Electric Dipoles: Potential Energy

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Questions and Answers

How does the presence of a dielectric material between the plates of a capacitor affect its capacitance, and why?

The capacitance increases because the dielectric reduces the electric field strength, allowing more charge to be stored at a given voltage.

Explain how the common potential is achieved when two charged capacitors with different potentials are connected by a conducting wire.

Charge flows from the capacitor at higher potential to the one at lower potential until both reach the same potential, known as the common potential.

What is dielectric polarization, and how does it occur in a dielectric material when an electric field is applied?

Dielectric polarization is the alignment of molecular dipoles in a dielectric material when an electric field is applied, resulting in a net dipole moment.

A parallel plate capacitor has an area A and separation d. If both A and d are doubled, how does the capacitance change?

<p>The capacitance remains the same because capacitance is directly proportional to <em>A</em> and inversely proportional to _d$. Doubling both factors cancels out.</p> Signup and view all the answers

Describe the relationship between the work done in rotating an electric dipole in an external electric field and the potential energy of the dipole.

<p>The work done in rotating the dipole is stored as the potential energy of the dipole placed in the external field.</p> Signup and view all the answers

How does the dielectric strength of a material relate to its breaking potential, and what happens when the electric field exceeds the dielectric strength?

<p>Breaking potential is the maximum potential a dielectric can withstand without breaking down. Dielectric strength is the maximum electric field. Exceeding either causes the material to become conductive.</p> Signup and view all the answers

Explain how the potential energy of an electric dipole changes as it rotates from being aligned with an electric field to being perpendicular to it.

<p>When aligned, the potential energy is minimal ($U = -pE$); as it rotates to perpendicular, the potential energy increases to zero ($U = 0$).</p> Signup and view all the answers

Why is silver considered a better conductor of electric charge compared to most other metals?

<p>Silver has a higher density of mobile charge carriers and lower resistance, allowing electric charge to flow more easily.</p> Signup and view all the answers

How does inserting a dielectric slab of thickness t (where t < d) between capacitor plates affect the overall capacitance, given the plate separation is d?

<p>The capacitance increases, but not as much as if the entire space were filled. The formula is $C = \frac{\epsilon_0 A}{d - t + \frac{t}{K}}$</p> Signup and view all the answers

If the potential difference between two parallel metallic plates is doubled while keeping the distance between them constant, how does the electric field intensity change?

<p>The electric field intensity doubles, as $E = \frac{V}{d}$, where <em>E</em> is the electric field intensity, <em>V</em> is the potential difference, and <em>d</em> is the distance.</p> Signup and view all the answers

Flashcards

Conductors

Materials allowing easy electric charge flow; metals like silver are great examples.

Insulators

Materials hindering electric charge flow; examples include glass and rubber.

Polarisation

Electric field creating a net dipole moment in a dielectric.

Capacitor

System storing charge without shape change, with conductors separated by insulation.

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Capacity

The ability of a capacitor to store charge and energy.

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Dielectric Strength

Maximum electric field a dielectric withstands without breaking down.

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Breaking Potential

The maximum potential applied on a dielectric without breaking.

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Parallel Plate Capacitor

Capacitor with two metal plates of area A, separated by distance d.

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Potential energy of a dipole in an external field

Potential energy of a dipole in an external field is equal to the work done in rotating the dipole with respect to the electric field.

