Electric Field and Forces Quiz

$F_{21} = \frac{1}{4\pi\epsilon_0}\frac{q_2}{r_{21}}$

$F_{21} = \frac{1}{4\pi\epsilon_0}\frac{q_1}{r_{12}}$

$F_{21} = \frac{1}{4\pi\epsilon_0}\frac{q_1q_2}{r_{12}^2}$

$F_{21} = \frac{1}{4\pi\epsilon_0}\frac{q_1q_2}{r_{21}^2}$ (correct)

The force is attractive.

The force depends on the magnitude of the charges.

The force depends on the distance between the charges.

The force is repulsive. (correct)

$F_1 = F_{1,2} + F_{1,3} + F_{1,4} + \ldots + F_{1,N}$ (correct)

$F_1 = F_{1,2} \times F_{1,3} \times F_{1,4} \times \ldots \times F_{1,N}$

$F_1 = F_{1,2} - F_{1,3} + F_{1,4} - \ldots + F_{1,N}$

$F_1 = F_{1,2} \div F_{1,3} \div F_{1,4} \div \ldots \div F_{1,N}$

<p>The total force experienced by a charge is the vector sum of the forces on it exerted by other charges.</p> Signup and view all the answers

<p>The electric field is defined as the ratio of the force experienced by a charge to the magnitude of the charge.</p> Signup and view all the answers