Linear Algebra: Quotient Spaces

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Questions and Answers

What is the equivalence relation defined on V?

v1 ∼ v2 if v1 − v2 ∈ W

What do we call the set of equivalence classes V/∼?

The quotient of V by its subspace W, denoted by V/W

How is the equivalence class containing v ∈ V denoted?

v + W

What linear map exists from V to V/W?

<p>The linear map V -&gt; V/W which sends a vector v in V to its equivalence class v + W</p> Signup and view all the answers

What is the relationship between Imf and V/Kerf?

<p>Imf is isomorphic to V/Kerf</p> Signup and view all the answers

What must be checked to prove that Imf is isomorphic to V/Kerf?

<p>One must define a map f : V/Kerf → Imf by the formula f(v + Kerf) = f(v) and check injectivity and surjectivity</p> Signup and view all the answers

What is the kernel of the linear map from V to V/W?

<p>The subspace W</p> Signup and view all the answers

What is the dimension of V/W in relation to V and W?

<p>dim V/W = dim V - dim W</p> Signup and view all the answers

When does a linear operator f induce a well-defined linear operator on V/W?

<p>When W is f-invariant</p> Signup and view all the answers

What is required for the function f̄ to be well-defined?

<p>For all v + W = v′ + W, f(v) + W = f(v′) + W must hold true.</p> Signup and view all the answers

What kind of basis does the set A = {v + W : v ∈ B \ BW} form for V/W?

<p>An ordered basis for V/W</p> Signup and view all the answers

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Study Notes

Equivalence Relation in Vector Spaces

  • Define equivalence relation on vector space ( V ): ( v_1 \sim v_2 ) if ( v_1 - v_2 \in W ), where ( W ) is a subspace of ( V ).

Quotient of Vector Space

  • The set of equivalence classes ( V/\sim ) is the quotient of ( V ) by its subspace ( W ), denoted ( V/W ).

Vector Space Structure of Quotient

  • Quotient ( V/W ) forms a vector space.
  • Define equivalence class of ( v \in V ) as ( v + W ).
  • Vector addition: ( (v + W) + (v' + W) := (v + v') + W ).
  • Scalar multiplication: ( a(v + W) := av + W ).
  • Well-definedness confirmed by the property of equivalence relations.

Linear Map to Quotient Space

  • A linear map ( V \to V/W ) exists, mapping each vector ( v ) in ( V ) to its equivalence class ( v + W ).
  • The kernel of this linear map is the subspace ( W ).

Isomorphism Between Image and Quotient

  • The image ( \text{Im} f ) of a linear map ( f: V \to W ) is isomorphic to ( V/\text{Ker} f ).

Proof of Isomorphism

  • Define map ( f: V/\text{Ker} f \to \text{Im} f ) by ( f(v + \text{Ker} f) = f(v) ).
  • Check injectivity: If ( f(v + \text{Ker} f) = 0 ), then ( v \in \text{Ker} f ).
  • Check surjectivity: For any ( w \in \text{Im} f ), there exists ( v \in V ) such that ( f(v) = w ).

Dimension Formula

  • For a linear map ( V \to V/W ), it is surjective with kernel ( W ).
  • Dimension formula: ( \text{dim}(V/W) = \text{dim}(V) - \text{dim}(W) ).

Example of Dimension Calculation

  • For space of polynomials degree ( \le n ), ( \text{dim}(V) = n + 1 ).
  • If linear operator ( f: p(x) \to p''(x) ), kernel is the subspace of polynomials degree ( \le 1 ) (dim ( 2 )).
  • Thus, ( \text{dim}(V/W) = n - 1 ).

Well-defined Operator Induction

  • A linear operator ( f: V \to V ) induces a well-defined operator ( \overline{f}: V/W \to V/W ) if ( W ) is ( f )-invariant.

Requirements for Well-definedness of Induced Operator

  • The function ( \overline{f} ) is well-defined if for all ( v + W = v' + W ), ( \overline{f}(v) + W = \overline{f}(v') + W ).
  • This requires ( f(v) - f(v') \in W ).

Basis and Induced Operator

  • For finite-dimensional ( V ) and ( f )-invariant subspace ( W ), if ( B_W ) is an ordered basis for ( W ):
    • Extend ( B_W ) to an ordered basis ( B ) for ( V ).
    • ( A = {v + W : v \in B \setminus B_W} ) forms an ordered basis for ( V/W ).
    • Relation between matrices: ( M_{B}(f) = M_{B_W}(f) ) follows from the induced operator on ( V/W ).

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