Gas Stoichiometry in Glucose Combustion
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Questions and Answers

If 0.500 moles of glucose are combusted, what chemical amount (in moles) of water is produced?

  • 12.0 moles
  • 3.00 moles (correct)
  • 0.500 moles
  • 6.00 moles
  • What conversion is necessary to calculate the mass of oxygen consumed during the combustion of 0.325 moles of glucose?

  • Convert moles of glucose to mass of glucose, then moles of oxygen to mass of oxygen.
  • Convert moles of glucose to moles of water, then moles of water to mass of oxygen.
  • Convert moles of glucose to mass of carbon dioxide, then convert to mass of oxygen.
  • Convert moles of glucose to moles of oxygen, then moles of oxygen to mass of oxygen. (correct)
  • When calculating the volume of carbon dioxide produced from the combustion of 50.0 g of glucose, which of the following is NOT a necessary step?

  • Using the ideal gas law to find volume of carbon dioxide.
  • Converting mass of glucose to moles of glucose.
  • Converting moles of carbon dioxide to mass of carbon dioxide. (correct)
  • Converting moles of glucose to moles of carbon dioxide.
  • If 275g of ethane (C2H6) is burned at Standard Temperature and Pressure, which of the following conversion steps will be used to find the volume of O2 required?

    <p>Convert mass of ethane to moles of ethane, then convert moles of ethane to moles of oxygen, then use molar volume to find volume of oxygen.</p> Signup and view all the answers

    When calculating the volume of CO2 produced by the combustion of butane at a pressure of 98.0 kPa and a temperature of 90.0°C, why is the ideal gas law (PV=nRT) used?

    <p>Because the conditions are not at STP or SATP.</p> Signup and view all the answers

    Study Notes

    Gas Stoichiometry

    • Glucose combustion is a part of cellular respiration
    • Stoichiometry calculations involve balanced equations, coefficients, molar ratios, and molar masses

    Calculating Moles of Water Produced

    • Given: 0.500 moles of glucose
    • Balanced chemical equation is needed to determine the molar ratio between glucose and water
    • Convert moles of glucose to moles of water using the molar ratio from the balanced equation

    Calculating Mass of Oxygen Consumed

    • Given: 0.325 moles of glucose
    • Convert glucose to moles of oxygen using the molar ratio
    • Convert moles of oxygen to mass of oxygen using the molar mass of oxygen

    Calculating Mass of Carbon Dioxide Produced

    • Given: 50.0 g of glucose
    • Convert mass of glucose to moles of glucose using molar mass
    • Convert moles of glucose to moles of carbon dioxide using the molar ratio
    • Convert moles of carbon dioxide to mass of carbon dioxide using molar mass

    Calculating Volume of Carbon Dioxide Produced

    • Given: 50.0 g of glucose
    • Convert mass of glucose to moles of glucose
    • Convert moles of glucose into moles of carbon dioxide using the molar ratio
    • Use the ideal gas law (PV = nRT) to calculate the volume of carbon dioxide
    • The standard temperature and pressure (STP) or standard ambient temperature and pressure (SATP) are required when using molar volume

    Gas Stoichiometry Fundamentals

    • Gas volume can be a starting point or end point in stoichiometry calculations
    • Gas stoichiometry requires gas volumes (in liters), pressure (in kPa), and temperature (in Kelvin) for calculation

    Example: Ethane Combustion

    • Given: 275g of ethane
    • Calculate moles of ethane, moles of O2 required for complete combustion using the balanced equation
    • At STP, calculate the volume of O2 using molar volume

    Example: Butane Combustion

    • Given: 275g of butane, pressure of 98.0 kPa and temperature of 90.0°C
    • Calculate moles of butane, moles of CO2 produced
    • Calculate volume of CO2 using the ideal gas law (PV = nRT)

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    Description

    This quiz focuses on gas stoichiometry related to the combustion of glucose, a crucial process in cellular respiration. Participants will learn to calculate moles, masses, and volumes of substances involved in the reactions. Knowledge of balanced equations and molar ratios is required for solving the problems effectively.

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