Hfst 7: Interne weerstand, serie en parallelle netwerke

<p>Dieselfde stroom vloei deur elke weerstand</p> Signup and view all the answers

<p>Dieselfde spanning val oor elke weerstand</p> Signup and view all the answers

<p>V = IR</p> Signup and view all the answers

<p>1/R_tot = 1/R₁ + 1/R₂ + ...</p> Signup and view all the answers

<p>V_las = ε - Ir</p> Signup and view all the answers

<p>P = VI</p> Signup and view all the answers

<p>Dit verlaag die uitgangspanning</p> Signup and view all the answers

<p>Die battery het 'n interne weerstand</p> Signup and view all the answers

<p>$V = \frac{\varepsilon}{1 + \frac{r}{R}}$</p> Signup and view all the answers

<p>Die potensiaalverskil oor elke komponent is dieselfde.</p> Signup and view all the answers

<p>Die maksimum potensiaalverskil (spanning) wat 'n battery kan lewer wanneer geen stroom deur dit vloei nie.</p> Signup and view all the answers

<p>Die werklike spanning is altyd minder as die emk as gevolg van die interne weerstand.</p> Signup and view all the answers

<p>Die stroom deur elke komponent is dieselfde.</p> Signup and view all the answers

<p>$R_{eq} = \frac{1}{\frac{1}{R_1} + \frac{1}{R_2} + \cdots + \frac{1}{R_n}}$</p> Signup and view all the answers

<p>Beide (b) en (c)</p> Signup and view all the answers

<p>Die spanning oor elke tak is dieselfde as die spanning oor die bron.</p> Signup and view all the answers

<p>Dit verminder die werklike uitgangspanning.</p> Signup and view all the answers

<p>$R_{total} = R_1 + R_2 + \ldots$</p> Signup and view all the answers

<p>Dit sal die battery se werkverrigting verswak.</p> Signup and view all the answers

<p>Enige van die bogenoemde formules kan gebruik word, afhangende van die gegewe hoeveelhede.</p> Signup and view all the answers

<p>$R_{eq} = \frac{1}{\frac{1}{R_1} + \frac{1}{R_2} + \ldots}$</p> Signup and view all the answers

<p>Die spanning wat deur 'n energiebron in 'n stroombaan gelewer word.</p> Signup and view all the answers

<p>$V = IR$</p> Signup and view all the answers

<p>$V_{las} = \epsilon - Ir$</p> Signup and view all the answers

<p>$R_t = R_1 + R_2 + ... + R_n$</p> Signup and view all the answers

<p>Dit sal die werklike uitgangspanning van die battery verlaag.</p> Signup and view all the answers

<p>Die maksimum spanning wat 'n battery kan lewer wanneer daar geen stroom vloei nie.</p> Signup and view all the answers

<p>Alle bogenoemde formules</p> Signup and view all the answers

<p>$V_\text{load} = \varepsilon - Ir$</p> Signup and view all the answers

<p>Die spanning oor elke parallelgekoppelde weerstand is dieselfde as die totale spanning oor die kring.</p> Signup and view all the answers

<p>$1/R_\text{eq} = 1/R_1 + 1/R_2 + ... + 1/R_n$</p> Signup and view all the answers

<p>Dit sal die werklike uitgangspanning verlaag.</p> Signup and view all the answers

<p>Omdat dit 'n interne weerstand het.</p> Signup and view all the answers

<p>Die spanning oor elke komponent is dieselfde.</p> Signup and view all the answers

<p>Die emk is altyd groter as die werklike spanning.</p> Signup and view all the answers

<p>Dit sal die spanning oor die las verlaag.</p> Signup and view all the answers

<p>$R_{ekw} = \frac{1}{\frac{1}{R_1} + \frac{1}{R_2} + \ldots + \frac{1}{R_n}}$</p> Signup and view all the answers

<p>$\epsilon = V_{bat} - IR_{int}$</p> Signup and view all the answers

<p>Die som van die strawwe deur elke komponent is gelyk aan die totale stroom.</p> Signup and view all the answers

<p>$V_{las} = \epsilon - IR_{int}$</p> Signup and view all the answers

<p>Die battery het 'n interne weerstand.</p> Signup and view all the answers

<p>$R_{tot} = \frac{1}{\frac{1}{R_1} + \frac{1}{R_2} + \ldots + \frac{1}{R_n}}$</p> Signup and view all the answers