Questions and Answers
Which of the following are possible mixture problem situations? (Select all that apply)
If x represents the pounds of walnuts used in the mixture, which expression would represent the total cost of the pecans used in the mixture?
0.60(90 - x)
If a dairyman has 300 pounds of milk testing 3% butterfat, how many pounds of skimmed milk must he remove to have milk testing 3.6% butterfat?
50 pounds
How much alcohol must a druggist add to a 20-ounce quantity of a 7% solution of iodine to reduce it to a 4% solution?
Signup and view all the answers
If x represents the number of quarts of 36 cent oil, which equation could be used to solve the mixing oil problem?
Signup and view all the answers
How many pounds of 80 cent seed should a seedman use to make a mixture of 30 pounds selling at 75¢ per pound?
Signup and view all the answers
Which expression represents the number of pounds of salt in the new 25% salt solution if x represents the pounds of salt to be added?
Signup and view all the answers
How much tin must be added to create 820 pounds of alloy that is 18% tin?
Signup and view all the answers
What percentage of gold is in the new alloy after recasting if it consists of 80 ounces with only one-fifth of an ounce of gold in 5 ounces?
Signup and view all the answers
How much silver must be added if the new alloy is to have only one-fifth of an ounce of gold in 5 ounces?
Signup and view all the answers
Study Notes
Mixture Problem Situations
- Mixture problems can involve financial investments, chemical compositions, or agricultural seed types.
Cost of Mixtures
- Total cost for pecans in a mixture: 0.60(90 - x), where x is the pounds of walnuts.
Dairyman's Butterfat Problem
- To increase butterfat from 3% to 3.6% in 300 pounds of milk, 50 pounds of skimmed milk must be removed.
Reduction of Iodine Solution
- To convert a 20-ounce 7% iodine solution to a 4% solution, 15 ounces of pure alcohol must be added.
Oil Mixture Equation
- For blending oils worth 36¢ and 52¢ to create a 300-gallon mixture worth 40¢ per quart, the equation is: 0.36x + 0.52(1200 - x) = 0.40(1200).
Seed Mixture Calculation
- To prepare a 30-pound seed mixture, 25 pounds of 80¢ seeds are required to achieve a selling price of 75¢ per pound.
Saltwater Solution Expression
- For a 50-pound saltwater solution with 10% salt, the expression representing the salt in a new 25% solution after adding x pounds of salt is: 0.25(x + 50).
Tin in Alloy Problem
- Adding tin to an alloy that initially contains 16% tin must result in an 18% tin alloy of 820 pounds; approximately 19.5 pounds of tin must be added.
Gold Percentage in Alloy
- After recasting an alloy of silver and gold to include more silver and achieve a specific composition, the new alloy contains 4% gold.
Silver Addition Calculation
- To adjust a silver and gold alloy weighing 80 ounces (with 10 ounces of gold) to ensure 1/5 ounce of gold per 5 ounces in the new mixture, 170 ounces of silver must be added.
Studying That Suits You
Use AI to generate personalized quizzes and flashcards to suit your learning preferences.
Description
Test your understanding of mixture problems with these flashcards. Explore various scenarios involving investments, chemistry, and agriculture. Solve practical examples to enhance your problem-solving skills.
