NCERT Class 12 Chemistry Chapter 2 Solutions Quiz

Study Notes

Mass Percentage Calculations

Mass percentage of a component in a solution is calculated as:
[ \text{Mass %} = \left( \frac{\text{mass of component}}{\text{total mass of solution}} \right) \times 100 ]
For benzene (C6H6):
Mass of benzene = 22 g
Mass of carbon tetrachloride (CCl4) = 122 g
Total mass of solution = 22 g + 122 g = 144 g
Mass percentage of benzene:
[ \text{Mass % of C6H6} = \left( \frac{22 , \text{g}}{144 , \text{g}} \right) \times 100 \approx 15.28% ]
For carbon tetrachloride (CCl4):
Mass percentage of CCl4:
[ \text{Mass % of CCl4} = \left( \frac{122 , \text{g}}{144 , \text{g}} \right) \times 100 \approx 84.72% ]

Molar Mass

Molar mass of benzene (C6H6):
Carbon (C) = 12.01 g/mol, Hydrogen (H) = 1.008 g/mol
Molar mass calculation:
[ (6 \times 12.01) + (6 \times 1.008) = 72.06 + 6.048 = 78.11 , \text{g/mol} ]
Molar mass of carbon tetrachloride (CCl4):
Chlorine (Cl) = 35.45 g/mol
Molar mass calculation:
[ 12.01 + (4 \times 35.45) = 12.01 + 141.80 = 153.81 , \text{g/mol} ]

Solution Summary

Total mass of the solution when 22 g of benzene is mixed with 122 g of carbon tetrachloride is 144 g.
Mass percentages provide insight into the composition of the solution, with benzene making up approximately 15.28% and carbon tetrachloride about 84.72%.

Description

Test your understanding of NCERT Class 12 Chemistry Chapter 2 solutions with this quiz. The quiz covers important concepts and provides a helpful resource for students preparing for their board examinations.