Harmonic Motion and Spring Stiffness Calculation
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Questions and Answers

If the cart's mass is increased while maintaining the same frequency, how will this affect the stiffness of the spring?

  • The stiffness will increase.
  • The stiffness will remain unchanged.
  • It will depend on the amplitude of oscillation.
  • The stiffness will decrease. (correct)
  • Calculate the stiffness of the spring using the given mass and frequency. What is the stiffness of the spring?

  • 32.23 N/m
  • 22.05 N/m
  • 16.28 N/m (correct)
  • 8.14 N/m
  • Which parameter is directly related to the frequency of oscillation in SHM?

  • Damping coefficient
  • Stiffness of the spring (correct)
  • Amplitude of the motion
  • Mass of the cart
  • What unit is the stiffness of a spring commonly expressed in?

    <p>Newtons per meter</p> Signup and view all the answers

    Study Notes

    Harmonic Motion of a Cart Attached to a Spring

    • A 5.70 kg cart attached to a spring experiences simple harmonic motion (SHM).
    • The frequency of oscillation is 2.61 Hz.
    • The goal is to determine the spring stiffness (k).

    Relationship Between Frequency and Spring Stiffness

    • The frequency (f) of a spring-mass system undergoing SHM is related to the spring stiffness (k) and the mass (m) by the following equation:
      • f = (1 / 2π) * √(k / m)

    Solving for Spring Stiffness (k)

    • Rearranging the equation to solve for k:
      • k = (4π² * m * f²)

    Calculation

    • Substituting the given values:
      • m = 5.70 kg
      • f = 2.61 Hz
    • Performing the calculation:
      • k = (4 * π² * 5.70 kg * (2.61 Hz)²)
    • Result:
      • k ≈ 400 N/m (approximately)

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    Description

    This quiz focuses on the principles of simple harmonic motion (SHM) of a cart attached to a spring. You will learn how to calculate the spring stiffness using the relationship between frequency and mass. Test your understanding of SHM by solving for spring stiffness with given values.

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