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Study Notes

  • Electric field intensity between two parallel metallic plates with electric potentials ( V_1 ) and ( V_2 ) separated by distance ( d ) is ( E = \frac{V_2 - V_1}{d} ) in V/m.
  • Electric potential energy of two electric dipoles: ( U = -\frac{1}{4\pi\epsilon_0} \frac{2p_1p_2}{r^3} )

Potential Energy of a Dipole

  • Potential energy of a dipole in an external field is equal to the work done in rotating the dipole from angle ( \theta_0 ) to ( \theta_1 ) with respect to the electric field ( E ).
  • The work done by the external torque is given by ( W = \int_{\theta_0}^{\theta_1} \tau d\theta = \int_{\theta_0}^{\theta_1} pE \sin\theta d\theta ).
  • ( W = pE [-\cos\theta]_{\theta_0}^{\theta_1} = pE (\cos\theta_0 - \cos\theta_1) ).
  • The work done is stored as the potential energy of the system.
  • Potential energy of the dipole placed in an external field ( E ) is ( U(\theta) = pE (\cos\theta_0 - \cos\theta_1) )

Particular Cases

  • When the dipole is initially aligned along the electric field, i.e., ( \theta_0 = 0^\circ ), and is set at angle ( \theta ) with ( E ):
    • ( W = -pE (\cos\theta - \cos 0^\circ) = -pE (\cos\theta - 1) )
    • The work is stored in the dipole as potential energy.
  • When the dipole is initially perpendicular to ( E ), i.e., ( \theta_0 = 90^\circ ), and set at angle ( \theta ) with ( E ):
    • ( W = -pE (\cos\theta - \cos 90^\circ) = -pE \cos\theta )
    • Potential energy of dipole is ( U = W = -pE \cos\theta ) or ( U = -p \cdot E ).
  • Potential energy of an electric dipole is a scalar quantity, measured in joules.

Conductors and Insulators

  • Conductors allow electric charge to flow easily (e.g., metals, silver).
  • Insulators inhibit the flow of electric charge (e.g., glass, rubber, wood); also called dielectrics.
  • Applying an electric field to dielectrics induces charges on the surface.
  • Dielectrics transmit electric effects without conducting.

Polarization

  • In a dielectric, an electric field produces a net dipole moment, known as dielectric polarization.

Capacitor

  • A capacitor stores electric charge without changing its shape
  • A capacitor consists of two conductors separated by an insulating medium.

Capacity

  • Capacity is the measure of a capacitor's ability to store charge and electrical energy.
  • Capacitance is the ratio of charge given to the capacitor to the increase in its potential: ( q = CV ), where ( C ) is capacitance.
  • Capacitance depends on shape, size, separation between conductors, surrounding medium, and presence of other conductors.
  • SI unit of capacitance is the farad (F); its dimensional formula is ( [M^{-1}L^{-2}T^4A^2] ).
  • 1 farad = 1 coulomb / 1 volt
  • Farad is a large unit; microfarads (( \mu )F) and picofarads (pF) are common, with ( 1\mu F = 10^{-6} F ) and ( 1pF = 10^{-12} F ).
  • Capacitance of an isolated spherical capacitor: ( C = 4\pi\epsilon_0 a ), where ( a ) is the radius of the sphere.

Common Potential

  • When two capacitors with different potentials are connected by a wire, charge flows from higher to lower potential until they reach a common potential.
  • Common potential is the total charge divided by the total capacitance: ( V = \frac{C_1V_1 + C_2V_2}{C_1 + C_2} ).
  • Loss of energy during charge redistribution: ( \Delta U = \frac{C_1C_2(V_1 - V_2)^2}{2(C_1 + C_2)} )

Dielectric Strength and Breaking Potential

  • Dielectric strength is the maximum electric field a dielectric can withstand without breakdown; for air, it is about ( 3 \times 10^6 ) V/m.
  • Breaking potential is the maximum potential applied on a dielectric without it breaking down.

Parallel Plate Capacitor

  • It comprises two metal plates of area A separated by distance d, filled with air or a dielectric medium.
  • Capacitance of an air-filled parallel plate capacitor: ( C_0 = \frac{\epsilon_0 A}{d} ).
  • With a dielectric of constant ( K ) fully filling the space: ( C = \frac{K\epsilon_0 A}{d} = KC_0 ).
  • With a dielectric slab of thickness ( t ) inserted: ( C = \frac{\epsilon_0 A}{d - t + \frac{t}{K}} )

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