Normal Distribution Statistics Quiz

$\sigma^2$

$\mu$ (correct)

$\sigma$

$\sqrt{2\pi}$

Mode of the distribution

Standard deviation of the distribution (correct)

Mean of the distribution

Variance of the distribution

$f(x) = \frac{1}{\sigma \sqrt{2\pi}} e^{-\frac{1}{2}\left(\frac{x-\mu}{\sigma}\right)^2}$ (correct)

$f(x) = \frac{1}{\sigma} e^{-\frac{1}{2}\left(\frac{x-\mu}{\sigma}\right)^2}$

$f(x) = \frac{1}{\sqrt{2\pi}} e^{-\frac{1}{2}\left(\frac{x-\mu}{\sigma}\right)^2}$

$f(x) = \sigma^2 \sqrt{2\pi} e^{-\frac{1}{2}\left(\frac{x-\mu}{\sigma}\right)^2}$

<p>Normal deviate</p> Signup and view all the answers

<p>Due to the central limit theorem</p> Signup and view all the answers