Questions and Answers
Any NFA having n states can be converted to a DFA having at most (select the smallest possible value)
What is the minimum number of states required for a DFA that accepts the language L = {w | the number of 1’s in w is divisible by 3}?
What is the ϵ-closure of state q1 in the given NFA?
Which of the following strings is accepted by the DFA below?
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Let L1 and L2 be two regular languages. What can we say about the language L = {w1 w2 | w1 ∈ L1, w2 ∈ L2}?
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What is the language accepted by the given NFA?
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Study Notes
NFA to DFA Conversion
- An NFA with n states can be converted to a DFA with at most 2^n states, since the states of the DFA correspond to subsets of the NFA's states.
Counting States in DFA
- For the language L = {w | the number of 1’s in w is divisible by 3}, a DFA requires a minimum of 3 states to track the count of 1's modulo 3.
ε-Closure in NFA
- The ε-closure of a state q includes all states reachable from q through ε-transitions only. For state q1, the ε-closure is {q0, q1}.
Accepted Strings by DFA
- The DFA accepts the string "01011101". Other provided strings do not lead to the accept state.
Regular Languages Concatenation
- The concatenation of two regular languages L1 and L2 results in a language L that is guaranteed to also be regular.
NFA Accepted Language
- The language accepted by a specific NFA includes strings that either begin with 0 or end with 1. Verification involves checking for computation paths leading to accept states based on input string characteristics.
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Description
Test your understanding of converting NFAs to DFAs with this quiz based on the NPTEL Theory of Computation course. Focus on key concepts from Week 1, including relevant theorems and constructions. Perfect for reinforcing your knowledge in automata theory.
