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Questions and Answers
Determine the fully expanded form of the expression: $(x - 2y)^5$.
Determine the fully expanded form of the expression: $(x - 2y)^5$.
- $x^5 - 32y^5$
- $x^5 - 10x^4y + 40x^3y^2 - 80x^2y^3 + 80xy^4 - 32y^5$ (correct)
- $x^5 - 5x^4y + 10x^3y^2 - 10x^2y^3 + 5xy^4 - y^5$
- $x^5 + 5x^4y + 10x^3y^2 + 10x^2y^3 + 5xy^4 + y^5$
The expression $9x^2 + 30x + 25$ can be factored into $(3x + 5)(3x - 5)$.
The expression $9x^2 + 30x + 25$ can be factored into $(3x + 5)(3x - 5)$.
False (B)
Simplify the following expression: $(4x^3 - 5x + 7) - (x^3 + 5x - 2) + (3x^3 - x^2 + x)$.
Simplify the following expression: $(4x^3 - 5x + 7) - (x^3 + 5x - 2) + (3x^3 - x^2 + x)$.
6x^3 - x^2 - 9x + 9
Factor the following expression completely: $3x^3 - 12x = 3x(x + ______)(x - ______)$.
Factor the following expression completely: $3x^3 - 12x = 3x(x + ______)(x - ______)$.
Match each polynomial expression with its factored form:
Match each polynomial expression with its factored form:
Solve for $x$ in the equation: $\frac{3}{x+2} + \frac{2}{x-2} = \frac{5}{x^2-4}$.
Solve for $x$ in the equation: $\frac{3}{x+2} + \frac{2}{x-2} = \frac{5}{x^2-4}$.
The expression $(a + b)^4$ expands to $a^4 + 4a^3b + 6a^2b^2 + 4ab^3 + b^4$, according to Pascal's Triangle.
The expression $(a + b)^4$ expands to $a^4 + 4a^3b + 6a^2b^2 + 4ab^3 + b^4$, according to Pascal's Triangle.
What is the result of dividing the polynomial $x^3 - 8$ by $x - 2$?
What is the result of dividing the polynomial $x^3 - 8$ by $x - 2$?
When factoring the expression $ax + ay + bx + by$, the factored form is (a + ______)(x + y).
When factoring the expression $ax + ay + bx + by$, the factored form is (a + ______)(x + y).
Which of the following is the correct factorization of the quadratic expression $6x^2 - 7x - 3$?
Which of the following is the correct factorization of the quadratic expression $6x^2 - 7x - 3$?
Flashcards
Expanding Brackets
Expanding Brackets
Multiplying each term inside the brackets by the term outside to simplify expressions.
Distributive Property
Distributive Property
a(b + c) = ab + ac; multiplying a term by a sum inside parentheses.
Binomial Expansion
Binomial Expansion
Expanding expressions in the form of (a + b)^n.
Factoring Expressions
Factoring Expressions
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Factoring GCF
Factoring GCF
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Simplifying Polynomials
Simplifying Polynomials
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Solving Equations
Solving Equations
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Zero Product Property
Zero Product Property
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Extraneous Solutions
Extraneous Solutions
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Like Terms
Like Terms
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Study Notes
- Expanding brackets involves multiplying each term inside the bracket by the term outside
- Simplifies expressions and helps in solving equations
Distributive Property
- A fundamental concept in algebra
- a(b + c) = ab + ac, where a, b, and c are numbers or variables
- Expanding brackets is an application of the distributive property
- 3(x + 2) = 3x + 6
- -2(y - 5) = -2y + 10
- The distributive property can be extended to more complex expressions
- a(b + c + d) = ab + ac + ad
- When expanding brackets, pay attention to signs
- Multiplying by a negative number changes the sign of each term inside the bracket
- -a(b - c) = -ab + ac
Binomial Expansion
- Involves expanding expressions of the form (a + b)^n
- For small values of n, direct multiplication can be used.
- (a + b)^2 = (a + b)(a + b) = a^2 + 2ab + b^2
- (a + b)^3 = (a + b)(a + b)(a + b) = a^3 + 3a^2b + 3ab^2 + b^3
- Pascal's triangle provides coefficients for binomial expansion
- The binomial theorem gives a general formula for expanding (a + b)^n
- (a + b)^n = Σ [n! / (k!(n-k)!)] * a^(n-k) * b^k, where k ranges from 0 to n
- (x + y)^4 = x^4 + 4x^3y + 6x^2y^2 + 4xy^3 + y^4
- The coefficients in the expansion are binomial coefficients
- The binomial coefficients can be calculated using combinations
- The coefficient of the term a^(n-k)b^k is often written as "n choose k" or C(n, k)
Factoring Expressions
- Is the reverse process of expanding brackets
- Involves finding the factors that multiply together to give the original expression
- Simplest type of factoring is finding the greatest common factor (GCF)
- 6x + 9 = 3(2x + 3), where 3 is the GCF
- Factoring quadratic expressions involves finding two binomials that multiply to give the quadratic
- x^2 + 5x + 6 = (x + 2)(x + 3)
- Difference of squares: a^2 - b^2 = (a + b)(a - b)
- Perfect square trinomial: a^2 + 2ab + b^2 = (a + b)^2
- Factoring by grouping is used for expressions with four or more terms
- ax + ay + bx + by = a(x + y) + b(x + y) = (a + b)(x + y)
- Factoring is useful for simplifying expressions and solving equations
Simplifying Polynomials
- Involves combining like terms
- Like terms have the same variable raised to the same power
- 3x^2 + 2x - x^2 + 5x = 2x^2 + 7x
- Polynomials can be simplified by adding, subtracting, multiplying, or dividing them
- Adding polynomials involves combining like terms
- Subtracting polynomials involves distributing the negative sign and then combining like terms
- Multiplying polynomials involves using the distributive property
- Dividing polynomials can be done using long division or synthetic division
- Simplifying polynomials makes it easier to work with them
- Simplified polynomials are easier to evaluate and graph
Solving Equations
- Involves finding the value(s) of the variable that make the equation true
- The goal is to isolate the variable on one side of the equation
- Expanding brackets can be a necessary step in solving equations
- 2(x + 3) = 10 becomes 2x + 6 = 10, then 2x = 4, and finally x = 2
- Factoring can also be used to solve equations, especially quadratic equations
- x^2 + 5x + 6 = 0 becomes (x + 2)(x + 3) = 0, so x = -2 or x = -3
- The zero product property states that if ab = 0, then a = 0 or b = 0
- This property is used when solving equations by factoring
- Equations can have one solution, no solutions, or infinitely many solutions
- Linear equations have one solution
- Quadratic equations can have two, one, or no real solutions
- Equations with no solutions are called contradictions
- Equations with infinitely many solutions are called identities
- When solving equations, it is important to check the solutions
- Checking the solutions ensures that they satisfy the original equation
- Extraneous solutions can arise when solving certain types of equations
- Extraneous solutions are solutions that do not satisfy the original equation
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