Heron's Formula in Geometry

$A = \frac{1}{2}ab\sin(C)$

$A = \sqrt{s(s-a)(s-b)(s-c)}$ (correct)

$A = \frac{1}{4}\sqrt{(a^2 + b^2 + c^2)^2 - 2(a^4 + b^4 + c^4)}$

$A = \frac{1}{2}bh$

$s = 21$

$s = 26$

$s = 25$ (correct)

$s = 20$

$A = 8$

$A = 10$

$A = 12$

$A = 6$ (correct)

<p>'s' represents the semiperimeter of the triangle</p> Signup and view all the answers

<p>$A=120$</p> Signup and view all the answers