Engineering Mathematics-I Question Bank Unit-1

Questions and Answers

a(x, y, z) = (0, 0, 0) (correct)

a(x, y, z) = (ax, y, az) (correct)

a(x, y, z) = (ax, 0, az) (correct)

a(x, y, z) = (2ax, 2ay, 2az) (correct)

Yes

No (correct)

Yes (correct)

No Signup and view all the answers

(0, -1) Signup and view all the answers

U = The set of all polynomials in P3 with constant term 0 Signup and view all the answers

U = {A | A ∈ M22 , A2 = A} Signup and view all the answers

U = {f | f(0) = 0} Signup and view all the answers

1(x + 1) + 1(x² + x) + 1(x² + 2) Signup and view all the answers

No Signup and view all the answers

Yes Signup and view all the answers

Study Notes

A vector space must satisfy properties under addition and scalar multiplication.
Scalar multiplication examples tested:
- (a(x, y, z) = (ax, y, az)): Non-vector space.
- (a(x, y, z) = (ax, 0, az)): Non-vector space.
- (a(x, y, z) = (0, 0, 0)): Not a valid scalar multiplication.
- (a(x, y, z) = (2ax, 2ay, 2az)): Valid vector space.

Nonnegative real numbers with standard operations fail as a vector space due to lack of negatives.
Polynomials of degree ≥ 3 lack a zero vector, making it non-vector space.
Polynomials of degree ≤ 3 form a vector space due to closure under addition and scalar multiplication.
The set {1, x, x², ...} is not a vector space; not closed under addition.
Certain matrix forms and conditions (like (2 \times 2) matrices) also tested for being vector spaces based on their properties and operations.

Positive real numbers as a vector space with multiplication for addition must prove closure and properties.
Ordered pairs (x, y) with modified addition and scalar multiplication form a vector space defined by unique operations.

Sets defined by specific conditions (e.g., (f(2) = 1)) do not form subspaces due to lack of closure.
Structuring through (g(x)) in relation to polynomial degrees checks subspaces of (P3).
Zero constant terms in polynomials define a valid subspace.

Matrices with certain properties (e.g., symmetry, specific determinants) were tested for forming valid subspaces.
Conditions like (A^T = A) show valid subspaces; others based on non-invertibility or specific matrix equations must validate.

Functions evaluated on conditions like (f(0) = 0) form a vector space (zero vector condition).
Maintaining conditions in integration or equality across intervals can also form valid subspaces.

Expressing polynomials as combinations of given forms (e.g. (x + 1), (x^2 + x)) allows for analysis of linear dependencies.
Specific polynomials demonstrate how they can be represented as linear combinations.

Demonstrating spanning characteristics through basis sets, like vectors in (R^3) or polynomials in (P2), confirms spanned nature.
Specific examples illustrate how defined sets can reach every vector in a space.

Testing whether elements belong to span confirms closeness within spaces formed by given vectors or matrices.
Conditions and representations of matrices and concepts play a key role in understanding span properties.