Integration by Parts Explained
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Questions and Answers

When applying integration by parts to $\int x^2 cos(x) dx$, what is the correct choice for u and $\frac{dv}{dx}$ based on LIATE?

  • $u = x^2, \frac{dv}{dx} = cos(x)$ (correct)
  • $u = cos(x), \frac{dv}{dx} = x^2$
  • $u = sin(x), \frac{dv}{dx} = x^2$
  • $u = x, \frac{dv}{dx} = x cos(x)$

After applying integration by parts once to $\int x^2 cos(x) dx$, which integral remains to be solved?

  • $\int sin(x) dx$
  • $\int 2x cos(x) dx$
  • $\int 2x sin(x) dx$ (correct)
  • $\int x^2 sin(x) dx$

To solve $\int x \sin x , dx$ using integration by parts, which of the following substitutions is most appropriate?

  • $u = x, dv = \sin x \, dx$ (correct)
  • $u = 1, dv = x \sin x \, dx$
  • $u = \sin x, dv = x \, dx$
  • $u = x \sin x, dv = dx$

What is the correct first step in evaluating the integral $\int x^3 \ln x , dx$ using integration by parts?

<p>Let $u = \ln x$ and $dv = x^3 , dx$ (B)</p> Signup and view all the answers

If $\int \ln(x) , dx = x\ln(x) - x + C$, what is the correct expression for $\int \ln^2(x) , dx$ after applying integration by parts once?

<p>$x \ln^2(x) - 2 \int \ln(x) , dx$ (A)</p> Signup and view all the answers

Which of the following integrals is correctly evaluated, assuming the constant of integration is omitted?

<p>$\int tan(x) dx = ln |sec(x)|$ (B)</p> Signup and view all the answers

Using the integration by parts formula, $\int u dv = uv - \int v du$, how should you select 'u' in the integral $\int x sin(x) dx$ according to the LIATE rule?

<p>u = x (C)</p> Signup and view all the answers

The formula for integration by parts is derived from which rule of differentiation?

<p>The product rule (B)</p> Signup and view all the answers

When applying integration by parts, the goal is to select 'u' and 'dv' such that:

<p>$\int v du$ is easier to evaluate, while still being correct (B)</p> Signup and view all the answers

According to the LIATE rule, which function should be prioritized as 'u' when integrating $\int x ln(x) dx$?

<p>ln(x) because Logarithmic functions come first (A)</p> Signup and view all the answers

Which of the following statements best describes a limitation of the integration by parts technique?

<p>It is ineffective when both functions in the integrand become more complicated after differentiation or integration. (D)</p> Signup and view all the answers

What is the correct application of the integration by parts formula to the integral $\int x e^x dx$?

<p>$xe^x - \int e^x dx$ (A)</p> Signup and view all the answers

What would be the next step to solve $\int x e^x dx$ after applying integration by parts and getting $xe^x - \int e^x dx$ ?

<p>Solve $\int e^x dx$ directly. (C)</p> Signup and view all the answers

When applying integration by parts, how does the LIATE rule guide the selection of $u$ and $dv$?

<p>It suggests choosing $u$ based on the order: Logarithmic, Inverse trigonometric, Algebraic, Trigonometric, Exponential, prioritizing functions that simplify when differentiated. (B)</p> Signup and view all the answers

For the integral $\int x \cos(x) dx$, what are the appropriate choices for $u$ and $dv$ when using integration by parts?

<p>$u = x$, $dv = \cos(x) dx$ (A)</p> Signup and view all the answers

What is the correct setup for integration by parts applied to $\int x^3 \ln(x) dx$?

<p>$u = \ln(x), dv = x^3 dx$ (A)</p> Signup and view all the answers

Given $\int x^2 e^{2x} dx$, what is the result after the first application of integration by parts?

<p>$\frac{1}{2}x^2e^{2x} - \int xe^{2x} dx$ (A)</p> Signup and view all the answers

In evaluating $\int x^2 e^{2x} dx$, after applying integration by parts twice, what is the correct form of the final integral (before adding the constant of integration)?

<p>$\frac{1}{2}x^2e^{2x}-\frac{1}{2}xe^{2x} - \frac{1}{4}e^{2x}$ (D)</p> Signup and view all the answers

To solve $\int x^2 \cos(x) dx$, how many times would you typically need to apply integration by parts?

