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Questions and Answers
What is the output of: Object x = "whoot"; object y = x; x = null; System.out.println(y);
What is the output of: Object x = "whoot"; object y = x; x = null; System.out.println(y);
whoot
What is the output of: Object a = "whoot"; object b = a; b = null; System.out.println(a);
What is the output of: Object a = "whoot"; object b = a; b = null; System.out.println(a);
whoot
What happens in the method mystery(Object one, Object two) when called with (g, h)?
What happens in the method mystery(Object one, Object two) when called with (g, h)?
It prints the value of 'h'.
What is printed after calling test.mystery2(z, w)?
What is printed after calling test.mystery2(z, w)?
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What will happen if test.mystery3(list) is called?
What will happen if test.mystery3(list) is called?
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Study Notes
Java Object References and Outputs
- When an object is assigned to another variable, both variables point to the same memory location.
- In the example with
Object x = "whoot";andObject y = x;, settingxtonulldoes not affecty, which still references "whoot". - Output of
System.out.println(y);is "whoot".
Variable Reassignment and Object Output
- Reassigning variable
btonullafterb = a;does not change the original object referenced bya. - Therefore,
System.out.println(a);also outputs "whoot".
Method Parameter Passing
- In Java, object references are passed by value; modifying the parameter does not change the original object outside the method.
- In
mystery(Object one, Object two), settingone = two;only changesonelocally.out.println(one);outputs the value oftwo, which isn't affected.
Method Behavior with Primitive Types
- For
mystery2(int one, int two), even thoughoneis set totwo, it does not change the values ofzorwdue to primitive type passing. - Consequently,
System.out.println(z + " " + w);retains the original values.
Array References in Methods
- In
mystery3(Object[] ray), assigningrayto a new array or object does not affect the original reference outside the method. - The modification of
raywithinmystery3is local.
Final Output Considerations
- Outputs do not reflect changes in method parameters or reassigned objects in the main context.
- Understanding memory allocation and how Java handles object references is crucial to predict outputs accurately.
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Description
Test your knowledge on Java object references, variable reassignment, and method parameter passing. This quiz covers the critical concepts of memory locations, reference behavior, and the distinction between object and primitive type handling in Java.
