False-Position Method (Regula Falsi Method)

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In Example 3, what is the interval used to find the approximate root of f(x) = x^2 - 2?

[1, 2]

What is the approximate root of the function f(x) = xlog(x) - 1?

1.76322284

What is the value of x1 in the Secant method when a=1, b=2, f(a)=-1, and f(b)=2?

1.33333

What is the value of x3 in the Secant method for finding the root of f(x) = x^2 - 2?

<p>1.41466898</p> Signup and view all the answers

What is the function f(x) in Example 3?

<p>x^2 - 2</p> Signup and view all the answers

What is the root of the function $f(x)=x^2-2$ found using the FalsePosition method with error $\epsilon=10^{-3}$?

<p>1.76322</p> Signup and view all the answers

What is the approximate root of the function $f(x)=x\log(x)-1$ in the interval [1,2] using the FalsePosition method with error $\epsilon=10^{-3}$?

<p>1.76322</p> Signup and view all the answers

What is the value of x3 in the FalsePosition method for finding the root of $f(x)=x\log(x)-1$?

<p>1.76316</p> Signup and view all the answers

In the FalsePosition method for $f(x)=x^2-2$, what is the interval used to find the root?

<p>[1.76316, 2]</p> Signup and view all the answers

What is the value of x7 in the Secant method for finding the root of $f(x)=x^2-2$?

<p>1.4142</p> Signup and view all the answers

What is the root of the function $f(x)=x^2-2$ found using the Secant method?

<p>1.4142</p> Signup and view all the answers

What is the value of x4 in the Secant method when finding the root of f(x) = xlog(x) - 1?

<p>1.76322284</p> Signup and view all the answers

What is the value of x2 in the Secant method for finding the root of f(x) = x^2 - 2?

<p>1.399999</p> Signup and view all the answers

What is the approximate root of the function f(x) = x^2 - 2 obtained using the Secant method?

<p>1.4142115</p> Signup and view all the answers

What is the value of x3 in the Secant method when finding the root of f(x) = x^2 - 2?

<p>1.41466898</p> Signup and view all the answers

What is the value of x1 in the Secant method when a=1, b=2, f(a)=-1, and f(b)=2 for the function f(x) = x^2 - 2?

<p>1.33333</p> Signup and view all the answers

What is the absolute difference between x1 and x2 in the Secant method when finding the root of f(x) = x^2 - 2?

<p>0.06666</p> Signup and view all the answers

In the False-Position method, if f(a) and f(b) have opposite signs, what does this indicate?

<p>There is a root between a and b</p> Signup and view all the answers

In the False-Position method, how is the next approximation x3 calculated after finding x2 and x1?

<p>x3 = x2 - (f(x2) * (x2 - x1)) / (f(x2) - f(x1))</p> Signup and view all the answers

What condition is checked in the False-Position method to determine the existence of a root between x3 and x2?

<p>f(x3) * f(x2) &gt; 0</p> Signup and view all the answers

How is the interval narrowed down in the False-Position method to find a more accurate root approximation?

<p>By iteratively calculating new approximations x4, x5, x6, ... until convergence</p> Signup and view all the answers

What is the termination condition in the False-Position method to stop the iteration process?

<p>When |x_{n+1} - x_n| ≤ ε</p> Signup and view all the answers

In the False-Position method, what does it mean when f(x_{n+1}) * f(x_n) > 0?

<p>There is no root between x_{n+1} and x_n</p> Signup and view all the answers

Study Notes

False-Position Method (Regula Falsi Method)

  • The method is used to find an approximate root of a continuous function f(x) defined on the interval [a, b].
  • The function f(x) has opposite signs at a and b (i.e., f(a) × f(b) < 0), indicating a root between x3 and x2.

Example 1: f(x) = x^2 - 2

  • The function has a root between x3 and x2, and the first iteration yields x4 = 1.3999.
  • The process is repeated until the error |x_i - x_(i-1)| < ε, where ε is the desired error tolerance.
  • The approximate root of f(x) = x^2 - 2 is x = 1.4142.

Example 2: f(x) = x log(x) - 1

  • The function has a root between x2 and x1, and the first iteration yields x3 = 1.76154.
  • The process is repeated until the error |x_i - x_(i-1)| < ε, where ε is the desired error tolerance.
  • The approximate root of f(x) = x log(x) - 1 is x = 1.76322284.

Secant Method

  • The method is used to find an approximate root of a function f(x) using the secant line approximation.
  • The iterative formula for the secant method is x_(n+1) = x_n - f(x_n) × (x_n - x_(n-1)) / (f(x_n) - f(x_(n-1))).
  • The process is repeated until the error |x_i - x_(i-1)| < ε, where ε is the desired error tolerance.

Example 3: f(x) = x^2 - 2

  • The function has a root between x1 and x2, and the first iteration yields x3 = 1.41466898.
  • The process is repeated until the error |x_i - x_(i-1)| < ε, where ε is the desired error tolerance.
  • The approximate root of f(x) = x^2 - 2 is x = 1.4142115.

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