Honors Algebra 2: Transformation of Functions

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Questions and Answers

All functions have a reciprocal that is also a function.

True (A)

The reciprocal for a function is a reflection over the y and x axis.

False (B)

If the original function has a root, then the reciprocal function will have a vertical asymptote.

True (A)

Invariant points are used to graph reciprocal functions and happen when the point does not change after the transformation.

<p>True (A)</p> Signup and view all the answers

If a function is a line, then its reciprocal is also a line.

<p>False (B)</p> Signup and view all the answers

All functions have an inverse that is also a function.

<p>False (B)</p> Signup and view all the answers

The inverse for a function is a reflection over the y and x axis.

<p>False (B)</p> Signup and view all the answers

If the domain of a function is all real numbers except 5, then the range of its inverse is all real numbers except 5.

<p>True (A)</p> Signup and view all the answers

True or false.

<p>True (A)</p> Signup and view all the answers

True or false.

<p>True (A)</p> Signup and view all the answers

True or false.

<p>False (B)</p> Signup and view all the answers

True or false.

<p>False (B)</p> Signup and view all the answers

True or false.

<p>True (A)</p> Signup and view all the answers

True or false.

<p>True (A)</p> Signup and view all the answers

True or false.

<p>False (B)</p> Signup and view all the answers

True or false.

<p>False (B)</p> Signup and view all the answers

When algebraically solving f(-x), what do you do?

<p>Plug in -x</p> Signup and view all the answers

When algebraically solving -f(x), what do you do?

<p>-(entire expression)</p> Signup and view all the answers

When algebraically solving -f(-x), what do you do?

<p>Plug in -x and then -(entire expression)</p> Signup and view all the answers

When algebraically solving 1/f(x), what do you do?

<p>1/entire expression</p> Signup and view all the answers

When algebraically solving f^-1(x), what do you do?

<p>Switch x and y, and then solve for y.</p> Signup and view all the answers

When transforming a table of points for f(-x), what do you do?

<p>(-x,y)</p> Signup and view all the answers

When transforming a table of points for -f(x), what do you do?

<p>(x,-y)</p> Signup and view all the answers

When transforming a table of points for -f(-x), what do you do?

<p>(-x,-y)</p> Signup and view all the answers

When transforming a table of points for 1/f(x), what do you do?

<p>Take the reciprocal of the y's and find the vertical asymptote.</p> Signup and view all the answers

When transforming a table of points for f^-1(x), what do you do?

<p>(y,x)</p> Signup and view all the answers

When graphically transforming f(-x), what do you do?

<p>Reflect over the y-axis</p> Signup and view all the answers

When graphically transforming -f(x), what do you do?

<p>Reflect over the x-axis</p> Signup and view all the answers

When graphically transforming -f(-x), what do you do?

<p>Reflect over the x-axis and the y-axis.</p> Signup and view all the answers

When graphically transforming 1/f(x), what do you do?

<p>Transform x intercepts into asymptotes; little y's become big y's; big y's become little y's; maxes become mins or mins become maxes.</p> Signup and view all the answers

When graphically transforming f^-1(x), what do you do?

<p>Reflect over y=x; x intercepts become y intercepts; y intercepts become x intercepts; points on y=x don't change.</p> Signup and view all the answers

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Study Notes

Transformation of Functions

  • All functions possess a reciprocal function, which is itself also a function.
  • The assertion that the reciprocal is a reflection over both the y and x axes is incorrect.
  • If an original function has a root, its reciprocal function will have a vertical asymptote.
  • Invariant points, where points remain unchanged during transformation, are crucial for graphing reciprocal functions.
  • Reciprocal functions differ in nature: a linear function’s reciprocal is not necessarily linear; similar holds for quadratics and rational functions.
  • Not all functions have an inverse that is also a function.
  • The notion that the inverse is a reflection over the y and x axes is false.
  • A function's inverse retains the domain and range relationship—in this case, if the domain excludes a number, so will the range of its inverse.
  • The vertical line test is not a valid method to determine if a function has an inverse that is itself a function.
  • A function's inverse also does not follow the same type (linear, quadratic) as the original function.
  • Standard processes for transformations include algebraic methods of substituting and adjusting function expressions.

Algebraic Transformation Techniques

  • To solve for f(-x), substitute -x into the function.
  • To solve for -f(x), apply the negative to the entire function expression.
  • For -f(-x), first substitute -x and then negate the entire expression.
  • When solving 1/f(x), take the reciprocal of the entire function's expression.
  • To find the inverse f^-1(x), switch the variables x and y and resolve for y.

Point Transformation for Functions

  • Transforming f(-x) alters the point coordinates to (-x, y).
  • Transforming -f(x) changes the points to (x, -y).
  • For -f(-x), points are transformed to (-x, -y).
  • The process for 1/f(x) involves taking the reciprocal of the y-values and determining the vertical asymptote when transforming point tables.
  • When deriving f^-1(x), swap the x and y values of the points.

Graphical Transformation Techniques

  • Graphically transforming f(-x) requires reflecting the function over the y-axis.
  • Reflecting the function -f(x) takes place over the x-axis.
  • For -f(-x), the reflection occurs over both the x and y axes.
  • Transforming 1/f(x) involves a series of changes: x-intercepts become asymptotes, smaller y-values switch with larger ones, and local maxima become minima (and vice versa).
  • For graphing f^-1(x), perform reflections over the line y=x, and swap intercepts accordingly while leaving points on the line y=x unchanged.

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