Frequency Distribution Tables Explained

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Questions and Answers

A researcher is organizing data about customer satisfaction levels (Very Satisfied, Satisfied, Neutral, Dissatisfied, Very Dissatisfied). Which type of frequency distribution is most appropriate?

  • Grouped frequency distribution
  • Relative frequency distribution
  • Cumulative frequency distribution
  • Categorical frequency distribution (correct)

In a grouped frequency distribution of exam scores, the lower class limit of the first class is 50 and the upper class limit is 59. What is the class mark for this class?

  • 55.0
  • 55.5
  • 54.0
  • 54.5 (correct)

A dataset of employee ages ranges from 22 to 60. If you decide to use 5 classes for a frequency distribution table, what is the most appropriate class width?

  • 8 (correct)
  • 9
  • 7
  • 6

Given the data set: 12, 15, 18, 21, 24, 12, 15, 18, 21, 27. If we constructed a frequency distribution table with a class width of 5, starting at 12, what would be the frequency of the class 17-21?

<p>4 (B)</p> Signup and view all the answers

In a frequency distribution table, the cumulative frequency for the third class is 28, and the frequency of the fourth class is 12. What is the cumulative frequency for the fourth class?

<p>40 (D)</p> Signup and view all the answers

For a set of test scores, the highest score is 95 and the lowest score is 52. Using the formula $1 + 3.322 * log(n)$ to determine the number of classes, where n = 50, approximately how many classes should be used in the frequency distribution table?

<p>7 (D)</p> Signup and view all the answers

If the lower and upper class limits of a class in a frequency distribution are 60 and 69 respectively, what are the class boundaries?

<p>59.5 and 69.5 (C)</p> Signup and view all the answers

A researcher collects data on the number of books read per month by 30 individuals. After arranging the data, the range is found to be 20. If the researcher decides to use 6 classes in a frequency distribution table, what is the most appropriate class width?

<p>4 (B)</p> Signup and view all the answers

Flashcards

Frequency Distribution Table

Organizes data by sorting observations into classes and showing frequency.

Categorical Frequency Distribution

Data sorted into categories (nominal or ordinal).

Grouped Frequency Distribution

Frequency distribution used for grouped data scores.

Lower Class Limit

The smallest data value within a class (group).

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Upper Class Limit

The largest data value within a class (group).

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Class Boundaries

Separates classes without gaps; found by adjusting class limits.

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Class Mark

Midpoint of a class; (lower limit + upper limit) / 2.

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Cumulative Frequency

Sum of frequencies for a class and all previous classes.

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Study Notes

Frequency Distribution Table Construction

  • Frequency distribution tables organize observations by sorting them into classes, displaying their occurrence frequency in each class.

Types of Frequency Distribution

  • Categorical frequency distributions are for data placed in distinct categories, such as nominal or ordinal level data.
  • Grouped frequency distributions are used for grouped data scores.

Categorical Frequency Distribution Example

  • In a sample survey, letters A, B, and C represent three categories.
  • Category A appears 6 times.
  • Category B appears 9 times.
  • Category C appears 15 times.
  • The total number of observations in this example is 30 (6 + 9 + 15).

Terminology for Grouped Data

  • The lower class limit represents the smallest data value within a class.
  • The upper class limit represents the largest data value within a class.
  • Class boundaries separate classes without any gaps.
  • The class mark is the midpoint of the classes, determined by (lower limit + upper limit) / 2.
  • Class width measures the difference between two consecutive lower class limits.
  • Cumulative frequency represents the sum of frequencies for the current class and all preceding classes, in increasing order.

Steps to Construct a Frequency Distribution Table

  • Begin by arranging the scores from the lowest to the highest.
  • Compute the range by subtracting the lowest score from the highest score.
  • Determine the number of classes (k) using the formula: 1 + 3.322 * log(n), with n being the total number of observations; always round up to the nearest whole number.
  • Calculate the class width by dividing the range by k and round up to the nearest whole number.
  • Select a starting point, either the lowest score or a lower class limit, and add the class width to determine subsequent lower class limits.
  • Determine upper class limits for each class.
  • Calculate class boundaries by subtracting 0.5 from each lower class limit and adding 0.5 to each upper class limit.
  • Tally the frequency, or count, for each class.
  • Determine the class mark for each class interval using the formula: (lower limit + upper limit) / 2.
  • Compute the cumulative frequency by summing the frequencies for each class and all preceding classes.

Example: Math Quiz Scores of 40 Students

  • Arrange scores from lowest to highest.
  • The highest score is 98, and the lowest score is 40.
  • The range is calculated as 98 - 40 = 58.
  • Determine the number of classes (k): 1 + 3.322 * log(40) ≈ 6.3229, rounded up to 7.
  • The class width is calculated as 58 / 7 ≈ 8.286, rounded up to 9.
  • Assign Classes and Determine Class Limits:
    • Start with the lowest score of 40 and add the class width (9) to find the subsequent lower class limits: 40, 49, 58, 67, 76, 85, 94.
  • Determine Upper Class Limits and Class Intervals:
    • The resulting class intervals are: 40-48, 49-57, 58-66, 67-75, 76-84, 85-93, 94-102.
  • Find Class Boundaries:
    • Subtract 0.5 from lower class limits and add 0.5 to upper class limits: 39.5-48.5, 48.5-57.5, 57.5-66.5, 66.5-75.5, 75.5-84.5, 84.5-93.5, 93.5-102.5
  • Tally the frequency of each class:
    • 40-48: 9
    • 49-57: 9
    • 58-66: 13
    • 67-75: 3
    • 76-84: 4
    • 85-93: 1
    • 94-102: 1
  • Class Mark (Midpoint) Calculation:
    • Use (lower limit + upper limit)/2 to find the midpoint of each class.
    • With a class width of 9, successively add 9 to the previous midpoint: 44, 53, 62, 71, 80, 89, 98.
  • Find the cumulative frequency for each class:
    • 40-48: 9
    • 49-57: 9 + 9 = 18
    • 58-66: 18 + 13 = 31
    • 67-75: 31 + 3 = 34
    • 76-84: 34 + 4 = 38
    • 85-93: 38 + 1 = 39
    • 94-102: 39 + 1 = 40
  • The last cumulative frequency (40) matches the total number of observations, confirming the calculations.

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