Hacking Smartcards and Microcontrollers: Noninvasive Attacks
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Questions and Answers

What was the purpose of the Clipper chip designed by the U.S. government in 1993?

  • To enable the government to decrypt any encrypted traffic (correct)
  • To create a more secure form of RAM
  • To enhance the speed of data encryption
  • To allow users to encrypt data securely

In the context of smartcards, what is stored in the EEPROM?

  • The Law Enforcement Access Field (LEAF)
  • The ciphertext
  • Key material (correct)
  • The user-supplied key

What problem do EEPROM-based devices face when erasing information?

  • High voltage requirement for erasure (correct)
  • Low sensitivity to voltage changes
  • Inability to store volatile information
  • Quick depletion of stored data

How did attackers manipulate early smartcards in pay-TV systems?

<p>By tampering with the programming voltage connection on the card (B)</p> Signup and view all the answers

Which operation does Capstone include along with public key encryption and digital signatures?

<p>Cipher instruction search attack prevention (A)</p> Signup and view all the answers

What key information does Clipper return along with the ciphertext when encrypting data?

<p>User-supplied key encrypted under a known government key (A)</p> Signup and view all the answers

What role does the Law Enforcement Access Field (LEAF) play in Clipper's encryption process?

<p>It contains the encrypted user-supplied key (C)</p> Signup and view all the answers

Why is it a concern if an attacker can remove the charge stored in EEPROM memory cells?

<p>The information stored becomes vulnerable (B)</p> Signup and view all the answers

How did attackers prevent certain channels from being deactivated in pay-TV systems?

<p>By tampering with broadcast signals (D)</p> Signup and view all the answers

What was a common way that subscribers manipulated their smartcards in pay-TV systems to prevent deactivation of channels they didn't pay for?

<p>Clamping the card inside the decoder using a diode (B)</p> Signup and view all the answers

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