5 Questions
What are the vertical components of the forces acting on the horizontal beam?
R sin θ and T sin 53.0°
What are the horizontal components of the forces acting on the horizontal beam?
R cos θ and T cos 53.0°
What are the magnitudes of the forces acting vertically on the beam?
200 N and 600 N
What are the distances from the pivot point to the locations where the forces act on the beam?
2.00 m and 4.00 m
What is the purpose of applying the conditions of equilibrium to this problem?
To obtain three equations to solve for the unknowns
Study Notes
Horizontal Beam Example
- Forces can be broken down into components in a free-body diagram, which includes: • R sin θ (vertical component) • R cos θ (horizontal component) • T sin 53.0° (vertical component) • T cos 53.0° (horizontal component)
- To achieve equilibrium, two conditions must be met, resulting in three equations: • The sum of the vertical forces equals zero • The sum of the horizontal forces equals zero • The sum of the torques equals zero
- The given values in the problem are: • 200 N (force) • 2.00 m (distance) • 600 N (force) • 4.00 m (distance)
Solve for the unknown forces and moments in a horizontal beam problem, applying the conditions of equilibrium and resolving forces into components.
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