Ionization Energy Comparison: S vs P

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Questions and Answers

What explains the higher first ionization energy of sulfur compared to phosphorus?

  • The presence of a full outer orbital in sulfur
  • The stability of a half-filled orbital in sulfur (correct)
  • Sulfur has a higher atomic mass than phosphorus
  • Phosphorus has more protons, attracting the electron more strongly

From which orbital is the first valence electron removed in the sulfur atom?

  • 3s orbital
  • 2p orbital
  • 3p orbital (correct)
  • 1s orbital

Why is a half-filled 3p orbital more stable than a partially filled 3p orbital in phosphorus?

  • It leads to a larger atomic radius.
  • It allows for greater electron repulsion.
  • It has lower energy due to symmetry and exchange energy. (correct)
  • It results in maximum electron pairing.

What is the primary reason more energy is needed to remove the first electron from sulfur compared to phosphorus?

<p>Sulfur's half-filled 3p orbital is more stable. (C)</p> Signup and view all the answers

Which statement about the ionization energies of sulfur and phosphorus is accurate?

<p>Sulfur has a higher ionization energy than phosphorus. (A)</p> Signup and view all the answers

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Study Notes

Ionization Energies of Sulfur and Phosphorus

  • Sulfur (S) has a higher first ionization energy compared to phosphorus (P).
  • The difference in ionization energy can be attributed to the stability of electron configurations.
  • The first valence electron from sulfur is extracted from a half-filled 3p orbital.
  • In contrast, the first valence electron from phosphorus is removed from a partially filled 3p orbital.
  • A half-filled orbital, such as that of sulfur, exhibits greater stability due to electron pairing effects and symmetry.
  • This enhanced stability of sulfur's half-filled 3p orbital necessitates greater energy to remove its first valence electron.
  • Consequently, removing an electron from sulfur requires more energy than from phosphorus due to these stability differences.

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