Horizontal Beam Equilibrium

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Questions and Answers

What are the vertical components of the forces acting on the horizontal beam?

R sin θ and T sin 53.0°

What are the horizontal components of the forces acting on the horizontal beam?

R cos θ and T cos 53.0°

What are the magnitudes of the forces acting vertically on the beam?

200 N and 600 N

What are the distances from the pivot point to the locations where the forces act on the beam?

<p>2.00 m and 4.00 m</p> Signup and view all the answers

What is the purpose of applying the conditions of equilibrium to this problem?

<p>To obtain three equations to solve for the unknowns</p> Signup and view all the answers

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Study Notes

Horizontal Beam Example

  • Forces can be broken down into components in a free-body diagram, which includes: • R sin θ (vertical component) • R cos θ (horizontal component) • T sin 53.0° (vertical component) • T cos 53.0° (horizontal component)
  • To achieve equilibrium, two conditions must be met, resulting in three equations: • The sum of the vertical forces equals zero • The sum of the horizontal forces equals zero • The sum of the torques equals zero
  • The given values in the problem are: • 200 N (force) • 2.00 m (distance) • 600 N (force) • 4.00 m (distance)

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