Magnetic Fields and Forces Quiz
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Questions and Answers

What is the formula for the force of a magnetic field on a current-carrying wire?

  • F = 4.6 x 10^-5 T
  • F = IlB sinθ (correct)
  • F = 2.2 x 10^-8 N
  • F = qvB sinθ
  • What is the magnitude of the current required to remove the tension in the supporting leads for the wire suspended in a uniform magnetic field?

  • 4.8 x 10^-4 N
  • 0.487 A (correct)
  • 1.6 x 10^-13 N
  • 10kN
  • For the new design of an electric train, what is the magnetic force needed to provide a current of 3.3 x 10^8 A?

  • F = qvB sinθ
  • F = 4.6 x 10^-5 T
  • F = IlB sinθ
  • 10kN (correct)
  • What are the magnitude of the magnetic force and acceleration of the proton when it encounters a magnetic field of 0.40 T at an angle of 30 degrees?

    <p>1.6 x 10^-13 N, 9.6 x 10^13 m/s</p> Signup and view all the answers

    What is the formula for the force of a magnetic field on a charge moving with velocity v?

    <p>F = qvB sinθ</p> Signup and view all the answers

    What is the magnitude of the magnetic field strength (B) when B = 2 x 10^-7(I/r) and F = 2.2 x 10 ^-8 N?

    <p>4.6 x 10^-5 T</p> Signup and view all the answers

    What is the formula for the force of a magnetic field on a charge moving with velocity v?

    <p>F = qvB sinθ</p> Signup and view all the answers

    What is the magnitude of the current required to remove the tension in the supporting leads for the wire suspended in a uniform magnetic field?

    <p>I = 0.487 A</p> Signup and view all the answers

    What are the magnitude of the magnetic force and acceleration of the proton when it encounters a magnetic field of 0.40 T at an angle of 30 degrees?

    <p>1.6 x 10^-13 N, 9.6 x 10^13 m/s^2</p> Signup and view all the answers

    What is the formula for the force of a magnetic field on a current-carrying wire?

    <p>F = BIl sinθ</p> Signup and view all the answers

    For the new design of an electric train, what is the magnetic force needed to provide a current of 3.3 x 10^8 A?

    <p>10kN</p> Signup and view all the answers

    What is the magnitude of the magnetic field strength (B) when B = 2 x 10^-7(I/r) and F = 2.2 x 10^-8 N?

    <p>4.6 x 10^-5 T</p> Signup and view all the answers

    Study Notes

    Magnetic Force Formulas

    • The formula for the force of a magnetic field on a current-carrying wire is F = BIL sin(θ), where F is the force, B is the magnetic field strength, I is the current, L is the length of the wire, and θ is the angle between the wire and the magnetic field.
    • The formula for the force of a magnetic field on a charge moving with velocity v is F = qvB sin(θ), where F is the force, q is the charge, v is the velocity, B is the magnetic field strength, and θ is the angle between the velocity and the magnetic field.

    Magnetic Force and Acceleration

    • The magnitude of the magnetic force and acceleration of a proton when it encounters a magnetic field of 0.40 T at an angle of 30 degrees can be calculated using the formula F = qvB sin(θ).
    • The acceleration of the proton can be calculated using the formula a = F/m, where a is the acceleration, F is the magnetic force, and m is the mass of the proton.

    Magnetic Field Strength

    • The magnetic field strength (B) can be calculated using the formula B = 2 x 10^-7(I/r), where I is the current and r is the distance from the wire.
    • The magnetic field strength (B) can also be calculated using the formula F = 2.2 x 10^-8 N, where F is the force and B is the magnetic field strength.

    Current and Magnetic Force

    • The magnitude of the current required to remove the tension in the supporting leads for the wire suspended in a uniform magnetic field can be calculated using the formula F = BIL sin(θ).
    • The magnetic force needed to provide a current of 3.3 x 10^8 A for the new design of an electric train can be calculated using the formula F = BIL sin(θ).

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    Description

    Test your knowledge of magnetic fields and forces with this quiz. Practice calculating magnetic field strength, magnetic flux, and the force of a magnetic field on a current-carrying wire.

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