$^{198}_{85}At$
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$^{198}_{85}At \longrightarrow {-1}^0e + ^{198}{86}Rn$
$^{198}_{85}At \longrightarrow {-1}^0e + ^{198}{86}Rn$
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$^{150}_{64}Gd$
$^{150}_{64}Gd$
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$^{150}_{64}Gd \longrightarrow 2^4He + ^{146}{62}Sm$
$^{150}_{64}Gd \longrightarrow 2^4He + ^{146}{62}Sm$
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$^{120}_{55}Cs$
$^{120}_{55}Cs$
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$^{120}_{55}Cs \longrightarrow {-1}^0e + ^{120}{56}Ba$
$^{120}_{55}Cs \longrightarrow {-1}^0e + ^{120}{56}Ba$
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Study Notes
- Nuclear equations are representations of nuclear reactions, showing how nuclei change during radioactive decay or other nuclear processes.
Alpha Decay Equations
- Alpha decay involves the emission of an alpha particle (Helium-4 nucleus) from a radioactive nucleus, reducing the atomic number by 2 and the mass number by 4.
- Protactinium-231 (²³¹Pa) undergoes alpha decay to form Actinium-227 (²²Ac) and an alpha particle (⁴₂He): ²³¹Pa → ⁴₂He + ²²⁷Ac
- Samarium-149 (¹⁴⁹Sm) undergoes alpha decay to form Neodymium-145 (¹⁴Nd) and an alpha particle (⁴₂He): ¹⁴⁹Sm → ⁴₂He + ¹⁴Nd
- Mendelevium-249 (²⁴⁹Md) undergoes alpha decay to form Einsteinium-245 (²⁴Es) and an alpha particle (⁴₂He): ²⁴⁹Md → ⁴₂He + ²⁴Es
- Samarium-146 (¹⁴⁶Sm) undergoes alpha decay to form Neodymium-142 (¹⁴²Nd) and an alpha particle (⁴₂He): ¹⁴⁶Sm → ⁴₂He + ¹⁴²Nd
- Gadolinium-150 (¹⁵⁰Gd) undergoes alpha decay to form Samarium-146 (¹⁴Sm) and an alpha particle (⁴₂He): ¹⁵⁰Gd → ⁴₂He + ¹⁴Sm
Beta Decay Equations
- Beta decay involves the emission of a beta particle (electron) from a radioactive nucleus, increasing the atomic number by 1 and keeping the mass number the same.
- Francium-223 (²²³Fr) undergoes beta decay to form Radium-223 (²²³Ra) and a beta particle (⁰₋₁e): ²²³Fr → ⁰₋₁e + ²²³Ra
- Promethium-165 (¹⁶⁵Pm) undergoes beta decay to form Samarium-165 (¹⁶Sm) and a beta particle (⁰₋₁e): ¹⁶⁵Pm → ⁰₋₁e + ¹⁶Sm
- Astatine-198 (¹⁹⁸At) undergoes beta decay to form Radon-198 (¹⁹⁸Rn) and a beta particle (⁰₋₁e): ¹⁹⁸At → ⁰₋₁e + ¹⁹⁸Rn
- Xenon-152 (¹⁵²Xe) undergoes beta decay to form Cesium-152 (¹⁵²Cs) and a beta particle (⁰₋₁e): ¹⁵²Xe → ⁰₋₁e + ¹⁵²Cs
- Cesium-120 (¹²⁰Cs) undergoes beta decay to form Barium-120 (¹²⁰Ba) and a beta particle (⁰₋₁e): ¹²⁰Cs → ⁰₋₁e + ¹²⁰Ba
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