Expanding Brackets and Distributive Property

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Questions and Answers

Determine the fully expanded form of the expression: $(x - 2y)^5$.

  • $x^5 - 32y^5$
  • $x^5 - 10x^4y + 40x^3y^2 - 80x^2y^3 + 80xy^4 - 32y^5$ (correct)
  • $x^5 - 5x^4y + 10x^3y^2 - 10x^2y^3 + 5xy^4 - y^5$
  • $x^5 + 5x^4y + 10x^3y^2 + 10x^2y^3 + 5xy^4 + y^5$

The expression $9x^2 + 30x + 25$ can be factored into $(3x + 5)(3x - 5)$.

False (B)

Simplify the following expression: $(4x^3 - 5x + 7) - (x^3 + 5x - 2) + (3x^3 - x^2 + x)$.

6x^3 - x^2 - 9x + 9

Factor the following expression completely: $3x^3 - 12x = 3x(x + ______)(x - ______)$.

<p>2</p> Signup and view all the answers

Match each polynomial expression with its factored form:

<p>x^2 - 4x + 4 = (x - 2)^2 x^2 - 4 = (x + 2)(x - 2) x^3 - 8 = (x - 2)(x^2 + 2x + 4) x^3 + 8 = (x + 2)(x^2 - 2x + 4)</p> Signup and view all the answers

Solve for $x$ in the equation: $\frac{3}{x+2} + \frac{2}{x-2} = \frac{5}{x^2-4}$.

<p>No Solution (C)</p> Signup and view all the answers

The expression $(a + b)^4$ expands to $a^4 + 4a^3b + 6a^2b^2 + 4ab^3 + b^4$, according to Pascal's Triangle.

<p>True (A)</p> Signup and view all the answers

What is the result of dividing the polynomial $x^3 - 8$ by $x - 2$?

<p>x^2 + 2x + 4</p> Signup and view all the answers

When factoring the expression $ax + ay + bx + by$, the factored form is (a + ______)(x + y).

<p>b</p> Signup and view all the answers

Which of the following is the correct factorization of the quadratic expression $6x^2 - 7x - 3$?

<p>$(2x - 3)(3x + 1)$ (D)</p> Signup and view all the answers

Flashcards

Expanding Brackets

Multiplying each term inside the brackets by the term outside to simplify expressions.

Distributive Property

a(b + c) = ab + ac; multiplying a term by a sum inside parentheses.

Binomial Expansion

Expanding expressions in the form of (a + b)^n.

Factoring Expressions

Finding the factors that multiply together to give the original expression.

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Factoring GCF

Simplifying by finding the greatest common factor (GCF).

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Simplifying Polynomials

Combining like terms (same variable and power) to simplify.

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Solving Equations

Finding the value(s) of the variable that make the equation true.

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Zero Product Property

If ab = 0, then either a = 0 or b = 0 (or both).

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Extraneous Solutions

Solutions that appear correct but do not satisfy the original equation.

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Like Terms

Terms with same variable raised to the same power.

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Study Notes

  • Expanding brackets involves multiplying each term inside the bracket by the term outside
  • Simplifies expressions and helps in solving equations

Distributive Property

  • A fundamental concept in algebra
  • a(b + c) = ab + ac, where a, b, and c are numbers or variables
  • Expanding brackets is an application of the distributive property
  • 3(x + 2) = 3x + 6
  • -2(y - 5) = -2y + 10
  • The distributive property can be extended to more complex expressions
  • a(b + c + d) = ab + ac + ad
  • When expanding brackets, pay attention to signs
  • Multiplying by a negative number changes the sign of each term inside the bracket
  • -a(b - c) = -ab + ac

Binomial Expansion

  • Involves expanding expressions of the form (a + b)^n
  • For small values of n, direct multiplication can be used.
  • (a + b)^2 = (a + b)(a + b) = a^2 + 2ab + b^2
  • (a + b)^3 = (a + b)(a + b)(a + b) = a^3 + 3a^2b + 3ab^2 + b^3
  • Pascal's triangle provides coefficients for binomial expansion
  • The binomial theorem gives a general formula for expanding (a + b)^n
  • (a + b)^n = Σ [n! / (k!(n-k)!)] * a^(n-k) * b^k, where k ranges from 0 to n
  • (x + y)^4 = x^4 + 4x^3y + 6x^2y^2 + 4xy^3 + y^4
  • The coefficients in the expansion are binomial coefficients
  • The binomial coefficients can be calculated using combinations
  • The coefficient of the term a^(n-k)b^k is often written as "n choose k" or C(n, k)

Factoring Expressions

  • Is the reverse process of expanding brackets
  • Involves finding the factors that multiply together to give the original expression
  • Simplest type of factoring is finding the greatest common factor (GCF)
  • 6x + 9 = 3(2x + 3), where 3 is the GCF
  • Factoring quadratic expressions involves finding two binomials that multiply to give the quadratic
  • x^2 + 5x + 6 = (x + 2)(x + 3)
  • Difference of squares: a^2 - b^2 = (a + b)(a - b)
  • Perfect square trinomial: a^2 + 2ab + b^2 = (a + b)^2
  • Factoring by grouping is used for expressions with four or more terms
  • ax + ay + bx + by = a(x + y) + b(x + y) = (a + b)(x + y)
  • Factoring is useful for simplifying expressions and solving equations

Simplifying Polynomials

  • Involves combining like terms
  • Like terms have the same variable raised to the same power
  • 3x^2 + 2x - x^2 + 5x = 2x^2 + 7x
  • Polynomials can be simplified by adding, subtracting, multiplying, or dividing them
  • Adding polynomials involves combining like terms
  • Subtracting polynomials involves distributing the negative sign and then combining like terms
  • Multiplying polynomials involves using the distributive property
  • Dividing polynomials can be done using long division or synthetic division
  • Simplifying polynomials makes it easier to work with them
  • Simplified polynomials are easier to evaluate and graph

Solving Equations

  • Involves finding the value(s) of the variable that make the equation true
  • The goal is to isolate the variable on one side of the equation
  • Expanding brackets can be a necessary step in solving equations
  • 2(x + 3) = 10 becomes 2x + 6 = 10, then 2x = 4, and finally x = 2
  • Factoring can also be used to solve equations, especially quadratic equations
  • x^2 + 5x + 6 = 0 becomes (x + 2)(x + 3) = 0, so x = -2 or x = -3
  • The zero product property states that if ab = 0, then a = 0 or b = 0
  • This property is used when solving equations by factoring
  • Equations can have one solution, no solutions, or infinitely many solutions
  • Linear equations have one solution
  • Quadratic equations can have two, one, or no real solutions
  • Equations with no solutions are called contradictions
  • Equations with infinitely many solutions are called identities
  • When solving equations, it is important to check the solutions
  • Checking the solutions ensures that they satisfy the original equation
  • Extraneous solutions can arise when solving certain types of equations
  • Extraneous solutions are solutions that do not satisfy the original equation

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