Podcast
Questions and Answers
What type of error occurs when attempting to access a variable that has not been declared?
What type of error occurs when attempting to access a variable that has not been declared?
- ReferenceError (correct)
- RangeError
- TypeError
- SyntaxError
Which example illustrates a SyntaxError in JavaScript?
Which example illustrates a SyntaxError in JavaScript?
- console.log(x);
- let name = 'John'; name.pop();
- const number = 5;
- var a = 'missing quote; (correct)
In which scenario would a TypeError be thrown?
In which scenario would a TypeError be thrown?
- console.log('test' + 5);
- Using undefined value in a mathematical operation
- (3).toString(8);
- 'hello'.pop(); (correct)
When would a RangeError be likely to occur?
When would a RangeError be likely to occur?
Which statement is true regarding JavaScript errors?
Which statement is true regarding JavaScript errors?
Flashcards
ReferenceError
ReferenceError
Occurs when you try to use a variable that hasn't been declared.
SyntaxError
SyntaxError
Caused by invalid JavaScript code.
TypeError
TypeError
Happens when a method is called on a wrong data type.
RangeError
RangeError
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Undeclared Variable
Undeclared Variable
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Study Notes
JavaScript Error Types
-
ReferenceError: This error happens when you use a variable that hasn't been declared. For example, attempting to use
usernamewithout defining it first will produce a ReferenceError. -
SyntaxError: This error occurs due to incorrect JavaScript code structure. Invalid syntax, like missing operators (e.g., trying to assign a value without an assignment operator
=), leads to a SyntaxError. -
TypeError: This error arises when a method or function is inappropriately used on a data type that doesn't support it. An example is trying to use the
.pop()method on a string, because strings do not contain arrays to pop from. -
RangeError: This error is triggered when a value is outside the permissible range for a particular function or operation. For example, using base-100 as a parameter for the
.toString()method is a RangeError, because the usual base is only 2 to 36.
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