Normal Stress in Axially Loaded Bars

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Questions and Answers

Which type of force is present in an axially loaded bar?

Torsional force
Tangential force
Shear force
Normal force (correct)

In which situations can a bar experience normal stress?

When pulled (tension) or compressed (correct)
When sheared
When bent
When twisted

When is the stress in a bar constant and uniform across the cross-sectional area?

When every point deforms the same amount (correct)
When there are multiple internal forces present
When every point deforms differently
When the bar is twisted

What assumptions is the equation for normal stress (σ = P/A) based on?

<p>Material homogeneity and isotropy (D)</p> Signup and view all the answers

Why is the stress distribution different near the concentrated load compared to far away in an axially loaded bar?

<p>Due to the contribution of particles in distributing the load (C)</p> Signup and view all the answers

Flashcards

Normal force

A force acting perpendicular to a surface, like the force pulling or pushing on a bar.

Normal stress

The internal resistance of a material to deformation, specifically caused by the normal force acting perpendicular to a surface.

Uniform stress distribution

When the stress experienced by the material throughout the cross-section is the same.

Material homogeneity and isotropy

The assumption that the material properties are the same in all directions and at all points within the material.

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Stress distribution in an axially loaded bar

The stress in a bar is not evenly distributed under the direct application of a concentrated load. It's more concentrated near the load and less concentrated further away.

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Study Notes

Normal stress in an axially loaded bar is discussed, where there is only an internal normal force present.
In such cases, the bar is either being pulled (tension) or compressed, with examples like trusses, legs when standing still, trees, chair legs, etc.
The stress in the bar is important to determine when it will break.
The stress is constant and uniform across the cross-sectional area when every point deforms the same amount.
The equation for normal stress (σ = P/A) is based on assumptions of material homogeneity and isotropy.
The equation applies at locations with uniform deformation and is an average normal stress.
The stress distribution is different near the concentrated load compared to far away due to the contribution of particles in distributing the load.