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McDougal Littell Geometry Chapter 12: Surface Area and Volume Practice

Test your skills in calculating surface area and volume of various geometric shapes, including cones, spheres, pyramids, and cylinders. This practice quiz covers formulas and problems from Chapter 12 of the McDougal Littell Geometry book.

Created by
@InspiringInterstellar

What is the formula to find the surface area of a cone?

SA = πr² + πr√(r² + h²)

A sphere has a radius of 4 cm. What is the volume of the sphere?

V = (4/3)π(4)³ = 268.08 cm³

LSA = ½pl

A cylinder has a radius of 3 cm and a height of 6 cm. What is the surface area of the cylinder?

<p>SA = 2πr(h + r) = 2π(3)(6 + 3) = 150.72 cm²</p> Signup and view all the answers

What is the formula to find the volume of a pyramid?

<p>V = (1/3)Bh</p> Signup and view all the answers

Study Notes

Surface Area and Volume of Various Shapes

• The formula to find the surface area of a cone is not provided in the given text, but it is typically represented as SA = πr(r + l), where r is the radius and l is the slant height.
• The volume of a sphere with a radius of 4 cm can be found using the formula V = (4/3)πr³, resulting in a volume of approximately 268.08 cm³.
• The formula to find the lateral surface area of a pyramid is not provided in the given text, but it is typically represented as LSA = 1/2pl, where p is the perimeter of the base and l is the slant height.
• The surface area of a cylinder with a radius of 3 cm and a height of 6 cm can be found using the formula SA = 2πr(h + r), resulting in a surface area of approximately 150.72 cm².
• The formula to find the volume of a pyramid is not provided in the given text, but it is typically represented as V = (1/3)Bh, where B is the area of the base and h is the height.

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