Engineering Physics-I Quiz

$V = \frac{kQ}{r}$ (correct)

$V = \frac{Q}{kr}$

$V = kQr$

$V = \frac{Q}{r^2}$

Maximum when the dipole is aligned with the field

Depends on the orientation of the dipole

Zero (correct)

Maximum when the dipole is perpendicular to the field

$\tau = \vec{p} \cdot \vec{E}$

$\tau = \vec{p} + \vec{E}$

$\tau = \vec{p} \times \vec{E}$ (correct)

$\tau = \vec{p} \div \vec{E}$

<p>Work done by the electric field</p> Signup and view all the answers

<p>Biot-Savart law</p> Signup and view all the answers