Enzyme Kinetics Quiz

It shows that the enzyme has a higher turnover number.

It suggests the enzyme is less effective with substrate.

It indicates a lower affinity for the substrate. (correct)

It indicates a higher catalytic efficiency.

$K_m$ increases while $V_{max}$ remains unchanged. (correct)

$K_m$ remains unchanged and $V_{max}$ decreases.

$K_m$ increases and $V_{max}$ increases.

$K_m$ decreases and $V_{max}$ decreases.

The enzyme's activity decreases as substrate concentration decreases.

The concentration of the substrate remains constant over time.

The formation of products is greater than substrate consumption.

The rate of formation of the enzyme-substrate complex is equal to the rate of its breakdown. (correct)

<p>$k_{cat}$ is a rate constant for turnover while catalytic efficiency considers both $k_{cat}$ and $K_m$.</p> Signup and view all the answers

<p>Both $V_{max}$ and $K_m$ decrease.</p> Signup and view all the answers