<p>Twice (B)</p> Signup and view all the answers

What is the primary reason for rewriting $\int x^3 \ln(x) dx$ as $\int \ln(x) \cdot x^3 dx$ before applying integration by parts?

<p>To align with the LIATE rule, placing the logarithmic function in the 'u' position. (B)</p> Signup and view all the answers

If you incorrectly choose $u$ and $dv$ when applying integration by parts, what is the most likely outcome?

<p>The resulting integral will be more complex than the original. (B)</p> Signup and view all the answers

Flashcards

Integration by Parts

A technique to integrate the product of two functions. It reverses the product rule of differentiation.

LIATE

A guideline for choosing 'u' in integration by parts: Logarithmic, Inverse trigonometric, Algebraic, Trigonometric, Exponential.

Integration by Parts Formula

∫u dv = uv - ∫v du

Integral of ln(x)

∫ ln(x) dx = xln(x) - x + C

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What is the LIATE rule used for?

To determine how to approach integration by parts problems.

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∫ u^(-n) dx

The integral of u^(-n) with respect to x is (u^(-n+1))/(1-n) + c, where c is the constant of integration.

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∫ u^n dx

The integral of u^n with respect to x is (u^(n+1))/(n+1) + c, where c is the constant of integration.

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∫ e^u u' dx

The integral of e^u * u' with respect to x is e^u + c, where c is the constant of integration.

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∫ (sin u) u' dx

The integral of (sin u) * u' with respect to x is -cos u + c, where c is the constant of integration.

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∫ tan x dx

The integral of tan x with respect to x is ln |sec x| + c, where c is the constant of integration.

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∫ cot x dx

The integral of cot x with respect to x is ln |sin x| + c, where c is the constant of integration.

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LIATE Rule

LIATE is an acronym that guides in choosing 'u' when using integration by parts: Logarithmic, Inverse Trigonometric, Algebraic, Trigonometric, Exponential.

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Goal of Integration by Parts

In $\int u \frac{dv}{dx} dx = uv - \int v \frac{du}{dx} dx$, it's beneficial if $\int v \frac{du}{dx} dx $ is simpler than $ \int u \frac{dv}{dx} dx$.

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Example of Choosing 'u'

For $\int xe^x dx$, choose u = x and dv = $e^x$ dx because the derivative of x simplifies to 1.

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Applying LIATE

Given $\int x cos x dx$, following LIATE, u = x (algebraic) and dv = cos x dx (trigonometric).

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Rearranging with LIATE

Rewrite the integral as $\int ln x \cdot x^3 dx$ to align with LIATE (Logarithmic before Algebraic).

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Iterative Integration by Parts

When integrating $\int x^2e^{2x} dx$ multiple times, apply integration by parts iteratively until the algebraic part is fully differentiated.

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Nested Integration by Parts

After initial integration by parts, you may need to apply it again on the new integral formed.

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Study Notes

  • Integration by parts is a technique used to integrate expressions containing two functions when one is not the derivative of the other.

Integration by Parts Formula

  • The integration by parts formula is: ∫u dv/dx dx = uv - ∫v du/dx dx
  • The formula can be written as: ∫u dv = uv - ∫v du
  • The integrand contains two functions: u and dv/dx
  • This method is helpful when ∫v du/dx is easier to solve than ∫u dv/dx.

Applying the Formula

  • Using the product rule of differentiation: d(uv)/dx = u(dv/dx) + v(du/dx)
  • Integrate both sides with respect to x: ∫ u(dv/dx) dx = uv - ∫ v(du/dx) dx
  • When using the formula, the functions u and dv/dx can be Logarithmic, Inverse trigonometric, Algebraic, Trigonometric, or Exponential.
  • To select 'u', follow the order LIATE (Logarithmic, Inverse trigonometric, Algebraic, Trigonometric, Exponential).

Examples

  • Integrand consists of Exponential (e^x) and Algebraic (x) functions meaning Algebraic functions should come first.
  • Substituting the results into the formula: ∫ u dv/dx dx = uv - ∫ v du/dx dx
  • Order matters so ensure you double check which comes first

Key Points

  • Formula: ∫ ln x dx = x ln x - x + c for integration of ln x when x > 0
  • Apply the formula to integrate the product of two functions
  • Remember to check yourself and that the formula is useful.

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Description

Learn about integration by parts, a technique for integrating expressions with two functions, where one isn't the derivative of the other. Understand the formula ∫u dv = uv - ∫v du and how to apply it effectively. Includes how to choose 'u' function by using the LIATE rule.

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