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Questions and Answers
What is the empirical formula of the organic compound C12H160g?
What is the empirical formula of the organic compound C12H160g?
- C12H16O6
- C6H8O4
- C3H4O2
- CH2O (correct)
What does the empirical formula C12H160g represent?
What does the empirical formula C12H160g represent?
- Glucose (correct)
- Methanol
- Ethanol
- Sucrose
How many carbon atoms are present in the empirical formula C6H8O4?
How many carbon atoms are present in the empirical formula C6H8O4?
- 8
- 6 (correct)
- 12
- 4
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Study Notes
Empirical Formula
- The empirical formula of the organic compound is C12H160g.
- The empirical formula C12H160g represents a molecule composed of 12 carbon atoms, 160 hydrogen atoms, and an unknown number of oxygen atoms (since it's not specified).
Empirical Formula Analysis
- To find the empirical formula of a compound, the molecular formula is divided by the greatest common divisor (GCD) of the subscripts.
- In the empirical formula C6H8O4, there are 6 carbon atoms, 8 hydrogen atoms, and 4 oxygen atoms.
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