Podcast
Questions and Answers
Magnetic fields are created by what?
Magnetic fields are created by what?
moving charges
What is magnetostatics?
What is magnetostatics?
Magnetostatics is the study of magnetic fields due to constant (steady) current sources.
What does the Biot-Savart law give us?
What does the Biot-Savart law give us?
The magnetic field dB due to a current element
Given an infinite wire, the magnitude of this vector is $B = \frac{\mu_0 I}{2\pi _____}$
Given an infinite wire, the magnitude of this vector is $B = \frac{\mu_0 I}{2\pi _____}$
Flashcards
Magnetostatics
Magnetostatics
The study of magnetic fields due to constant (steady) current sources.
Biot-Savart Law
Biot-Savart Law
A law that gives the magnetic field dB due to a current element.
R (in Biot-Savart Law)
R (in Biot-Savart Law)
The vector from the source to the point where the magnetic field is calculated.
dl (in Biot-Savart Law)
dl (in Biot-Savart Law)
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Right-hand rule
Right-hand rule
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B = (μ₀I) / (2πr)
B = (μ₀I) / (2πr)
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Study Notes
- Magnetic fields are vector fields, denoted as B, created by moving charges.
- The magnetic field due to a moving point charge is given by: B = (μ₀ / 4π) * (qν × R) / |R|².
- Magnetostatics and the Biot-Savart law will be covered.
- Distance Vector: R = r - r', where R is the physical distance vector.
- r is the vector from the origin to the point where the field is calculated.
- r' is the vector from the origin to the source of the field.
- R is the vector from the source to the point of calculation.
- Magnetic fields due to moving point charges curl around the charge.
Magnetostatics
- Study of magnetic fields from constant (steady) current sources, similar to electrostatics with stationary charges.
- Constant current I creates a magnetic field B, the sum of contributions from moving charges via superposition: Btot = B1 + B2 + B3 + ...
Biot-Savart Law
- Gives the magnetic field dB due to a current element: dB = (μ₀ / 4π) * (Idl × R) / |R|².
- sin definition: dB = (μ₀ / 4π) * (Idl sin φ) / R², where R is the distance from the wire element to the point P.
- For an extended wire, integrate the equation to find the total magnetic field.
Magnetic Field due to a Wire of Length 2a
- Formula: B = (μ₀ / 4π) ∫ (Idl × R) / |R|²
- Considering wire of length 2a on the y-axis:
- r = <x, 0, 0>
- r' = <0, y, 0>
- R = <x, -y, 0>
- |R| = √(x² + y²)
- Unit vector R = (1/√(x² + y²)) <x, -y, 0>
- dl is in the direction of current: dl = <0, dy, 0>
- dl = |dl|ÃŽ, where |dl| = dy and ÃŽ = <0, 1, 0>
- dB = (μ₀ / 4π) * (Idl × R) / |R|² can be calculated by finding dl x R
- dl × R = <0, 0, xdy / √(x² + y²)
- dB = -((μ₀ * I) / (4π)) * (x dy) / (x² + y²)^(3/2) k
- Integrating from y = -a to y = a:
- x is constant wrt integration
- B = -k (μ₀ * I) / (4π) * [y / (x²√(x² + y²)] from -a to a
Magnetic Field due to Infinite Wire
- derived from previous equation, when y goes to infinity
- B = -(k μ₀ I) / (4π) * (2a / (x √(x² + a²))
- B = -(k μ₀ I) / (2πx)
- Magnitude: B = (μ₀I) / (2πr), where r is the distance from the wire.
- Standard introductory result for magnetostatics.
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