Gas Stoichiometry in Glucose Combustion

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Questions and Answers

If 0.500 moles of glucose are combusted, what chemical amount (in moles) of water is produced?

12.0 moles
3.00 moles (correct)
0.500 moles
6.00 moles

What conversion is necessary to calculate the mass of oxygen consumed during the combustion of 0.325 moles of glucose?

Convert moles of glucose to mass of glucose, then moles of oxygen to mass of oxygen.
Convert moles of glucose to moles of water, then moles of water to mass of oxygen.
Convert moles of glucose to mass of carbon dioxide, then convert to mass of oxygen.
Convert moles of glucose to moles of oxygen, then moles of oxygen to mass of oxygen. (correct)

When calculating the volume of carbon dioxide produced from the combustion of 50.0 g of glucose, which of the following is NOT a necessary step?

Using the ideal gas law to find volume of carbon dioxide.
Converting mass of glucose to moles of glucose.
Converting moles of carbon dioxide to mass of carbon dioxide. (correct)
Converting moles of glucose to moles of carbon dioxide.

If 275g of ethane (C2H6) is burned at Standard Temperature and Pressure, which of the following conversion steps will be used to find the volume of O2 required?

<p>Convert mass of ethane to moles of ethane, then convert moles of ethane to moles of oxygen, then use molar volume to find volume of oxygen. (A)</p> Signup and view all the answers

When calculating the volume of CO2 produced by the combustion of butane at a pressure of 98.0 kPa and a temperature of 90.0°C, why is the ideal gas law (PV=nRT) used?

<p>Because the conditions are not at STP or SATP. (B)</p> Signup and view all the answers

Flashcards

Moles to Moles Calculation

The balanced chemical equation and the mole ratios are used to determine the moles of products produced from a specific amount of reactant.

Mass to Moles Calculation

The molar mass of the reactant is used to convert the mass of the reactant into moles. Then, the mole ratio from the balanced chemical equation is used to convert moles of reactant to moles of product.

Moles to Mass Calculation

The molar mass of the product is used to convert moles of product to grams. The mole ratio from the balanced chemical equation is used to convert moles of reactant to moles of product.

Molar Volume at STP

Gas stoichiometry problems involving STP (Standard Temperature and Pressure) can use the molar volume (22.4 L/mol) to convert between moles of gas and volume of gas.

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Ideal Gas Law

Gas stoichiometry problems involving non-STP conditions can use the ideal gas law (PV = nRT) to convert between moles of gas and volume of gas.

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Study Notes

Gas Stoichiometry

Glucose combustion is a part of cellular respiration
Stoichiometry calculations involve balanced equations, coefficients, molar ratios, and molar masses

Calculating Moles of Water Produced

Given: 0.500 moles of glucose
Balanced chemical equation is needed to determine the molar ratio between glucose and water
Convert moles of glucose to moles of water using the molar ratio from the balanced equation

Calculating Mass of Oxygen Consumed

Given: 0.325 moles of glucose
Convert glucose to moles of oxygen using the molar ratio
Convert moles of oxygen to mass of oxygen using the molar mass of oxygen

Calculating Mass of Carbon Dioxide Produced

Given: 50.0 g of glucose
Convert mass of glucose to moles of glucose using molar mass
Convert moles of glucose to moles of carbon dioxide using the molar ratio
Convert moles of carbon dioxide to mass of carbon dioxide using molar mass

Calculating Volume of Carbon Dioxide Produced

Given: 50.0 g of glucose
Convert mass of glucose to moles of glucose
Convert moles of glucose into moles of carbon dioxide using the molar ratio
Use the ideal gas law (PV = nRT) to calculate the volume of carbon dioxide
The standard temperature and pressure (STP) or standard ambient temperature and pressure (SATP) are required when using molar volume

Gas Stoichiometry Fundamentals

Gas volume can be a starting point or end point in stoichiometry calculations
Gas stoichiometry requires gas volumes (in liters), pressure (in kPa), and temperature (in Kelvin) for calculation

Example: Ethane Combustion

Given: 275g of ethane
Calculate moles of ethane, moles of O2 required for complete combustion using the balanced equation
At STP, calculate the volume of O2 using molar volume

Example: Butane Combustion

Given: 275g of butane, pressure of 98.0 kPa and temperature of 90.0°C
Calculate moles of butane, moles of CO2 produced
Calculate volume of CO2 using the ideal gas law (PV = nRT)

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Description

This quiz focuses on gas stoichiometry related to the combustion of glucose, a crucial process in cellular respiration. Participants will learn to calculate moles, masses, and volumes of substances involved in the reactions. Knowledge of balanced equations and molar ratios is required for solving the problems effectively.