HCL Lamps in Analytical Chemistry
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Questions and Answers

What is the purpose of modulating the radiation source in atomic absorption spectroscopy?

  • To discriminate between the radiation from the hollow cathode lamp and the radiation given off by excited atoms in the flame (correct)
  • To increase the intensity of the radiation
  • To improve the sensitivity of the instrument
  • To reduce the noise from the detector
  • What is the main purpose of using a chopper in atomic absorption spectroscopy?

  • To increase the intensity of the radiation
  • To modulate the radiation source (correct)
  • To reduce the noise from the detector
  • To improve the sensitivity of the instrument
  • What type of interference is more common in atomic absorption spectroscopy?

  • Spectral interference
  • Chemical interference (correct)
  • Instrumental interference
  • Physical interference
  • What is the effect of formation of low volatility compounds in atomic absorption spectroscopy?

    <p>Decrease in absorbance signal</p> Signup and view all the answers

    How can the effects of low volatility compounds be minimized in atomic absorption spectroscopy?

    <p>By using a higher flame temperature</p> Signup and view all the answers

    What is the purpose of adding releasing agents in atomic absorption spectroscopy?

    <p>To prevent the analyte from reacting with the interferant</p> Signup and view all the answers

    What type of complex is formed between Mg and Al in atomic absorption spectroscopy?

    <p>Heat stable complex</p> Signup and view all the answers

    What is the effect of chopper modulation on the detector signal in atomic absorption spectroscopy?

    <p>It creates an ac signal</p> Signup and view all the answers

    What is the purpose of using a mechanical chopper in atomic absorption spectroscopy?

    <p>To modulate the radiation source</p> Signup and view all the answers

    What type of radiation is given off by excited atoms in the flame in atomic absorption spectroscopy?

    <p>Visible radiation</p> Signup and view all the answers

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