6 Questions
Quid est radicem quadratam de $16$?
$4$
Quid est resultatus de $3 oot{3} oline{√}2 + 2 oot{3} oline{√}2$?
$5 oot{3} oline{√}2$
Si res est $rac{ oot{3} oline{√}27}{ oot{3} oline{√}9}$, quae est res?
$3$
What is the result of $2 oot{3}{5} - oot{3}{20}$?
$ oot{3}{10} - oot{3}{20}$
If $3 oot{3}{7} imes 4 oot{3}{7} = a oot{3}{7}$, what is the value of $a$?
$24$
When simplifying the expression $rac{3 oot{3}{12}}{2 oot{3}{3}}$, what is the denominator after simplification?
$2 oot{3}{3}$
Study Notes
Radices Quadratae
- Radicem quadratam de $16$ est $4$, quod est numerus qui, multiplicatus per se ipsum, dat $16$.
Algebra Radicum
- Resultatus de $3\sqrt{2} + 2\sqrt{3}$ est $5\sqrt{2} + 2\sqrt{3}$.
Fractiones Radicum
- Si res est $\frac{\sqrt{27}}{\sqrt{9}}$, quae est res, tunc res est $\sqrt{3}$, quod est radix quadrata de $3$.
Operationes Radicum
- Resultatus de $2\sqrt[3]{5} - \sqrt[3]{20}$ est $\sqrt[3]{10}$, quod est radix cubica de $10$.
Multiplicatio Radicum
- Si $3\sqrt[3]{7} \times 4\sqrt[3]{7} = a\sqrt[3]{7}$, tunc $a$ est $12$.
Simplificatio Fractionum Radicum
- Denominator, post simplificationem, in expressione $\frac{3\sqrt[3]{12}}{2\sqrt[3]{3}}$ est $\sqrt[3]{3}$.
Test your knowledge of surds at a MYP year 5 extended math level with questions about adding, subtracting, multiplying, and dividing them. This quiz will help you practice and consolidate your understanding of surds.
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