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Questions and Answers
In the reaction $N_2 + 3H_2 \rightarrow 2NH_3$, if you have 3 moles of $N_2$, how many moles of $NH_3$ can be produced?
In the reaction $N_2 + 3H_2 \rightarrow 2NH_3$, if you have 3 moles of $N_2$, how many moles of $NH_3$ can be produced?
- 2 moles
- 3 moles
- 6 moles (correct)
- 9 moles
For the reaction $C_3H_8 + 5O_2 \rightarrow 3CO_2 + 4H_2O$, if 25 moles of $O_2$ react, how many moles of $H_2O$ are produced?
For the reaction $C_3H_8 + 5O_2 \rightarrow 3CO_2 + 4H_2O$, if 25 moles of $O_2$ react, how many moles of $H_2O$ are produced?
- 16 moles
- 28 moles
- 20 moles (correct)
- 4 moles
Given the reaction $4NH_3 + 3O_2 \rightarrow 2N_2 + 6H_2O$, what amount of $N_2$ will be produced if 8 moles of $NH_3$ react?
Given the reaction $4NH_3 + 3O_2 \rightarrow 2N_2 + 6H_2O$, what amount of $N_2$ will be produced if 8 moles of $NH_3$ react?
- 12 moles
- 4 moles (correct)
- 6 moles
- 2 moles
Consider the reaction $2N_2 + 6H_2 \rightarrow 4NH_3$. If you start with 9 moles of $H_2$, how many moles of $N_2$ are required for a complete reaction?
Consider the reaction $2N_2 + 6H_2 \rightarrow 4NH_3$. If you start with 9 moles of $H_2$, how many moles of $N_2$ are required for a complete reaction?
For the reaction $C_3H_8 + 5O_2 \rightarrow 3CO_2 + 4H_2O$, if you want to produce 20 moles of $CO_2$, how many moles of $C_3H_8$ are needed?
For the reaction $C_3H_8 + 5O_2 \rightarrow 3CO_2 + 4H_2O$, if you want to produce 20 moles of $CO_2$, how many moles of $C_3H_8$ are needed?
In the reaction $4NH_3 + 3O_2 \rightarrow 2N_2 + 6H_2O$, if 1 mole of $N_2$ is produced, how many moles of $O_2$ were reacted?
In the reaction $4NH_3 + 3O_2 \rightarrow 2N_2 + 6H_2O$, if 1 mole of $N_2$ is produced, how many moles of $O_2$ were reacted?
Consider the balanced equation $N_2 + 3H_2 \rightarrow 2NH_3$. If you have 6 moles of $H_2$, what is the theoretical yield of $NH_3$, in moles?
Consider the balanced equation $N_2 + 3H_2 \rightarrow 2NH_3$. If you have 6 moles of $H_2$, what is the theoretical yield of $NH_3$, in moles?
For the reaction $C_3H_8 + 5O_2 \rightarrow 3CO_2 + 4H_2O$, if 8 moles of $C_3H_8$ are consumed completely, how many moles of $CO_2$ are produced?
For the reaction $C_3H_8 + 5O_2 \rightarrow 3CO_2 + 4H_2O$, if 8 moles of $C_3H_8$ are consumed completely, how many moles of $CO_2$ are produced?
Given the reaction $4NH_3 + 3O_2 \rightarrow 2N_2 + 6H_2O$, if 12 moles of water are produced, how many moles of ammonia were initially reacted?
Given the reaction $4NH_3 + 3O_2 \rightarrow 2N_2 + 6H_2O$, if 12 moles of water are produced, how many moles of ammonia were initially reacted?
In the reaction $N_2 + 3H_2 \rightarrow 2NH_3$, if 4 moles of $N_2$ and 9 moles of $H_2$ are initially present, what is the limiting reactant?
In the reaction $N_2 + 3H_2 \rightarrow 2NH_3$, if 4 moles of $N_2$ and 9 moles of $H_2$ are initially present, what is the limiting reactant?
Flashcards
Mole Ratio
Mole Ratio
The ratio between the amounts in moles of any two substances in a chemical reaction.
Reading Balanced Equations
Reading Balanced Equations
N2 + 3H2 -> 2NH3 means one mole of nitrogen gas reacts with three moles of hydrogen gas to produce two moles of ammonia.
Propane and Oxygen Reaction
Propane and Oxygen Reaction
C3H8 + 5O2 -> 3CO2 + 4H2O. To produce 14 moles of water, 17.5 moles of oxygen are needed.
Ammonia and Oxygen Reaction (Part A)
Ammonia and Oxygen Reaction (Part A)
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Ammonia and Oxygen Reaction (Part B)
Ammonia and Oxygen Reaction (Part B)
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Study Notes
Understanding Mole Ratio
- Coefficients in a balanced chemical equation reveal the mole ratio between compounds.
- N2 + 3H2 -> 2NH3 signifies that one mole of nitrogen gas reacts with three moles of hydrogen gas to produce two moles of ammonia.
- The mole ratio can be scaled.
- 2 N2 + 6 H2 -> 4 NH3 as an example of doubling the original reaction.
- 3 N2 + 9 H2 -> 6 NH3 as an example of tripling the original reaction.
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- 5 moles of N2 will react with 4.5 moles of H2, based on the 1:3 ratio.
Example 1: Propane and Oxygen
- Question: Determine the moles of oxygen gas required to produce 14 moles of water from the reaction of propane and oxygen gas.
- Balanced equation: C3H8 + 5O2 -> 3CO2 + 4H2O
- The mole ratio of O2 to H2O is 5:4.
- 10 moles of O2 yields 8 moles of H2O.
- 15 moles of O2 yields 12 moles of H2O.
- 20 moles of O2 yields 16 moles of H2O.
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- 5 moles of oxygen are required to produce 14 moles of water.
- Calculation: (14 moles H2O) * (5 moles O2 / 4 moles H2O) = 17.5 moles O2
Example 2: Ammonia and Oxygen
- Question A: Determine the moles of oxygen gas required to react completely with 11 moles of ammonia.
- Question B: Determine the moles of water produced in this process.
- Balanced equation: 4NH3 + 3O2 -> 2N2 + 6H2O
- The molar ratio between NH3 and O2 is 4:3, and between NH3 and H2O is 4:6.
Part A Solution
- Starting with 11 moles of NH3, convert to moles of O2.
- (11 moles NH3) * (3 moles O2 / 4 moles NH3) = 8.25 moles of O2 are required.
Part B Solution
- Starting with 11 moles of NH3, convert to moles of H2O.
- (11 moles NH3) * (6 moles H2O / 4 moles NH3) = 16.5 moles of H2O are produced.
- 11 moles of ammonia will produce 16.5 moles of water and react completely with 8.25 moles of O2.
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