Linear Programming and Transportation Planning

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Questions and Answers

Is the solution x1 = 2, x2 = 5 feasible for the equation 0.4x1 + 0.6x2 = 0?

  • Yes, as it satisfies the production requirements.
  • No, because the coefficients must be equal.
  • No, because the equation leads to a contradiction. (correct)
  • Yes, because both variables are positive.

What does the equation 0.4x1 + 0.6x2 = 0 imply about the values of x1 and x2?

  • At least one of the variables must be greater than one.
  • Both variables must equal zero. (correct)
  • At least one of the variables must be negative.
  • Both x1 and x2 must be positive.

If 0.4x1 + 0.6x2 = 0 and x1 = 0, what must x2 be for the equation to hold true?

  • Any positive number.
  • Any negative number.
  • It must also be zero. (correct)
  • It must be less than zero.

What is the significance of the coefficients 0.4 and 0.6 in the equation 0.4x1 + 0.6x2 = 0?

<p>They show the relationship between the two variables in the production process. (A)</p> Signup and view all the answers

In the context of the equation 0.4x1 + 0.6x2 = 0, what can be inferred about the production levels when x1 and x2 are both positive?

<p>They lead to an infeasibility in the equation. (A)</p> Signup and view all the answers

For the production equation $0.4x_1 + 0.6x_2 = 0$, what must be true if $x_1$ is a positive number?

<p>$x_2$ must be negative. (D)</p> Signup and view all the answers

If a production problem is defined by $0.4x_1 + 0.6x_2 = 0$, what does this imply about the relationship between $x_1$ and $x_2$?

<p>If $x_1$ increases, then $x_2$ must decrease and be proportional (A)</p> Signup and view all the answers

For the equation $0.4x_1 + 0.6x_2 = 0$, which of the following pairs $(x_1, x_2)$ is a feasible solution?

<p>(3,-2) (A)</p> Signup and view all the answers

If the production equation is $0.4x_1 + 0.6x_2 = 0$ and we know that $x_2 = -4$, what is the value of $x_1$?

<p>+6 (B)</p> Signup and view all the answers

In a production model represented by $0.4x_1 + 0.6x_2 = 0$, if both $x_1$ and $x_2$ are constrained to be non-negative, which of these is true?

<p>The only solution is that both $x_1$ and $x_2$ must both equal zero. (A)</p> Signup and view all the answers

Flashcards

Feasibility in Linear Programming

A solution is feasible if all constraints in the linear programming problem are satisfied. In this case, we are given that the constraint is 0.4x1 + 0.6x2 = 0. We need to determine if the values x1 = 2 and x2 = 5 satisfy this constraint. Substituting these values into the constraint, we get: 0.4(2) + 0.6(5) = 0.8 + 3 = 3.8. As the result is not 0, the solution is not feasible.

Constraint in Linear Programming

A constraint in linear programming represents a limitation or restriction on the variables in the problem. These constraints define the feasible region, which represents all the possible solutions that satisfy these limitations.

Variables in Linear Programming

Variables in linear programming represent the quantities or amounts that we are trying to determine in the problem. They are typically represented by letters like x1, x2, ..., xn.

Solution in Linear Programming

A solution to a linear programming problem is a set of values for the decision variables that satisfy all the constraints. There may be multiple solutions, but we are typically trying to find the optimal solution.

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What is a feasible solution in linear programming?

In linear programming, a feasible solution is one that satisfies all the constraints of the problem. This means that all the values of the variables in the solution meet the conditions specified by the constraints.

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What is a constraint in linear programming?

A constraint in linear programming is a limitation or restriction on the variables of the problem. They define the feasible region of possible solutions. Examples include maximum resource availability or production capacity.

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What are the variables in linear programming?

Variables in linear programming represent the quantities or amounts that we are trying to determine in the problem. They are typically represented by letters like x1, x2, ..., xn. These variables represent factors that can be adjusted to optimize a particular objective.

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How do you check if a solution is feasible?

To check if a solution is feasible, substitute the given variable values into the constraint equation. If the equation is true, the solution is feasible. If it's false, the solution is not feasible.

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Is the solution x1 = 2, x2 = 5 feasible for the constraint 0.4x1 + 0.6x2 = 0?

In the given problem, the constraint is 0.4x1 + 0.6x2 = 0. When we substitute x1 = 2 and x2 = 5, we get 0.8 + 3 = 3.8. Since this does not equal 0, the solution is not feasible.

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Study Notes

Linear Programming, Transportation, and Production Planning

  • Constraint 1: A production problem uses the constraint 0.4x₁ + 0.6x₂ ≤ 300. Optimal solution uses 300 labor hours. The constraint is binding because the left-hand side equals the right-hand side.

  • Constraint 2: A resource constraint is 5x₁ + 2x₂ ≤ 50. The solution only uses 45 units. The constraint is not binding because the left-hand side does not reach 50.

  • Constraint 3 (New): A company with two suppliers and three warehouses has a constraint for Warehouse 3 as x₁₃ + x₂₃ = 150. This means the total shipments to Warehouse 3 must be 150.

  • Shadow Price: A shadow price of $10 indicates that adding one unit of the resource increases profit by $10.

  • Shadow Price of $0: A shadow price of $0 means the constraint is non-binding, and additional resource availability will not affect the objective function.

  • Transportation Problem Objective Function: A company's transportation problem with costs (C₁₁ = 5, C₁₂ = 6, C₂₁ = 4) has an objective function to minimize cost (Z = 5x₁₁ + 6x₁₂ + 4x₂₁).

  • Inventory Holding Cost Objective Function: A factory producing two products with costs of $12 and $18 per unit and inventory holding costs of $3 and $4 per unit, respectively, has an objective function to minimize total cost (Z = 12xA + 18xB + 3sA + 4sB).

  • Minimization Problem Objective Function: The goal of an objective function in a minimization problem is to minimize resource use and minimize total cost.

  • Feasibility (Constraint 1): 4x₁ + 3x₂ ≤ 24. Examples of feasible solutions: x₁ = 2, x₂ = 4; x₁ = 3, x₂ = 2

  • Feasibility (Constraint 2): 5x₁ + 2x₂ ≥ 20. x₁ = 2, x₂ = 5 is not feasible.

  • Feasibility (Constraint 3): Additional examples of x1 and x2 values that satisfy 4x₁ + 3x₂ <= 24 are provided

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