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Questions and Answers
What is the formula used to calculate the energy stored in an inductor?
What is the formula used to calculate the energy stored in an inductor?
- $E = LI^2$
- $E = \frac{1}{2}LI^2$ (correct)
- $E = \frac{1}{2}C(V^2)$
- $E = VI$
If a 50 mH coil carries a current of 2 amperes, what is the inductance in henries?
If a 50 mH coil carries a current of 2 amperes, what is the inductance in henries?
- 0.5 H
- 0.05 H (correct)
- 50 H
- 5 H
What is the energy stored in a 50 mH coil with a current of 2 amperes?
What is the energy stored in a 50 mH coil with a current of 2 amperes?
- 0.05 Joules
- 0.5 Joules (correct)
- 0.1 Joules
- 1 Joule
Which of the following values represents an incorrect conversion of inductance for the given coil?
Which of the following values represents an incorrect conversion of inductance for the given coil?
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In the calculation of energy stored in a coil, which component does not influence the result?
In the calculation of energy stored in a coil, which component does not influence the result?
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Study Notes
Energy Stored in an Inductor
- The energy stored in an inductor is calculated using the formula: Energy (E) = 1/2 * L * I^2
- E represents Energy in Joules (J)
- L represents Inductance in Henries (H)
- I represents Current in Amperes (A)
Inductance Calculation
- A 50 mH coil is equivalent to 0.05 Henries (H).
- 1 mH (millihenry) = 0.001 H (henry)
Energy Stored in a 50 mH Coil
- The energy stored in a 50 mH coil carrying a current of 2 amperes can be calculated using the formula:
- E = 1/2 * 0.05 H * (2 A)^2
- E = 0.1 Joules (J)
Incorrect Inductance Conversion
- The text does not provide specific values for inductance conversions. It simply asks which value is incorrect.
- To determine the incorrect value, you would need to be provided with a set of options.
Components Not Affecting Energy Stored
- The energy stored in a coil depends solely on the values of Inductance (L) and Current (I).
- Other components, such as resistance, do not influence the energy stored in the coil.
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