Flashcards on Inequalities

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Questions and Answers

Which represents the solution set of $5(x + 5) < 85$?

x < 12

A taxi service charges a flat fee of $1.25 and $0.75 per mile. If Henri has $14.00, which of the following shows the number of miles he can afford to ride in the taxi?

  • 16 miles (correct)
  • 18 miles
  • 20 miles
  • All of the above

Which graph shows the solution set of the inequality $2.9(x + 8) < 26.1$?

  • Graph C
  • Graph B
  • Graph A
  • Graph D (correct)

For what number of hours does Grayson charge more than Ian if $h$ represents the number of hours?

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Flashcards

Solution to 5(x + 5) < 85

x is less than 12. This is the range of values for which the inequality 5(x + 5) < 85 is true.

Taxi ride affordability

Henri can afford to ride 16 miles in the taxi with $14.00, considering the flat fee and per-mile charge.

Solution to 2.9(x + 8) < 26.1

The solution set represents all values of x that satisfy the inequality. Solve for x to find the range.

What 'h' represents

The number of hours (h) is a variable placeholder. It can represent a quantity of time.

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Study Notes

Inequalities Overview

  • Solution set for the inequality 5(x + 5) < 85 simplifies to x < 12.
  • Represents a linear inequality indicating all values less than 12.

Taxi Service Fare Calculation

  • Taxi service has a base charge of $1.25 plus $0.75 for each mile.
  • Henri has a total budget of $14.00 for taxi fare.
  • To determine the maximum miles he can afford, the inequality to solve would involve the flat fee and cost per mile.

Graphing Inequalities

  • The solution set of the inequality 2.9(x + 8) < 26.1 must be represented on a graph.
  • Visual representation helps in understanding the range of values that satisfy the inequality (option D indicates the correct graph).

Comparison of Tax Preparation Costs

  • Grayson charges $35 per hour plus a $35 administration fee.
  • Ian charges $45 per hour with a $15 administration fee.
  • To find when Grayson becomes more expensive than Ian, set up the inequality involving hours (h) worked and solve for h.

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